Using Jquery autocomplete with images - php

Question

I am using the code bellow of foxycomplete to get some results from my db with images.
With local files works great but i cant do it with mysql.
Here is my code that i am using..
<form id="autocompleteForm" name="autocompleteForm" action="" method="post">
<input type="text" name="s" id="s" value="Search" style="border:none;" />
</form>
The Javascript Code:
(function($) {
$(document).ready(function() {
$( '#s' ).each( function(){
$(this).attr( 'title', $(this).val() )
.focus( function(){
if ( $(this).val() == $(this).attr('title') ) {
$(this).val( '' );
}
} ).blur( function(){
if ( $(this).val() == '' || $(this).val() == ' ' ) {
$(this).val( $(this).attr('title') );
}
} );
} );
$('input#s').result(function(event, data, formatted) {
$('#result').html( !data ? "No match!" : "Selected: " + formatted);
}).blur(function(){
});
$(function() {
function format(mail) {
return "<a href='"+mail.permalink+"'><img src='" + mail.image + "' /><span class='title'>" + mail.title +"</span></a>";
}
function link(mail) {
return mail.permalink
}
function title(mail) {
return mail.title
}
$("#s").autocomplete(completeResults, {
width: $("#s").outerWidth()-2,
max: 5,
scroll: false,
dataType: "json",
source: "video_search.php",
matchContains: "word",
parse: function(data) {
return $.map(data, function(row) {
return {
data: row,
value: row.title,
result: $("#s").val()
}
});
},
formatItem: function(item) {
return format(item);
}
}).result(function(e, item) {
$("#s").val(title(item));
//location.href = link(item);
});
});
});
})(jQuery);
And the php code to retrieve my data:
<?php
require "connectiondb.php";
if(isset($_REQUEST['s']))
{
$queryString = mysql_real_escape_string($_REQUEST['s']);
echo'var completeResults = [{';
$ss = mysql_query ("SELECT title, image FROM users WHERE title LIKE '$queryString%' LIMIT 7");
while($result = mysql_fetch_assoc($ss)) {
echo '
"permalink": "index.html",
"image": "'.$result['image'].'",
"title": "'.$result['title'].'"
},';
}
echo '}];';
}else{
}
?>
Thank you Guys!!!

Answer 1

Whats inside the $result['image']? If it contains the image file itself(binary data) and not just the path, then you need to create one more file (image.php?s=id) which would retreive just that binary data with adequate header.. ie
<?php
header('Content-Type: image/jpeg');
// sql stuff
echo $result['image'];
?>
In your main file you'll then call just
"image": "'.image.php?id='.$result['id'].'",
also, dont torture yourself and use json_encode() :)