For eg I have 5 records of same user. What is the best way I can sort and display each one of them on a different page using next and previous links.For eg on clicking previous i must get previous record. Then i again click previous i must get previous to that record and so on.
Pick an order and set it with ORDER BY [order], then use LIMIT start, amount to slice the result.
Related
I have a webgallery (made with laravel) and would like to add the possibility to reorder the images... Now, I have thought of several approaches but for every aproach i find that there should be a better way of doing it.
the gallery does not use javascript, so ones changes have been made it needs to be sumbitted and reloaded to reflect the changes
The main difficulties are:
how to store the order in the database? an additional Integer column?
how to add a picture "between" two others?
how to handle it at a frontend level?
So far the best ideas I had are these:
a column with integers, order by clause on this column. Frontend: a move up and a move down button.
problems of this solution: it needs a refresh after each single movement. it needs to identify the previous/next picture and swap the number with that one. To move a single pic from the end of the gallery to the top it takes forever.
a column with integers, automatically prefilled in steps of 100, order by this column + upload time in case of same numbers, Frontend: a textbox where the user can specify the integers for each picture and a submit button.
problems of this solution: does not look very professional. solves all the problems of the previous solution
same as previous solution but with double values to be able to insert pictures without limits.
They all dont seem the real deal.. Any sugestion on how to do it properly is welcome. thanks
I have done that kind of sorting in OpenCart products list (custom backend design)
Sort order was additional column order INT(11) in database
We had 3 input fields: up/down/custom
Where custom was dropdown of all indexes from 1 to max-items.
All inputs does the same:
Take new order value and shift all elements except itself. Up or down shift depends if you move element to front or to back of current position
UPDATE order FROM products SET order = :newOrder WHERE id = :currentItemId
if ($newOrder > $oldOrder)
UPDATE order FROM products SET order + 1 WHERE order >= :newOrder AND id != :currentItemId
else
UPDATE order FROM products SET order - 1 WHERE order <= :newOrder AND id != :currentItemId
Inserting does the same update, just first query becomes INSERT INTO
To get rid of ugly refresh of page on every action we do Ajax requests and re-sorted DOM with jQuery
In JQGrid I want to show group data on one page. That is, if containing all of the items in an order would exceed the list limit, then no items from that order are contained and the list is simply slightly shorter than the limit and shows data to previous order. Is there any way?
Personally I think that this should be done at server and not at client grid. If I understand right , suppose you have 10 items limit per page and the response contain 8 from one group and 2 from the other - if the second group contain really 2 items, which will be deleted, this will be not correct.
In case there are more records from previous page - the previous deleted 2 records should be included into the next page, but according to your server response they will be missed.
I am using sphinxsearch + php for full text search in my app.
I need next prev buttons on my product page. For example I run query "Men shoes" it returns me result of 20 shoes (paging limit is 20), then I click into product and open up a product page, and here I have next and previous products. But next and prev should work to specific to my search query "Men shoes". I store my query in session, and I have ID of product. So how can I find the position of these product and increment or decrement it find products I need.
Is it possible to without query-ing the whole table and looping through to find what I need.
While you can* create a cursor solution, it may be simpler to just use offset.
Page 1 is offset zero, page 2 is offset 20, page 3 is 40 and so on.
where you call setLimits, you can set the offset.
*Basically you need a consistent sort order, and need to store the value of the column, as the 'cursor' for paging, and use it for filtering the next page. If sorting by weight, you store the weight of the last result on the page. Then for the next page, you only want weights bedlow that one. (with weights is even more complicated as there can be many results with the same weight, so you need to do multi-column sorting)
I have searched everywhere but could not get anything. The scenario is that when I run a select statement from MySQL/PHP, I want to use Next & Previous buttons to navigate backwards and forward through the results.
Does anyone know how I can accomplish this?
Here's how I run the query: select everything from members where hair = black;
This returns 8 results, and I have a page like so details.php?id=3 which takes id and display the details.
I want to be able to keep clicking the next button and move to another id from the result.
How do I accomplish this?
Thank you for your assistance.
If you mean to display 1 product details per page with Next buttons, then
1) Get the total rows from table
2) Find total number of pages like
$totalPages = $totalRows; //since 1 record per page
3) Loop thru $totalPages value to generate next links
4) Get the id of product from page url $_GET
5) Query sql using te product id obtained frm GET
Well thats the basics, hope your get it
Assuming you have all ids in the $allIds var, try something like this:
<?php
$id = (int) $_GET['id'];
$key = array_search($id, $allIds);
$nextId = $allIds[$key+1];
?>
Well, you have 2 different scopes here to address, first, when you query you are in PHP/Server side mode. PHP gets some data, processes it, shows some of it to the knowledge i have of your problem and then sends it to the browser.
Next, you have the client scope, where the client has the HTML rendered to his screen and has the possibility to click NEXT and PREVIOUS. When he does that, he issues a request to the server to get the NEXT or PREVIOUS record based on the current one.
You have 2 scenarios to work this problem out:
1) Load the whole data into memory and scan it to find your current position, see if there is a NEXT and PREVIOUS element and respond to the request of the user. If the user asked for the NEXT, easy, just move one more record. If the user asked for PREVIOUS item, then when scanning using a WHILE or FOR/FOREACH, always keep in memory the "lastitem" you saw, you can use this "lastitem" as your PREVIOUS item.
2) In the event you have many (i mean like more than 1000) items, you need to use a little subquery magic and work this out using SQL.
select everything from members where hair = black AND id = XYZ ORDER BY id LIMIT 2;
This will return you the CURRENT AND NEXT elements. Then call the same query again but this time, order it DESC so that your 2 items are the CURRENT AND PREVIOUS.
select everything from members where hair = black AND id = XYZ ORDER BY id DESC LIMIT 2;
Note that you can order this the way you want, the goal is to get a static result, something that always gets out the same way so that you can reverse it and get the items around the selected one.
I hope this helps you
I'm currently working on a site that will display a list of online shops,
Each shop will be stored on my database and I'll be using PHP to select and display them.
But since those shops will pay me, I want to let each shop to be on the top of the list sometimes,
(for example if the shop name starts with a "Z", they will probably complain for being on the bottom of the list all the time, so I want to keep it fair).
So I thought about letting each letter be on the top of the list for an hour, but i have no idea how to do that..
Is that even possible?
Thanks in advance!
I'd show a separate box and call it "today's pick" or something with just one shop in it. That way you can push the shops starting with "Z" to the top once in a while and at the same time keep the user experience of a list of shops which is sorted normally.
Then use the database to save which shop has been in the "today's pick"-box how many times to get them all up there equally.
There's no sane way (that I'm aware of) to handle this directly in SQL without adding a "priority" field to your schema (although it's possible, it would be convoluted at best). That said, here are two suggestions:
Modify your schema
Simply add a "priority" field to the relevant schema and sort by priority, name (or whatever the default is). You will of course need to reset the priority field every hour, but this is a fairly trivial task.
Handle it in PHP
Carry out the query as per usual.
Grab all the results into an array.
Re-prioritise as required based on the current hour. (You'll need to array_splice the item(s) you want to bump out of the array and then array_unshift them to the top.)
Output based on the array.
This will of course become more convoluted/less efficient if you need to handle pagination, but the basic idea is the same.
A nice solution would be to add another column to the database with the shop names, and call it something like "last_shown" then when you show this shop, update the column with a timestamp, and each select do something like:
"SELECT name,link FROM shops ORDER BY last_shown DESC"
then in php you could check
<?php
if($row['last_shown']+3600 > now()){
//run select but in ASC order
//update the new row's column to the current timestamp
}
?>
that way it will only update once an hour, but otherwise it will keep selecting the shop at the top of the list for the hour
sorry it's a bit of a mess i just typed this out quickly at work
You can add
1) a extra column as shown_times in schema
2) order by shown_times asc
3) & as a shop is shown you would +1
or
Another solution :
You can even use ORDER BY RAND()