dropdown list is empty in <select> - php

Question

I cannot seem to find my error, my dropdown list is empty but there are values in the array when i do a print_r($data).
My code:
<?php $sql = "SELECT p.firstname, p.lastname from person p where p.personid >= :personid";
$array = array('personid' => 75101);
$sth = $dbh->prepare($sql);
if($sth->execute($array)) {
$data = $sth->fetchAll();
} ?>
<tr><td style="width:120px;">Contact Person</td>
<td>
<select>
<?php foreach ($data as $key => $value) { ?>
<option value=" <?php $key; ?>" > <?php $value ?> </option>
<?php } ?>
</select>
</td>
can some one help please?
thanks

Answer 1

try this...
<?php $sql = "SELECT p.firstname, p.lastname from person p where p.personid >= :personid";
$array = array('personid' => 75101);
$sth = $dbh->prepare($sql);
if($sth->execute($array)) {
$data = $sth->fetchAll();
} ?>
<tr><td style="width:120px;">Contact Person</td>
<td>
<select>
<?php foreach ($data as $key => $value) { ?>
<option value=" <?php echo $key; ?>" > <?php echo $value; ?> </option>
<?php } ?>
</select>
</td>

Answer 2

Try this
<?php foreach ($data as $key => $value) { ?>
<option value=" <?php echo $key; ?>" > <?php echo $value; ?> </option>
<?php } ?>

Answer 3

You cant print a variable without using echo , you forgot to print the $key and $value ,
change
<option value=" <?php $key; ?>" > <?php $value ?> </option>
with
<option value=" <?php echo $key; ?>" > <?php echo $value; ?> </option>

Answer 4

You are not print variables. Only use in your code.
If You need short tags, try this code:
<?php foreach ($data as $key => $value) { ?>
<option value="<?=$key;?>"><?=$value["firstname"]." ".$value["lastname"];?></option>
<?php } ?>
But if on your server short tags is disabled then try code from previous replay, only $value variables replace with $value["firstname"].