Update ALL records in active record - codeignighter - php

Im trying to update all records in the DB, there is no key and no where clause.
But im getting an error saying I must specify a where clause.
$data = array('views' => 0);
$this->db->update_batch('table_places', $data);

Simply using
$data = array('views' => 0);
$this->db->update('table_places', $data)
will update all the records in the table_places database for you.
update_batch() is used for updating multiple rows in your table with different data.

Related

Laravel update specific column in database 'cost' and add supplier_id to another database table

i'm working with sensitive data hope you can help find if there any wrong in code's writing
i have list of suppliers in my database i added column 'cost'
i'm trying to update and insert cost for existing suppliers from specific query
and i created model and migration to get foreign keys too by adding the puled supplier id from the query
....
$suppliers_data = $suppliers_query->fetchall(PDO::FETCH_ASSOC);
foreach ($suppliers_data as $supplier_data) {
$supplier_name = $supplier_data['supplier_name'];
$cost_rate = $supplier_data['Cost'];
if (!Supplier::where('supplier', $supplier_name)->exists()) {
Supplier::insert([
'supplier' => $supplier_name,
'cost_rate' => $cost_rate
]);
} else {
Supplier::update([
'cost_rate' => $cost_rate // does this will update cost for the current supplier ?
]);
}
$supplier_id = Supplier::where('supplier', $supplier_name)->pluck('supplier_id');
Test::insert($supplier_id);
}
$supplier_count = test::count();
Test::update(['test_data_count' => $supplier_count]);
Updating table data with supplier name is not correct here I believe. Instead of using supplier name in where condition using particular supplier id is recommended for better application. Names can be duplicate so its not a good idea to use supplier name in where.
In your current code I have 2 things to say :
You need to add where in update eloquent to work properly
Supplier::where('supplier', $supplier_name)
->update([
'cost_rate' => $cost_rate // this will update cost for the current supplier
]);
Or to minimalize the code you can use updateorCreate method instead of making insert and update in the if() else() condition
Supplier::updateOrCreate(
['supplier' => $supplier_name],
['cost_rate' => $cost_rate]
);

Laravel/Mysql: unable to set field to null

I am working on a laravel project and trying to duplicate a record in mysql db.
after replication I want to set a field value to null(appointment_status).
everything is working except the new record's value (appointment_status) is the same as the original record even tho I set it to null.
$newAppointment = $appointment->replicate();
//push to get the id for the cloned record
$newAppointment->push();
$newAppointment->duplicated_from_id = $appointment->id;
$newAppointment->appointment_status = null;
$newAppointment->save();
//updating the old appointment
$appointment->duplicated_to_id = $newAppointment->id;
$appointment->save();
Instead of whole code-block, try something like this:
// replicate as the new record with some different fields
$newAppointment = $appointment->replicate()->fill([
'duplicated_from_id' => $appointment->id,
'appointment_status' => null,
])->save();
// update some fields of initial original record
$appointment->update([
'duplicated_to_id' => $newAppointment->id,
]);
For more check out this.

Array to string conversion error in Code Igniter when inserting array of data into table in database

I'm trying to insert an array of data into a table in database but an error said Array to string conversion error
This is the post function in my controller, first i post an array of data. The values of the array will be the names, and numbers, they are not id. The id is only kodejdwl. This will be pass to my model
function index_post() {
$data = array(
'kodejdwl' => $this->post('kodejdwl'),
'tahun_akad' => $this->post('kode_tahun_akad'),
'semester' => $this->post('semester'),
'mk' => $this->post('mk'),
'ruangan' => $this->post('ruangan'),
'nama_dosen' => $this->post('nama_dosen'),
'namakelas' => $this->post('nama_kelas'),
'jam_mulai' => $this->post('jam_mulai'),
'jam_selesai' => $this->post('jam_selesai'),
);
}
After the data from above code is passed to the model. I created some new variables which are the id of each the name of the value in the array data. e.g if the value of data['mk'] is Website then the id will be 1 and that id will be stored in variable $kodemk and i do it to each value in the data. Then i created new_data which stores array of the id's which i previously made. Then i insert that array into one table in my database. I thought it would be fine but it said Array to string conversion error. What should i do so i could insert that array into the table in my database?
public function insert($data){
$this->db->select('thn_akad_id');
$tahunakad_id = $this->db->get_where('tik.thn_akad',array('tahun_akad'=>$data['tahun_akad'],'semester_semester_nm'=>$data['semester']))->result();
$this->db->flush_cache();
$this->db->select('kodemk');
$kode_mk = $this->db->get_where('tik.matakuliah',array('namamk'=>$data['mk']))->result();
$this->db->flush_cache();
$ruangan = $this->db->get_where('tik.ruangan', array('namaruang' => $data['ruangan']), 1)->result();
$this->db->flush_cache();
$this->db->select('nip');
$nip_dosen = $this->db->get_where('tik.staff',array('nama'=>$data['nama_dosen']))->result();
$this->db->flush_cache();
$this->db->select('kodeklas');
$kodeklas = $this->db->get_where('tik.kelas',array('namaklas'=>$data['namakelas']))->result();
$this->db->flush_cache();
$this->db->select('kode_jam');
$kode_mk = $this->db->get_where('tik.wkt_kuliah',array('jam_mulai'=>$data['jam_mulai'],'jam_selesai'=>$data['jam_selesai']))->result();
$this->db->flush_cache();
$new_data = array(
'kodejdwl' => $data['kodejdwl'],
'thn_akad_thn_akad_id' => $tahunakad_id,
'matakuliah_kodemk' => $kode_mk,
'ruangan_namaruang' => $ruangan,
'staff_nip' => $nip_dosen,
'kelas_kodeklas' => $kodeklas,
);
$insert = $this->db->insert('tik.jadwal_kul', $new_data);
return $this->db->affected_rows();
}
You probably want to use row() instead of result() because it'll contain only one result that you want. If you want to use result() and store multiple values then you'll have to use implode to concatenate them and store it as a string.
I've written a possible solution for your problem; Some things were missing, so I've mentioned them in the comments. See if this helps you.
public function insert($data){
$this->db->select('thn_akad_id');
$tahunakad_id = $this->db->get_where('tik.thn_akad',array('tahun_akad'=>$data['tahun_akad'],'semester_semester_nm'=>$data['semester']))->row(); // use row here
$this->db->flush_cache();
$this->db->select('kodemk');
$kode_mk = $this->db->get_where('tik.matakuliah',array('namamk'=>$data['mk']))->row();
$this->db->flush_cache();
// remove your_ruangan_column with your desired column name
$this->db->select('your_ruangan_column');
$ruangan = $this->db->get_where('tik.ruangan', array('namaruang' => $data['ruangan']), 1)->row();
$this->db->flush_cache();
$this->db->select('nip');
$nip_dosen = $this->db->get_where('tik.staff',array('nama'=>$data['nama_dosen']))->row();
$this->db->flush_cache();
$this->db->select('kodeklas');
$kodeklas = $this->db->get_where('tik.kelas',array('namaklas'=>$data['namakelas']))->row();
$this->db->flush_cache();
// Not sure where this ↓↓ is being used but you can use it the same way as others
$this->db->select('kode_jam');
// duplicate variable name here ↓↓ (fix this)
$kode_mk = $this->db->get_where('tik.wkt_kuliah',array('jam_mulai'=>$data['jam_mulai'],'jam_selesai'=>$data['jam_selesai']))->row();
$this->db->flush_cache();
$new_data = array(
'kodejdwl' => $data['kodejdwl'],
'thn_akad_thn_akad_id' => $tahunakad_id->thn_akad_id, // {$tahunakad_id} consists an object with the key {thn_akad_id}-- table_column_name
'matakuliah_kodemk' => $kode_mk->kodemk, // ...
'ruangan_namaruang' => $ruangan->your_ruangan_column, // ...
'staff_nip' => $nip_dosen->nip, // ...
'kelas_kodeklas' => $kodeklas->kodeklas // ...
);
$insert = $this->db->insert('tik.jadwal_kul', $new_data);
return $this->db->affected_rows();
}
Your are making a total of 7 separate trips to the database. Best practice recommends that you always minimize your trips to the database for best performance. The truth is that your task can be performed in a single trip to the database so long as you set up the correct INSERT query with SELECT subqueries.
I don't know what your non-English words are, so I will use generalized terms in my demo (I've tested this successfully in my own CI project). I am also going to reduce the total subqueries to 3 to reduce the redundance in my snippet.
$value1 = $this->db->select('columnA')->where('cond1', $val1)->get_compiled_select('childTableA');
$value2 = $this->db->select('columnB')->where('cond2', $val2)->get_compiled_select('childTableB');
$value3 = $this->db->select('columnC')->where('cond3', $val3)->get_compiled_select('childTableC');
return (int)$this->$db->query(
"INSERT INTO parentTable
(column1, column2, column1)
VALUES (
($value1),
($value2),
($value3)
)"
);
// to mirror your affected rows return... 1 will be returned on successful insert, or 0 on failure
Granted this isn't using the ActiveRecord technique to form the complete INSERT query, but this is because CI doesn't allow subqueries in the VALUES portion (say, if you were to use the set() method). I am guessing this is because different databases use differing syntax to form these kinds of INSERTs -- I don't know.
The bottom line is, so long as you are fetching a single column value from a single row on each of these sub-SELECTs, this single query will run faster and with far less code bloat than running N number of individual queries. Because all of the variables involved are injected into the sql string using get_compiled_select() the stability/security integrity should be the same.

PostgreSQL Update Issue With Quotation('')

I'm using PostgreSQL & Codeigniter. There is a table called folio in the database. It has few columns containing remarks1, remarks2, remarks3 as well. Data for the all the other columns are inserted when the INSERT statement executes for the 1st time.
When I try to execute below UPDATE statement later for the below 3 columns, remarks1 column get updated correctly. But remarks2, remarks3 columns are updated with ''.
UPDATE "folio" SET "remarks1" = 'test remark', "remarks2" = '', "remarks3" = '' WHERE "id" = '51';
Given that remarks1, remarks2, remarks3 columns data type is character varying. I'm using Codeigniter active records. At a time all 3 columns could be updated else single column could be updated depending on the user input.
What could be the issue? How can I fix this? Why columns are updated with ''?
As requested the php array in CI would be below
$data = array(
'remark1' => $this->input->post('remark1'),
'remark2' => $this->input->post('remark1'),
'remark3' => $this->input->post('remark1')
);
Function which saves the data contains below two lines only
$this->db->where('id', $folio_id);
$this->db->update('folio', $data);
Those columns are updated with '' because you tell them to?
Let's take a closer look at the query
UPDATE "folio"
SET
"remarks1" = 'test remark',
"remarks2" = '',
"remarks3" = ''
WHERE
"id" = '51';
First you select the table folio for the update.
Then you tell it to update remarks1 through remarks3 with new values. For remarks2 and remarks3 you specify to set them to an empty string. And that's what's going to happen.
Last but not least, you tell it to only apply this update to rows where id equals 51.
So, in order to only update remarks1 you can simply remove the other columns from your update:
UPDATE "folio"
SET
"remarks1" = 'test remark'
WHERE
"id" = '51';
Update:
I'm by far not a CI expert, but from what I see, I'd change the $data array to only contain information for remark1:
$data = array(
'remark1' => $this->input->post('remark1')
);
And (from my understanding) it should only update this single column.

Query about CI's DB function '$query->row_array()'

I'm using the DB class of CI framework. There're 5 rows queried out from the first line, and the second line printed 5, but why did the statement count($query->row_array())(or count($query->row_array(),1)) returned 11(the field number of table) and only one row filled in the result, rather than 5 rows?
$query = $this->db->query($SQL_BYLABEL, array($labelId, $orderby, (int)$m, (int)$n));
log_message('error', $query->num_rows()); // 5 rows
log_message('error', count($query->row_array())); // 11
$query->row_array() returns the data of one record as an array. So count($query->row_array() return the number of columns of the table.
Check the manual.

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