Hello I am using the following code to get result from the database , in the second dump te results is okay, in the first one there is a problem, because If file is uploaded with space in the name the result is cut after the space:
<?php echo "".$row['pdf']."" ?>
first $row is = 124564
second $row is = 124564 SPRASHORT.pdf
how to fix the first result to be like the second one ?
If you have a space you should encode before linking
<?php echo '' . $row['pdf'] . '' ?>
href should be inside quotes
<?php echo "<a href='pdf/".$row['pdf']."'>".$row['pdf']."</a>" ?>
OR
<?php echo "".$row['pdf']."" ?>
Related
I have a variable given to me by my cms
I want to add one space before that but have tried many things lol and all dont work, below is what I have tried so far.
<?php echo str_repeat('', 1) htmlencode('$postcode_coveringsRecord['postcode']) ?>
<?php echo htmlencode(' $postcode_coveringsRecord['postcode']) ?>
<?php echo htmlencode('. $postcode_coveringsRecord['postcode'].) ?>
<?php echo ' ''htmlencode('$postcode_coveringsRecord['postcode'])' ?>
<?php echo htmlencode(' ''$postcode_coveringsRecord['postcode']) ?>
How can I minipulate
where as the variable gives me one blank space prior to the variable content.
cheers for any input
emma
These ones should work
echo ' '.htmlencode($postcode_coveringsRecord['postcode']);
or
echo ' '.htmlencode($postcode_coveringsRecord['postcode']);
<?php echo $row["html"]; ?>
Inside of the $row["html"] there's:
<?php $Site->Nav($owner); ?>
but when I echo it, it only echoes:
Nav($owner); ?>
How may I print the full and make it usable, which means that it will print the function Nav?
I've tried to replace <?php with [[// i the database, and just before echoing it, I change back with replace. But without success
I think you need to use eval function of php. See the example below.
$string = 'cup';
$name = 'coffee';
$str = 'This is a $string with my $name in it.';
echo $str. "\n";
eval("\$str = \"$str\";");
echo $str. "\n";
Might be it can help.
Use eval function. It might solve your problem like this:
<?php echo eval($row["html"]); ?>
Keep the code as is in DB as if you are writing it in PHP file but without PHP opening and closing tags i.e. <?php and ?>. I haven't checked this (as i am not sure what $Site->Nav($owner); will do) but hope it would work in this case.
If I understand correctly you are wanting to output the results of $Site->Nav($owner);
I have no idea what this is expected to output, but assuming it is a string of some kind that you wish to display (hence echo) - an example of achieving this would be calling your code and have that method return the value, so you can echo it out. Ie:
function Nav($owner){
// Do your stuff
return 'Your Desired Output';
}
Then on your page you would have
<?php echo $Site->Nav($owner); ?>
Which would echo "Your Desired Output".
I am writing an application that will look at a single record, obtain values from about 12 flags (0 or 1), look up those flags against a status table (in MySQL) and return a variable called $status_message which is in that table.
In this table I need to have hyperlinks (working fine) but also echo some variables, i.e.
You have no bids for {{$row->_item_name}}
or
View this item now by clicking here
Now I need item name and the other example to be translated into <?php echo $row->_item_name; ?>
I have tried a preg_replace with the following:
<?php
$find = array('/{{/', '/}}/');
$replace = array('<?php echo ', ' ?>');
echo preg_replace($find, $replace, $status_message);
?>
but this is not working.
Can anyone advise how I can get the desired result and 'echo' the variable in the MySQL field?
Had a brainwave. Much simpler,
instead of $row->_item_name I just put {{itemname}} in the string. I then use the following code:
<?php
$message_buyer = str_replace('{{itemname}}', $row->_item_name , $message_buyer);
echo $message_buyer;
?>
so no need to have <?php calls in the string at all.
So I'm basically calling and returning an entire row from a mysql table using a while loop (which is working), but I'm trying to use the data that I call inside an html link, but I can't seem to get it to work.
Ideally, eventually it will just be a list of links with each person's individual name. I can return the list fine, but I can't seem to return the list with a link.
Here is my code that I feel should be working :(
<?php
require 'db/connect.php';
$result = $con->query('SELECT distinct name FROM mytable');
while($rows = $result->fetch_assoc())
{
echo ''$rows['name']'' , "</br>";
}
?>
Any help would be greatly appreciated!
Issue might be with your string concatenation. Try following code block
echo ''.$rows['name'].'';
echo ''. $rows['name']. '' , "</br>";
You just need to use . to concatenate strings together.
try this
echo ''.$rows['name'].'' , "</br>";
Should work just fine. Basically it's '.$row['name'].'
when concatenating strings with variables you have to use dot(.) like echo "string".$var; it will be invalid to write echo "string"$var; in your example you have ignored this point.
The following code is for a Wordpress plugin, it displays points and tank of a user:
<?php
if(function_exists('cp_displayPoints') && $authordata->ID){
echo '<span class="cubepoints_buddypress">'; cp_displayPoints($authordata->ID); echo '</span>';
if(function_exists('cp_module_ranks_getRank')) echo ' <span class="cupepoints_buddypress_rank">'.cp_module_ranks_getRank($authordata->ID).'</span>';
}
?>
I am trying to extract these two echo functions from the If statement but only succeeded with one of them. I can echo the points like this:
<?php cp_displayPoints($authordata->ID); ?>
Works fine. Now I tried doing the same with the second echo:
<?php cp_module_ranks_getRank($authordata->ID); ?>
But it did not work. Obviously, there is some basic thing that I am missing here. Do you know what it is?
The first one likely prints directly to output, while the second returns its value. So, you need to echo() the second one, just as they're doing in your sample code:
<?php echo cp_module_ranks_getRank($authordata->ID); ?>