Page system where category = 1 - php

Question

Im trying to make a pagination to my article page.
the problem is i want it to count the articles WHERE category = 1
ive worked with the script for sometime, but it still just shows a blank page no errors.
any suggestions why it wont work?
<?php
error_reporting(E_ALL); ini_set("display_errors", 1);
$db = mysql_connect("localhost", "root", "");
mysql_select_db("dirts_mysql", $db);
echo "<h1>articles</h1>";
$pr_page = 2;
$number = mysql_result(mysql_query("SELECT COUNT(*) FROM article WHERE category = 1"), 0) or die(mysql_error());
$show_from = (isset($_GET["visfra"]) && is_numeric($_GET["visfra"]) && $_GET["visfra"] < $number) ? $_GET["visfra"] : 0;
$query = mysql_query("SELECT * FROM article ORDER BY id DESC limit $show_from, $pr_page") or die(mysql_error());
while ($row = mysql_fetch_array($query)) {
?>
<link rel="stylesheet" type="text/css" href="style.css">
<div id="news">
<h2><u><? echo $row['name']; ?></u></h2>
<p>
<?php echo nl2br($row['description']); ?>...
</p>
<br/><br/>
[...]
</div>
<br>
<?php
}
if ($show_from > 0) {
$back = $show_from - $pr_page;
echo "<a href='?showfrom=$back'>Forrige</a> ";
}
$page = 1;
for ($start = 0; $number > $start; $start = $start + $pr_page) {
if ($show_from != $page * $pr_page - $pr_page) {
echo "<a href='?showfrom=$start'>$page</a> ";
} else {
echo $page . " ";
}
$page++;
}
if ($show_from < $number - $pr_page) {
$next = $show_from + $pr_page;
echo " <a href='?&showfrom=$next'>Næste</a>";
}
?>

Answer 1

add the following on the top of your code:
error_reporting(E_ALL);
ini_set("display_errors", 1);
On the otherside, I will suggest you to start using function to structure your code. :)