show path of image on update form php - php

Question

When populating the fields of an update form how can I show the path to the current image like this
so that if the user doesn't want to change the image the same image is used.
This is what the browser displays:
<input type="file" value="uploads/chaps_B.jpg" name="image_edit"></input>
I have a feeling my photopath in not in scope but unsure how to go about fixing it. All variables populate the form and it saves to the db fine just can't figure out the image path.
if(isset($_POST['update_submit']))
{
$get_products = $db->prepare("select `photopath` from `item` where
`item_id` = '$get_item' LIMIT 1");
$get_products->execute();
$path= $get_products->fetchColumn(6);
if($_FILES['image_edit']['tmp_name'] != "")
{
$edit_name = $_POST['item_name'];
$edit_description =$_POST['item_description'];
$form_id = $_POST['edit_form_id'];
$file_dir = "uploads/";
$image = $file_dir. $_FILES['image_edit']['name'];
move_uploaded_file($_FILES['image_edit']['tmp_name'], $image);
$edit_sql =$db->prepare("UPDATE item SET item_name = '$edit_name',
item_description = '$edit_description',
photopath ='$image' WHERE item_id = '$form_id'");
$edit_sql->execute();
header("Location: manage_items.php");
exit();
}
else
{
$edit_name = $_POST['item_name'];
$edit_description =$_POST['item_description'];
$form_id = $_POST['edit_form_id'];
$edit_sql =$db->prepare("UPDATE item SET item_name = '$edit_name',
item_description = '$edit_description'
WHERE item_id = '$form_id'");
$edit_sql->execute();
header("Location: manage_items.php");
exit();
}
UPDATE FORM
<form action="item_edit.php" method="post" enctype="multipart/form-data">
<input type = "text" name="item_name" value="<?php echo $item_name ?> "/>
<textarea name="item_description"><?php echo $item_description ?></textarea>
<p> <img src="<?php echo $image; ?>" width="75" height="75" /></p>
<input type="file" name="image_edit" />
<input name="edit_form_id" type="hidden" value="<?php echo $get_item ?>">
<p><input type="submit" name="update_submit" value="Update"/></p>
<p><input type="submit" name="cancel_edit" value="Cancel"/></p>
</form>
DB STRUCTURE

Answer 1

When retrieving a single row, you do not have to loop through as you asked in the comment in your code.
As for the database, what exactly are you storing what does your table structure look like?
You could easily save the name of the image in a field and retrieve that and not even get the fullpath ( since there could be more images there )
EDIT 1
This is one way to solving the empty string insertion issue yes, however the query will have to be different so you'll have to write one which does insert the image, and one that excludes it
EDIT 2
After you retrieve the image path all you'd have to do now is split the string by using PHP's explode, e.g. $aPath = explode('/', $yourDBfield);, this would give you an array with items split on a /, since the file will always be at the end, simply do this: $image = $aPath[(count($aPath)-1)];, this should give you the image.
EDIT 3
As requested by the OP,
The main query should include the image update, e.g. when the value set is not empty.
$edit_sql =$db->prepare("UPDATE item SET item_name = '$edit_name',
item_description = '$edit_description',
photopath ='$image' WHERE item_id = '$form_id'");
The other query should exclude photopath = '$image' e.g.
$edit_sql =$db->prepare("UPDATE item SET item_name = '$edit_name',
item_description = '$edit_description',
WHERE item_id = '$form_id'");
You could also, as mentioned in the comments, add the default path, e.g. $image (not split) to the value of the field when the page is requested, this way you'd only have to write 1 query, and the image would remain the same if untouched.