Adding content of Array into where Condition in SQL query - php

Question

I'm trying to make this function get() that takes tbl_name and condition which will be used in WHERE.
Here $condition is an array like:
$condition = array(
'id' => 'some id',
'anycondition' => 'any value');
public function get($tbl_name, $condition = null) {
if($condition) {
$data = "select * from '$tbl_name' WHERE '$condition'";
}
else {
$data = $tbl_name;
}
return $data;
}
I want the echo be like this
select * from $tbl_name WHERE id='some id' and anycondition='any value'

Answer 1

Try This:
$query ="SELECT * FROM '$tbl_name' WHERE id='".$condition['id']."' AND anycondition='".$condition['anycondition']."'";

Answer 2

$data="select * from '$tbl_name' WHERE
(select array_to_string($condition, 'and', '') as condition);
here (in array_to_string) :
first parameter -->array
2nd -->concatenation text
3rd -->replacement of the null value in your array

Answer 3

This a horrible way a approach a class, which handles the database layer of your application. If I was you I read throughly into mysqli driver http://us2.php.net/manual/en/book.mysqli.php and come up with a better solution.
But here is what I think you were trying to accomplish in your opening post.
class A
{
public function sqlSelect($dbh, $tableName, $params=array()) {
if (!empty($param)) {
foreach ($params as $field => $value) {
// http://www.php.net/manual/en/function.mysql-real-escape-string.php
$value = mysql_real_escape_string($value, $dbh);
$whereSql[] = sprintf("%s = %s", $field, $value);
}
$whereSql = implode(" AND ", $whereSql);
return sprintf("SELECT * FROM %s WHERE %s",
$tableName, $whereSql);
}
return sprintf("SELECT * FROM %s", $tableName);
}
}
$condition = array(
'id' => 1234,
'some_other_column' => 'someOtherValue'
);
echo A.sqlSelect('SomeTableName', $condition);
echo A.sqlSelect('SomeOtherTableName');
Output:
SELECT * FROM SomeTableName WHERE id = 1234 AND some_other_column = 'someOtherValue'
SELECT * FROM SomeOtherTableName