This question already has answers here:
How can I convert ereg expressions to preg in PHP?
(4 answers)
Closed 9 years ago.
I have this code in my PHP form :
function IsEmail($email)
{
$pattern = "^([a-z0-9_]|\\-|\\.)+#(([a-z0-9_]|\\-)+\\.)+[a-z]{2,7}$";
return (eregi($pattern,$email)) ? true : false;
};
And my local server gives me an error :
Function eregi() is deprecated
So I modified my code to :
function IsEmail($email)
{
$pattern = "^([a-z0-9_]|\\-|\\.)+#(([a-z0-9_]|\\-)+\\.)+[a-z]{2,7}$";
return (preg_match($pattern,$email)) ? true : false;
};
and now I get this error :
Warning: preg_match() [function.preg-match]: No ending delimiter '^' found
Any idea ?
You should begin the regexp with / and also end it with /.
Like:
$pattern = "/^([a-z0-9_]|\\-|\\.)+#(([a-z0-9_]|\\-)+\\.)+[a-z]{2,7}$/";
Add a delimiter.
$pattern = "/^([a-z0-9_]|\\-|\\.)+#(([a-z0-9_]|\\-)+\\.)+[a-z]{2,7}$/";
In this case I used / as delimiter. It occurs once at the beginning and once at the end.
Note that you have to escape the delimiter character if it occurs in the regex itselfs and should not act as a delimiter but as normal matching char. So every / in your regex has to be escaped to \/ (except the delimiters of course). But you don't have any inside your regex.
Related
This question already has answers here:
Unknown modifier '/' in ...? what is it? [duplicate]
(4 answers)
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 9 years ago.
Regex PHP Code
// If url matches regex
$regex = "/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/";
if (preg_match($regex, $this->value)) {
$this->valid();
}
Error Message
Warning: preg_match() [<a href='function.preg-match'>function.preg-match</a>]: Unknown modifier 'p' in C:\Apache\www\profiletwist\lib\php\form\url.php on line 41
Call Stack
# Time Memory Function Location
1 0.0079 440016 {main}( ) ..\new.php:0
2 0.0964 667832 form->validate( ) ..\new.php:60
3 0.0968 668248 form_URL->validateUploadURL( ) ..\form.php:372
4 0.0969 668400 preg_match ( ) ..\url.php:41
Variables in local scope (#3)
$regex =
string '/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/' (length=79)
Question
How do I fix the regex for this "unknown modifier" error to not occur?
ultimately, I would like a regex that makes sure the text input matches:
"/upload/temporary/####_##_##_[A-z0-9 _-]+ "." [a-z]{3}
This is a filename target. The beginning does not change and the last part can be a random hash followed by an arbitrary extension. Further processing is done after the regex but this is the first test.
Thank you!
In a regex string you have to escape your delimiters. Or better: use a character which doesn't appear in the regex itself as delimiter:
other delimiter (recommended):
$regex = "#^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$#";
escaped delimiters:
$regex = "/^(\/upload\/temporary\/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ \/-]+.[A-z]{2,4}$/";
You need to escape the front slashes or just use another delimiter (I've used ! in this case):
$regex = "!^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$!"
$regex = "~^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[\w./-]+\.[a-z]{2,4}$~";
Change your delimiters to ~
When you use a delimiter for example /, you must escape all litteral / in your pattern otherwhise the regex engine believes that it is the end of the pattern.
Since u is a modifier and p isn't a modifier, you have this error because of the substring /^(/up....
This question already has answers here:
Unknown modifier '/' in ...? what is it? [duplicate]
(4 answers)
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 9 years ago.
Regex PHP Code
// If url matches regex
$regex = "/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/";
if (preg_match($regex, $this->value)) {
$this->valid();
}
Error Message
Warning: preg_match() [<a href='function.preg-match'>function.preg-match</a>]: Unknown modifier 'p' in C:\Apache\www\profiletwist\lib\php\form\url.php on line 41
Call Stack
# Time Memory Function Location
1 0.0079 440016 {main}( ) ..\new.php:0
2 0.0964 667832 form->validate( ) ..\new.php:60
3 0.0968 668248 form_URL->validateUploadURL( ) ..\form.php:372
4 0.0969 668400 preg_match ( ) ..\url.php:41
Variables in local scope (#3)
$regex =
string '/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/' (length=79)
Question
How do I fix the regex for this "unknown modifier" error to not occur?
ultimately, I would like a regex that makes sure the text input matches:
"/upload/temporary/####_##_##_[A-z0-9 _-]+ "." [a-z]{3}
This is a filename target. The beginning does not change and the last part can be a random hash followed by an arbitrary extension. Further processing is done after the regex but this is the first test.
Thank you!
In a regex string you have to escape your delimiters. Or better: use a character which doesn't appear in the regex itself as delimiter:
other delimiter (recommended):
$regex = "#^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$#";
escaped delimiters:
$regex = "/^(\/upload\/temporary\/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ \/-]+.[A-z]{2,4}$/";
You need to escape the front slashes or just use another delimiter (I've used ! in this case):
$regex = "!^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$!"
$regex = "~^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[\w./-]+\.[a-z]{2,4}$~";
Change your delimiters to ~
When you use a delimiter for example /, you must escape all litteral / in your pattern otherwhise the regex engine believes that it is the end of the pattern.
Since u is a modifier and p isn't a modifier, you have this error because of the substring /^(/up....
This question already has answers here:
Unknown modifier '/' in ...? what is it? [duplicate]
(4 answers)
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 9 years ago.
Regex PHP Code
// If url matches regex
$regex = "/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/";
if (preg_match($regex, $this->value)) {
$this->valid();
}
Error Message
Warning: preg_match() [<a href='function.preg-match'>function.preg-match</a>]: Unknown modifier 'p' in C:\Apache\www\profiletwist\lib\php\form\url.php on line 41
Call Stack
# Time Memory Function Location
1 0.0079 440016 {main}( ) ..\new.php:0
2 0.0964 667832 form->validate( ) ..\new.php:60
3 0.0968 668248 form_URL->validateUploadURL( ) ..\form.php:372
4 0.0969 668400 preg_match ( ) ..\url.php:41
Variables in local scope (#3)
$regex =
string '/^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$/' (length=79)
Question
How do I fix the regex for this "unknown modifier" error to not occur?
ultimately, I would like a regex that makes sure the text input matches:
"/upload/temporary/####_##_##_[A-z0-9 _-]+ "." [a-z]{3}
This is a filename target. The beginning does not change and the last part can be a random hash followed by an arbitrary extension. Further processing is done after the regex but this is the first test.
Thank you!
In a regex string you have to escape your delimiters. Or better: use a character which doesn't appear in the regex itself as delimiter:
other delimiter (recommended):
$regex = "#^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$#";
escaped delimiters:
$regex = "/^(\/upload\/temporary\/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ \/-]+.[A-z]{2,4}$/";
You need to escape the front slashes or just use another delimiter (I've used ! in this case):
$regex = "!^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[A-Za-z0-9._ /-]+.[A-z]{2,4}$!"
$regex = "~^(/upload/temporary/)[0-9]{4}_[0-9]{2}_[0-9]{2}_[\w./-]+\.[a-z]{2,4}$~";
Change your delimiters to ~
When you use a delimiter for example /, you must escape all litteral / in your pattern otherwhise the regex engine believes that it is the end of the pattern.
Since u is a modifier and p isn't a modifier, you have this error because of the substring /^(/up....
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
php regular expressions No ending delimiter ‘^’ found in
The code is as follows:
if(preg_match($exp, $value)){
return "";
}
the value of $exp is: ^[0-9]*$
the value of $value is: 7
and the output gives :
Warning: preg_match() [function.preg-match]: No ending delimiter '^' found in /...
$exp should be something like /^[0-9]*$/ for it to work the way you intended. It is assuming ^ is your regex delimiter, because it is the first character - you'd want your first char to be something else. See preg_match manual entry for details.
This question already has answers here:
Warning: preg_replace(): Unknown modifier
(3 answers)
Closed 3 years ago.
I'm trying to validate dates like DD/MM/YYYY with PHP using preg_match(). This is what my REGEX expression looks like:
$pattern = "/^([123]0|[012][1-9]|31)/(0[1-9]|1[012])/(19[0-9]{2}|2[0-9]{3})$/";
But using it with a correct value, I get this message:
preg_match(): Unknown modifier '('
Complete code:
$pattern = "/^([123]0|[012][1-9]|31)/(0[1-9]|1[012])/(19[0-9]{2}|2[0-9]{3})$/";
$date = "01/03/2011";
if(preg_match($pattern, $date)) return TRUE;
Thank you in advance
Escape the / characters inside the expression as \/.
$pattern = "/^([123]0|[012][1-9]|31)\/(0[1-9]|1[012])\/(19[0-9]{2}|2[0-9]{3})$/";
As other answers have noted, it looks better to use another delimiter that isn't used in the expression, such as ~ to avoid the 'leaning toothpicks' effect that makes it harder to read.
You use / as delimiter and also in your expression. Now
/^([123]0|[012][1-9]|31)/
Is the "complete" expression and all following is expected as modifier, also the (.
You can simply use another delimiter.
~^([123]0|[012][1-9]|31)/(0[1-9]|1[012])/(19[0-9]{2}|2[0-9]{3})$~
Or you escape all occurence of / within the expression, but I would prefer another delimiter ;) Its more readable.
your delimiter is /, but you are using it inside the pattern itself.
Use a different delimiter, or escape the /
You could escape the slashes / as suggested. It'll eventually lead to the Leaning Toothpick Syndome, though.
It's common to use different delimiters to keep your regular expression clean:
// Using "=" as delimiter
preg_match('=^ ... / ... $=', $input);
checek date using below function
function checkDateFormat($date)
{
//match the format of the date
if (preg_match ("/^([0-9]{2}) \/([0-9]{2})\/([0-9]{4})$/", $date, $parts))
{
//check weather the date is valid of not
if(checkdate($parts[2],$parts[1],$parts[3]))
return true;
else
return false;
}
else
return false;
}
echo checkDateFormat("29/02/2008"); //return true
echo checkDateFormat("29/02/2007"); //return false