PHP Session Getting CorrectValue - php

Question

Question: What to do to fix my problem on handling the session because it is returning an incorrect value.
Situation: I'm having problem on this session variable from the table. I added data from database to a table using while loop. Here is my code:
<form action="edit2.php" method="get">
<?php
$link = mysql_connect("localhost", "root", "root");
mysql_select_db("ispot", $link);
$result4 = mysql_query("SELECT * FROM user_ispot", $link);
$num_rows = mysql_num_rows($result4);
$result = mysqli_query($con,"SELECT * FROM complaints");
echo "<table border='1'>
<tr>
<th>Id Number</th>
<th>Category</th>
<th>Problem</th>
<th>Date Reported</th>
<th>Complaint ID </th>
<th>Action</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td name=id_num>" . $row['id_number'] . "</td>";
$_SESSION['favcolor'] = "$row[id_number]";
echo "<td name=remarks>" . $row['remarks'] . "</td>";
echo "<td name=status>" . $row['status'] . "</td>";
echo "<td name=date>" . $row['date_reported'] . "</td>";
echo "<td>" . "<INPUT TYPE = text Name = cid VALUE = " . $row['complaint_id'] . ">" . "</td>";
echo "<td>" . "<INPUT TYPE = Submit Name = Submit1 VALUE =Edit>" . "</td>";
echo "</tr>";
}
echo "</table>" ;?>
And it looks like this:
As you can see, there is the edit button, where I can edit a specific row in the table.
When I press the edit button, this will show:
Notice that the User ID is wrong, what can I do to fix it? because the user id that is being post here was the last user_id that was inserted in the table.
And here is my code for the second image:
<b>Date:</b> <input type='text' name='today' placeholder='<?php echo $today ?>' disabled='disabled'> <br><br>
<b>User ID:</b> <input type='text' disabled='disables' name='userid' placeholder='<?php
//$comid = $_GET["cid"];
//echo $userid;
echo $_SESSION['userid'];
//$result = mysqli_query($con,"SELECT * FROM complaints WHERE id = XXX");
//$row = mysqli_fetch_assoc($result);
//print_r($row);
//$result2 = mysql_query("SELECT * FROM complaints WHERE complaint_id = '$comid'", $link);
//$result2 = mysql_query("SELECT * FROM complaints", $link);
//while($row = mysql_fetch_assoc($result2))
//{
//echo $row['id_number'];
//}
?>'></br><br>
Any help would be appreciated. Thank you.

Answer 1

i replaced the button with a link, used it to pass the value when edit is clicked, catch the value with a get and it works for me.
in edit.php
echo "<td> <a href = 'edit2.php?id=$num_id'>Edit</a></td>";
in edit2.php
$id = $_GET['id'];
<b>User ID:</b> <input type='text' disabled='disables' name='userid' value = '<?php echo $id;?>'></input type>

Answer 2

$result2 = mysql_query("SELECT * FROM complaints WHERE complaint_id = '$comid'", $link);
$result2 = mysql_query("SELECT * FROM complaints", $link);
You must use just one of them this rows. I think problem is the second row. This query not choose the "id" that is "comid".
Your first query row is enough:
$result2 = mysql_query("SELECT * FROM complaints WHERE complaint_id = '$comid'", $link);