Update table using variables - php

Question

I want to update a table using a array but I can't get it to work. It inserts the date in the table but the update query doesn't work.
<?php
session_start();
$dateinsert = $_SESSION['aanwezigheidsdatum'];
$nameninsertarr = $_SESSION['namen'];
for ($i =2 ; $i<$_SESSION['totaalpersoneel'];$i++){
$test = $_GET["ureninsert".$i];
if ($test == ""){$test = X;}
$ureninsertarray[$i-2] = $nameninsertarr[$i-2]." = '".$test."'";
}
$ureninsertarr = implode(' , ',$ureninsertarray);
echo $ureninsertarr;
include("connectdb.php");
$query = "INSERT INTO Aanwezigheidslijst (dag) VALUES ('$dateinsert')";
mysql_query($query);
$query = "UPDATE 'Aanwezigheidslijst' SET $ureninsertarr WHERE dag = '$dateinsert'";
echo "<br>".$query;
$putquery = mysql_query($query);
if (!$putquery) echo "error";
?>

Answer 1

thats because u have written update syntax wrong.u have to specify column name in 'set'.fix this issue and ur update query will work.
$query = "UPDATE Aanwezigheidslijst
SET column_name=$ureninsertarr
WHERE dag = $dateinsert";
update syntax:
UPDATE [LOW_PRIORITY] [IGNORE] table_reference
SET col_name1={expr1|DEFAULT} [, col_name2={expr2|DEFAULT}] ...
[WHERE where_condition]
[ORDER BY ...]
[LIMIT row_count]

Answer 2

$query = "UPDATE 'Aanwezigheidslijst' SET $ureninsertarr WHERE dag = '$dateinsert'";
should be changed in
$query = "UPDATE `Aanwezigheidslijst` SET $ureninsertarr WHERE dag = '$dateinsert'";
But should use another way to talk with your database. (PDO?)
In PDO it would look like
$stmt = $dbh->prepare("UPDATE `Aanwezigheidslijst` SET $ureninsertarr WHERE `dag` = ?");
$dbh->execute(array($dateinsert));
You should also take care or params used in $ureninsertarr. Getting them directly from $_GET means that you don't really know what is beeing inserted into you DB. (!SQL Injection!)
PDO Manual
EDIT: as posted before, $ureninsertarr needs to be a string that also cointains the columns nam. Not only the values...