Apply foreach to multiple arrays? - php

Question

I've been playing around with this one for a few days, I'm not a professional coder but I'm trying to put a nice basic system in place to manage checkin/out at a local volunteer rescue organization.
Basically I'm trying to get all members member with the ISLOGGEDIN value set as 1
$loggedin = mysql_query("SELECT * FROM members WHERE ISLOGGEDIN=1");
$loggedinarray=mysql_fetch_array($loggedin);
And present their information (name, etc) into a table:
foreach($loggedinarray as $key=>$value) {
echo "
<tr>
<td>".$value[firstname]." ".$value[lastname]."</td>
<td>".$value[timeloggedin]."</td>
</tr>
";
}
However the results I'm getting are quite random and not what I'm looking for, at all!
var_dump($loggedinarray) output:
array(12) { [0]=> string(5) "5395" ["SES_ID"]=> string(5) "5395" [1]=> string(7) "Anthony" ["FIRST"]=> string(7) "Anthony" [2]=> string(8) "LastName" ["LAST"]=> string(8) "Willison" [3]=> string(1) "1" ["ISLOGGEDIN"]=> string(1) "1" [4]=> string(1) "0" ["TRAINER"]=> string(1) "0" [5]=> string(1) "1" ["OFFICER"]=> string(1) "1" }
Any help would be greatly appreciated!

Answer 1

You have to use while; it was random, because it fetched only one row from table.
$loggedin = mysql_query("SELECT * FROM members WHERE ISLOGGEDIN = 1");
if (mysql_num_rows($loggedin) > 0) {
echo "<table>";
while ($row = mysql_fetch_array($loggedin)) {
echo "
<tr>
<td>".$row['FIRST']." ".$row['LAST']."</td>
<td>".$row['timeloggedin']."</td>
</tr>
";
}
echo "</table>";
}
This code will output every row from table, where ISLOGGEDIN = 1.
PS: about data $row['timeloggedin'], you dont have it in your query (as seen in var_dump), so it will be an empty string.