Replace URL occurrence in string using PHP - php

Question

I want to replace the url in the following text with [FILENAME], where FILENAME is the name of the file.
check out this car http://somesite/ford.png
This will then appear like:
check out this car [ford]
This is my code so far:
$text = $_POST['text']; //get submitted post
$link = strstr($text, 'http://'); //look for an http
$filename = pathinfo ($link, PATHINFO_FILENAME); //get filename from $link
$result = str_replace($text,$link,"[".$filename."]"); // search on $text, find $link, replace it with $filename
echo $result;
At the moment, I am only getting back [ford], where is all the other text?

Answer 1

Using str_replace
You have your parameters in the wrong order, you need to change them like so:
$result = str_replace($link,"[".$filename."]",$text);
See here for documentation.
Alternative (Regular Expression)
You could use a regular expression. This method is marginly slower, but it will use less code:
$result = preg_replace('/http(s?):\/\/[a-z]\/(.+)\.png/i', '[$1]', $text);
You can then alter your regular expression further by allowing other kinds of images like so:
$result = preg_replace('/http(s?):\/\/[a-z]\/(.+)\.(png|gif|jpg|jpeg)/i', '[$1]', $text);
To Conclude
You can use either of the above methods, but in my opinion I would use the first. Regular Expressions can be brilliant, but they can also be unreliable if you define them incorrectly, or forget about a potential factor in the pattern.

Answer 2

$result = preg_replace ('/http:\/\/somesite\/(.+)\.png/', '[$1]', $text);

Answer 3

I'd use a # as regex delimiter.
$result = preg_replace('#http://somesite/(.+)\.png#', '[$1]', $text);

Answer 4

You can use this:
<?php
$text = 'check out this car http://somesite/ford.png'; //get submitted post
$link = strstr($text, 'http://'); //look for an http
$filename = pathinfo ($link, PATHINFO_FILENAME); //get filename from $link
$result = ereg_replace("http://([-]*[.]?[a-zA-Z0-9_/-?&%])*", "[$filename]", $text); // search on $text, find $link, replace it with $filename
echo $result;
?>
Output:
check out this car [ford]
Or if you wanna link to use forum
<?php
$text = 'check out this car http://somesite/ford.png'; //get submitted post
$link = strstr($text, 'http://'); //look for an http
$filename = pathinfo ($link, PATHINFO_FILENAME); //get filename from $link
$result = ereg_replace("http://([-]*[.]?[a-zA-Z0-9_/-?&%])*", "\\0", $text); // search on $text, find $link, replace it with $filename
echo $result;
?>
Or you want to up "ford" as link you can use this:
<?php
$text = 'check out this car http://somesite/ford.png'; //get submitted post
$link = strstr($text, 'http://'); //look for an http
$filename = pathinfo ($link, PATHINFO_FILENAME); //get filename from $link
$result = ereg_replace("http://([-]*[.]?[a-zA-Z0-9_/-?&%])*", "$filename", $text); // search on $text, find $link, replace it with $filename
echo $result;
?>