display inline html from php search - php

Source can be found here: results.php
and the zip: Results zip
<?php
// create short variable names
$searchtype=$_POST['searchtype'];
$searchterm=trim($_POST['searchterm']);
if (!$searchtype || !$searchterm) {
echo '<p><strong>You have not entered search details. Please go back and try again.</strong></p>';
exit;
}
if (!get_magic_quotes_gpc()){
$searchtype = addslashes($searchtype);
$searchterm = addslashes($searchterm);
}
# $db = new mysqli("*","*","*","*");
if (mysqli_connect_errno()) {
echo 'Error: Could not connect to database. Please try again later.';
exit;
}
$query = "select * from acronymns where ".$searchtype." like '%".$searchterm."%' ORDER BY title ";
$result = $db->query($query);
$num_results = $result->num_rows;
echo "<p>Number of records found: ".$num_results."</p>";
for ($i=0; $i <$num_results; $i++) {
$row = $result->fetch_assoc();
echo "<p><strong>".($i+1).". ";
echo $row['acro'];
echo " - ";
echo $row['title'];
echo "</strong><br />";
echo $row['desc'];
echo "</p>";
}
// $result->free();
$db->close();
Output looks like:
Americans with Disabilities Act (ADA)
The Americans with Disabilities Act was enacted in 1990 to establish the prohibition of discrimination on the basis of disability, which may include autism. The ADA is divided into three Titles. Title I speaks to employment law, Title II covers State and Local activities (including public transportation), and Title III relates to accommodations in public buildings and businesses.
The link is: www.ada.com target="_blank" Americans with Disabilities Act</a> (within the MySql db.
The actual link shows: http://mysiteishere.com/"www.ada.com" which of course makes a 404 Error.
Thanks ahead of time.

Just because the desc filed contains URL's doesn't mean they will autmoatically show up as links in your HTML. You need to output the links as an href value in an <a> element to make a clickable link. You are probably best off not storing full HTML in your DB, but rather just the link. It looks like you combination now is producing an invalid link. Simple look at your HTML source and fix it.

From what you said, it seems that you're not including the link correctly. It doesn't have anything to do with the $row['desc'] but what's inside it. When you're inserting the link from whatever form you're using, use the following.
ex:
Americans with Disabilities

You can use the below function while fetching 'DESC' column
function make_links_clickable($text){
return preg_replace('!(((f|ht)tp(s)?://)[-a-zA-Zа-яА-Я()0-9#:%_+.~#?&;//=]+)!i', '$1', $text);}
For Eg.
$text = 'Here is link: http://google.com And http://example.com inside. And another one at the very end: http://test.net';
echo make_links_clickable($text);

Went ahead and changed my code and the text in the db. In the db I removed the Text.. and put the in between parentheses. The Php I changed to the following and now it shows the links with the urls, so it works. It's the "a href.." that I can't make work. I don't understand why though.
for ($i=0; $i <$num_results; $i++) {
$row = $result->fetch_assoc();
echo "<strong>".($i+1).". ";
//echo $row['acro'];
//echo " - <br />";
//echo "<br>";
echo $row['title'];
echo " - ";
echo "<br>";
echo "</strong>";
$text = $row['desc'];
$text = preg_replace('/(^|[^"])(((f|ht){1}tp:\/\/)[-a-zA-Z0-9#:%_\+.~#?&\/\/=]+)/i','\\1\\2', $text);
echo $text;
}

The link in the MysqlDB should be:
Americans with Disabilities Act
Now lets assume you got this right, you should look at your charset of your DB, just making sure they match your editors charset.
That said, please post the output of HTML "Show source".

Related

PHP form loop only submit last value or all values

The context is: e-commerce, the problem stands in adding items to the cart.
I created a while loop to iterate through each item my query returns and each item has a button that redirects to a "info on the item" page. My problem is that since there's a loop, the values to submit (e.g. the ID of the item) is overloaded and every button submits the values of the last item.
I can pass all the IDs of all the plants but i have no idea how to, in the "item detail" page, to show the correct item among the array.
lista-piante.php: (summarized)
<?php session_start();
// connect to the database
$connessione = new mysqli('localhost', 'root', 'root', 'mio');
//query
$user_check_query = "SELECT Pianta.NOME as nome, PIANTA.ID as pid, Item.PREZZO as prezzo, Item.ID as id
FROM Item, Pianta WHERE Pianta.ID = Item.PIANTA";
$result = mysqli_query($connessione, $user_check_query);
if($result->num_rows > 0) {
echo"<h3>Lista delle nostre piante</h3>";
echo"<ul class=\"plant-flex\">";
// loop through records
while($row = $result->fetch_array(MYSQLI_ASSOC)){
echo"<form method='get' action='../html/details-pianta.php'>";
echo"<li>";
echo"<div class='plant-preview'>";
echo"<div class='plant-preview-description'>";
//dichiarazione variabili (per leggibilità)
$nome= $row['nome'];
$pid = $row['pid'];
// PRINT NAME
echo"<div class='plant-preview-description-name'>";
echo "<p class='bold'>" . $nome . "</p>";
echo "<input type='hidden' name='name' value='$nome' />";
echo"</div>";
echo "<input type='hidden' name='pid[]' value='$pid' />";
echo"<div>";
echo"<button type=\"submit\" class=\"btn\" name=\"details_plant\">Dettagli" . $item . "</button>";
echo"</div>";
echo"</li>";
echo"<form/>";
}
$result->free();
}
echo "<ul/>";
$connessione->close();
details-pianta.php: (summarized, it will contain the style of the page)
<?php session_start();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="it" lang="it">
<head> <!-- meta tag and other stuff --> </head>
<body>
<div>
<?PHP include('../php/dettagli-pianta.php'); ?>
</div>
</div>
</body>
</html>
dettagli-pianta.php: (summarized, it should contain the info of each item)
<?php
session_start();
// connect to the database
$connessione = new mysqli('localhost', 'root', 'root', 'mio');
$pid = mysqli_real_escape_string($connessione, $_GET['pid']);
//but pID is either the last item's id, or an array with all items' ids, so i can't chose the only one i want
//the URL shows always more pIDs (from the lista-piante.php get form)
$user_check_query = "SELECT * FROM Pianta, item WHERE Pianta.ID = '$pid' ";
$result = mysqli_query($connessione, $user_check_query);
if($result->num_rows > 0) {
echo"<h3>Dettagli della pianta</h3>";
echo"<ul>";
//loop thought query records
while($row = $result->fetch_array(MYSQLI_ASSOC)){
echo"<form method='post' action='../php/add-carrello.php'>";
echo"<li>";
echo"<div>";
//dichiarazione variabili (per leggibilità)
$nome =$row['NOME'];
//$genere= $row['GENERE'];
//$specie= $row['SPECIE'];
//etc etc
// PRINT NAME
echo"<div>";
echo "<p class='bold'>" . $nome . "</p>";
echo"</div>";
//echo"<div>";
//echo "<p class='bold'>" . $specie. "</p>";
//echo"</div>";
//echo "<input type='hidden' name='pid' value='$pid' />";
echo"<div>";
echo"<button type=\"submit\" class=\"btn\" name=\"add-carrello\"> Aggiungi al carrello</button>";
echo"</div>";
echo"</li>";
}
$result->free();
}
echo "<ul/>";
$connessione->close();
There is an error with form closing, but... I have a feeling you are complicating it for yourself by using all those forms/buttons.
I would clean up the code and get rid of the form/button scheme altogether, and use simple a href links with ?id=$pid
Something like this (shortened, if needed post a comment and I can expand):
while($row = $result->fetch_array(MYSQLI_ASSOC)){
echo "<li>";
echo "<div class='plant-preview'>";
echo "<div class='plant-preview-description'>";
//dichiarazione variabili (per leggibilità)
$nome = $row['nome'];
$pid = $row['pid'];
// PRINT NAME
echo "<div class='plant-preview-description-name'>";
echo "<p class='bold'>" . $nome . "</p>";
echo "</div>";
echo "<div>";
echo "<a href ='../html/details-pianta.php?pid=$pid'>Dettagli " . $nome . "</a>";
echo "</div>";
echo "</li>";
}
You can use CSS later to make your a-href link look like a button, add image, or play with it any way you like.
Then in the product details page (dettagli-pianta.php) use your product id pretty much same as you already do:
$pid = $_GET['pid']
...
$user_check_query = "SELECT * FROM Pianta WHERE Pianta.ID = '$pid' ";
Here is one Stack Overflow that talks about using link instead form:
How send parameter to a url without using form in php?
Edit (mistakes found, more suggestions, in case you still want to keep forms/buttons):
you did not close ?> in your examples, but ok, probably just copy/paste here
you have $item variable that isn't defined, and not pulled from SELECT query, so I can only assume that is supposed to be $nome (or you deleted something to make it shorter in question and forgot about it)
you also probably wanted a space like this (note space after Dettagli)
echo "<button type='submit' class='btn' name='details_plant'>Dettagli " . $nome . "</button>";
not sure why you keep files in folders "../html/" and "../php/" when both are with extensions .php, could be confusing for others later working on your code, or ... maybe it's just me
you have <?php session_start();?> then under it you include a file that also has <?php session_start();?> ... no need for one of them. Since "details-pianta.php" is in folder "html" I guess you can remove it from there, as you don't need session just to include another PHP file
in form you submit name='pid[]' when you should just use name='pid' (no brackets), like this:
echo "<input type='hidden' name='pid' value='$pid' />";
in "dettagli-pianta.php" you have a select like this: $user_check_query = "SELECT * FROM Pianta, item WHERE Pianta.ID = '$pid' "; where you name two tables but don't join them, and I can only assume it should be $user_check_query = "SELECT * FROM Pianta WHERE Pianta.ID = '$pid' ";
be careful of uppercase/lowercase in database and column names, try to standardize
in one line you echo with mixed quotes something like echo "<bla name='bla'>" and in next you escape quotes like echo "<bla name=\"bla\">" ... make it easy on yourself and - standardize. Unless absolutely necessary, first way (mixing single and double quotes) is preferable, and only when you have something really complicated to echo like mix of HTML+JavaScript, then resort to escaping quotes
And finally, but actually a direct answer to your issue - you closed your form in the wrong way (yeah, had to look real hard to see it):
echo"<form/>";
You need to have (space is optional, reads better):
echo "</form>";
Non the less, as others too have already commented, using forms just to get buttons is an overkill. Try using simple links (<a href> elements) and style them with CSS to your liking, making them look like buttons...
And last, but... I believe it to be important... Try not to mix Italian and English in code (including database structure). It is obvious you are just learning but havin database called "mio" with table "pianti" and column "prezzo" ... then use something like "item". Also, names of files like "details-pianta", then you have another file "detaggli_pianta", and in button name you use "details_plant", it is huge mashup of two languages. you seem to be fluent English speaker judging from your question, so - why not use English everywhere in code? Name your database "my_first_web_store", name your table "plants", name your column "price", name your PHP files "plant_details" (or details_plant, whatever), use comments in English in your code (nobody but you and other developers see that). You will be thankful later when your plant-selling company expands worldwide, and when you will have multi-language webshop, and maybe 3 more developers working from India and US, all working on same project... :)
Have fun learning!

Use PHP to generate from an existing database for each row a new specific HTML that i already made

First I'm hitting on a wall here and I really could use your help. I coded the database so I have it all up and working plus all the data inside. I worked the HTML and the CSS media print query and I have it how I want it to look exactly. All I have to do now is:
for every row of the mysql select table I have to fill every specific input form
of the html page I made and print it
Can someone give me a hint of how I can do that?
Assuming you want to connect to your database and simply fetch the id you can do the following.
Ensure you change my_host, my_user, my-password, my_databse,my_tablewith your configuration settings. Then if you want to fetch anything else thanid` just change it to the column name you are looking for.
Be aware we are using PHP here.
// Open Connection
$con = #mysqli_connect('my_host', 'my_user', 'my-password', 'my_databse');
if (!$con) {
echo "Error: " . mysqli_connect_error();
exit();
}
// Some Query
$sql = 'SELECT * FROM my_table';
$query = mysqli_query($con, $sql);
while ($row = mysqli_fetch_array($query))
{
echo $row['id'];
}
// Close connection
mysqli_close ($con);
Check this link to get a in-depth explanation.
You can do this with two pages. One page gives you the overview and the other page gives you a print preview of your invoice.
The overview:
// DB select stuff here
while ($row = $result->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>\n";
echo " <td>".htmlspecialchars($row['what'])."</td>\n";
echo " <td>".htmlspecialchars($row['ever'])."</td>\n";
echo " <td>Detail</td>\n";
echo "</tr>\n";
}
The detail page:
$sql = 'SELECT your, columns FROM tab WHERE id = ?';
$stmt = $db->prepare($sql);
$stmt->execute(array($_GET['id']));
$row = $stmt->fetch(PDO::FETCH_ASSOC);
if (!$row) {
echo "There is no data for the given Id\n";
return;
}
echo "What: ".htmlspecialchars($row['what'])."<br />\n";
echo "Ever: ".htmlspecialchars($row['ever'])."<br />\n";

php text in css tooltip

What I am trying to do is add information from extracted with php into a css tooltip. The text, instead of appearing inside the tooltip, appears next to the label tag I have. The tooltip appears over the label tag. Here my code so you can probably help me:
<form action="<?php echo $_SERVER['PHP_SELF']?>" method="post">
<?php
//Connect to the database
require_once("dboconn.php");
$conn=ConnectionFactory::connect();
$query = "SELECT * FROM programmer";
$resultset = $conn->query($query);
function projects($prog_id){
require_once("dboconn.php");
$conn=ConnectionFactory::connect();
$query2= "SELECT * FROM programmer pm INNER JOIN project p ON pm.programmer_id=p.programmer_id WHERE pm.programmer_id=:id";
$resultset2= $conn->prepare($query2);
$resultset2->bindValue(":id",$prog_id);
$resultset2->execute();
$isthere=false;
while($row2 = $resultset2->fetch()){
echo "Working on project ".$row2['project_id'].".";
$isthere=true;
}
if(!$isthere){
echo "No projects";
}
}
while ($row = $resultset->fetch())
{
echo "<p class='col'>";
echo "<input type='checkbox' name='programmers[]' id='programmer".$row['programmer_id']."' value='".$row['programmer_id']."'>";
echo "<a href='' class='help tip-below' data-tip='".projects($row['programmer_id'])."'><label for='programmer".$row['programmer_id']."'>".$row['programmer_name']." ".$row['programmer_surname']."</label></a>";
echo "</p>";
}
?>
Thanks a lot for helping me out!
Your function projects() has no return value (instead you print it, which is bad practice btw)!
Change
while($row2 = $resultset2->fetch()){
echo "Working on project ".$row2['project_id'].".";
$isthere=true;
}
if(!$isthere){
echo "No projects";
}
To something like this
$result = "";
while($row2 = $resultset2->fetch()){
$result .= "Working on project ".$row2['project_id'].".";
}
if(empty($result)){
return "No projects";
}
return $result;
To clarify this, you can think of a function as a calculator maybe. You input specific data (an equation e.g.) and it returns something (the solution). What happens inside, you don't know and don't really care.
Now back to PHP, the input is clear: the parameters ($prog_id), but your function has no return, instead it just prints something to the screen (what you really shouldn't do outside a development environment). To test this you can use
var_dump( projects($some_id) );
And it will return NULL (because no return was specified), but what you really wanted was a string of some sort.

Apply CSS Styling to PHP output

The following displays HTML results from the database field "Never". I am trying to apply CSS styling to the output.
Here's what I have...
echo "<p><strong>Never:</strong> ".$results['Never']."".$results['text']."</p><br />";
Here's what I've tried...
echo "<p><strong>Never:</strong> ".$results['<div id="nevermsg">'Never'</div>]."".$results['text']."</p><br />";
Here's my CSS...
#nevermsg { color: red; }
...but it's not applying properly. I am receiving a syntax error and a headache. Am I putting this in the wrong spot?
The $results variable is not being filled.
Edit: Code Added
Here's my connection...
<?php
mysql_connect("localhost", "jpcso_compliance", "abc*123") or die("Error connecting to database: ".mysql_error());
/*
localhost - it's location of the mysql server
root - username
third is your password
if connection fails it will stop loading the page and display an error
*/
mysql_select_db("jpcsolut_compliance") or die(mysql_error());
/* jpcsolut_webfro_HS is the name of database we've created */
?>
There is no other HTML formatting for the output, other than what is right here...
<div id="title">
<p><h1>Database Search Results</h1></p></div>
<br />
<div id="main_inner">
<?php
$query = $_GET['query'];
// gets value sent over search form
$min_length = 2;
// you can set minimum length of the query if you want
if(strlen($query) >= $min_length){ // if query length is more or equal minimum length then
$query = htmlspecialchars($query);
// changes characters used in html to their equivalents, for example: < to >
$query = mysql_real_escape_string($query);
// makes sure nobody uses SQL injection
$raw_results = mysql_query("SELECT * FROM Compliance
WHERE (`Question` LIKE '%".$query."%') OR (`Sample Response / Must` LIKE '%".$query."%') OR (`Must` LIKE '%".$query."%') OR (`Can` LIKE '%".$query."%') OR (`Never` LIKE '%".$query."%') OR (`Tags` LIKE '%".$query."%')") or die(mysql_error());
// * means that it selects all fields, you can also write: `id`, `title`, `text`
// IllegitimateHighSchools is the name of our table
// '%$query%' is what we're looking for, % means anything, for example if $query is Hello
// it will match "hello", "Hello man", "gogohello", if you want exact match use `title`='$query'
// or if you want to match just full word so "gogohello" is out use '% $query %' ...OR ... '$query %' ... OR ... '% $query'
if(mysql_num_rows($raw_results) > 0){ // if one or more rows are returned do following
while($results = mysql_fetch_array($raw_results)){
// $results = mysql_fetch_array($raw_results) puts data from database into array, while it's valid it does the loop
echo "<p><strong><u><h2>Question:</u> ".$results['Question']."".$results['text']."</h2></u></strong></p><br />";
echo "<p><strong>Sample Response / Must:</strong> ".$results['Sample Response / Must']."".$results['text']."</p><br />";
//echo "<p><strong>Location:</strong> <a href='".$results['Location']."' target='_blank'>".$results['SchoolLocation']."</a>".$results['text']."</p><br />";
echo "<p><strong>Must:</strong> ".$results['Must']."".$results['text']."</p><br />";
echo "<p><strong>Can:</strong> ".$results['Can']."".$results['text']."</p><br />";
//echo "<p><strong>Never:</strong> ".$results['Never']."".$results['text']."</p><br />";
echo "<span id=\"nevermsg\"><p><strong>Never:</strong> ".$results['Never']."".$results['text']."</p></span><br />";
echo "<p><strong>_____________________________________________</strong> "."</p><br />";
echo "<p><strong>Tags:</strong> ".$results['Tags']."".$results['text']."</p>";
// posts results gotten from database(title and text) you can also show id ($results['id'])
}
}
else{ // if there is no matching rows do following
echo "<br /><br /><br /><strong><h2>"."You have searched a term that is not in the database. Please contact ".htmlentities('email#domain.com') . ", if you think this term should be added."."</h2></strong>";
}
}
else{ // if query length is less than minimum
echo "Minimum length is ".$min_length;
}
?>
<br />
<br />
<br />
<br />
<br />
<br />
</div>
<!--End of Inner Main-->
Additionally, here is a link to the site, where I've included a query in the URL here.
Lastly, I call the stylesheet 'global.css', which is where the style lives.
#nevermsg { color: red; }
You need to change the array type in your while loop. mysql_fetch_array will return a standard array accessed like $array[0] not $array['my_key'] so use mysql_fetch_assoc.
So instead of this:
while ($results = mysql_fetch_array($raw_results)) {
echo "<p><strong>Never:</strong> <span id=\"nevermsg\">".$results['Never']."</span></p>"; //Doesn't
}
Do this:
while ($results = mysql_fetch_assoc($raw_results)) {
echo "<p><strong>Never:</strong> <span id=\"nevermsg\">".$results['Never']."</span></p>"; //Works
}
UPDATE:
Another option if you don't know the key is loop through the $results array itself like so with a foreach:
while ($results = mysql_fetch_assoc($raw_results)) {
foreach ($results as $key => $value) {
echo "<span id=\"nevermsg\"><p><strong>$key:</strong> ".$value."</p></span><br/>";
}
}
See the PHP fiddle example of the loop and <span> in action here. For obvious reasons the SQL could not be duplicated in the fiddle.
Why don't you use direct output of HTML?
// some preceding PHP code
?>
<p>
<strong>Never:</strong> <span id="nevermsg"><?=$results['Never'].$results['text'] ?></span>
</p>
It will be more readable and there will be no mess of HTML and PHP quotes, and no need to escape them...
Try this:
<?php
echo "<p><strong>Never:</strong> " . $results['<div id=\"nevermsg\">\'Never\'</div>'] . $results['text'] . "</p><br />";
?>
Your query is fine, it's your HTML which is quite messy. Try replacing this:
echo "<p><strong>Never:</strong> ".$results['Never']."".$results['text']."</p><br />";
With:
?>
<strong>Never:</strong>
<div id="nevermsg"><?= $results['Never']; ?></div>
<br>
<?php

Is it possible to Query a Mysql database from a field selected from dropdown menu populated from a Query in php

Hello i am new to php and i have tried to find a piece of code that i can use to complete the task i need, i currently have a page with a form set out to view the criteria of a course. also i have a dropdown menu which currently holds all the course codes for the modules i have stored in a database. my problem is when i select a course code i wish to populate the fields in my form to show all the information about the course selected. The code i am trying to get to work is as follows:
<?php
session_start();
?>
<? include ("dbcon.php") ?>
<?php
if(!isset($_GET['coursecode'])){
$Var ='%';
}
else
{
if($_GET['coursecode'] == "ALL"){
$Var = '%';
} else {
$Var = $_GET['coursecode'];
}
}
echo "<form action=\"newq4.php\" method=\"GET\">
<table border=0 cellpadding=5 align=left><tr><td><b>Coursecode</b><br>";
$res=mysql_query("SELECT * FROM module GROUP BY mId");
if(mysql_num_rows($res)==0){
echo "there is no data in table..";
} else
{
echo "<select name=\"coursecode\" id=\"coursecode\"><option value=\"ALL\"> ALL </option>";
for($i=0;$i<mysql_num_rows($res);$i++)
{
$row=mysql_fetch_assoc($res);
echo"<option value=$row[coursecode]";
if($Var==$row[coursecode])
echo " selected";
echo ">$row[coursecode]</option>";
}
echo "</select>";
}
echo "</td><td align=\"left\"><input type=\"submit\" value=\"SELECT\" />
</td></tr></table></form><br>";
$query = "SELECT * FROM module WHERE coursecode LIKE '$Var' ";
$result = mysql_query($query) or die("Error: " . mysql_error());
if(mysql_num_rows($result) == 0){
echo("No modules match your currently selected coursecode. Please try another coursecode!");
} ELSE {
Coursecode: echo $row['coursecode'];
Module: echo $row['mName'];
echo $row['mCredits'];
echo $row['TotalContactHours'];
echo $row['mdescription'];
echo $row['Syllabus'];
}
?>
however i can only seem to get the last entry from my database any help to fix this problem or a better way of coding this so it works would be grateful
Thanks
The main error is in your final query, you're not actually fetching anything from the query, so you're just displaying the LAST row you fetched in the first query.
Some tips:
1) Don't use a for() loop to fetch results from a query result. While loops are far more concise:
$result = mysql_query(...) or die(mysql_error());
while($row = mysql_fetch_assoc($result)) {
...
}
2) Add another one of these while loops to your final query, since it's just being executed, but not fetched.
For me i would use some javascript(NOTE: i prefer jQuery)
An easy technique would be to do this(going on the assumption that when creating the drop downs, your record also contains the description):
Apart from creating your dropdown options like this <option value="...">data</option>, you could add some additional attributes like so:
echo '<option value="'.$row['coursecode'].'" data-desc="'.$row['description'].'">.....</option>
Now you have all your drop down options, next is the javascript part
Let's assume you have included jQuery onto your page; and let's also assume that the description of any selected course is to be displayed in a <div> called description like so:
<div id="course-description"> </div>
<!--style it how you wish -->
With your javascript you could then do this:
$(function(){
$("#id-of-course-drop-down").change(function(){
var desc = $(this).children("option").filter("selected").attr("data-des");
//now you have your description text
$("#course-description").html(desc);
//display the description of the course
}
});
Hope this helps you, even a little
Have fun!
NOTE: At least this is more optimal than having to use AJAX to fecch the description on selection of the option :)

Categories