I have a regex to reformat a date from "dd/mm/yyyy HH:ii:ss" to YYYY-MM-DD HH:II:SS which is fine, but I would also use the same for validating date only (when no hours are provided).
Maybe there is a way to give default value to the replacement but I didn't found it.
$regex = '#^(\d{2})/(\d{2})/(\d{4})(?: (\d{2}):(\d{2})(?::(\d{2}))?)?$#';
$replace = '$3-$2-$1 $4:$5:00';
$str = '07/11/2013 20:30';
$val = preg_replace($regex, $replace, $str);
echo $val; // "2013-11-07 20:30:00"
$str = '07/11/2013';
$val = preg_replace($regex, $replace, $str);
echo $val; // "2013-11-07 ::00"
You can use preg_replace_callback and provide a custom callback method to perform the replacement. Inside you're callback, you can apply your default values:
$regex = '#^(\d{2})/(\d{2})/(\d{4})(?: (\d{2}):(\d{2})(?::(\d{2}))?)?$#';
$replace = function ($m) {
if (!$m[4]) $m[4] = '00';
if (!$m[5]) $m[5] = '00';
return "$m[3]-$m[2]-$m[1] $m[4]:$m[5]:00";
};
$str = '07/11/2013 20:30';
$val = preg_replace_callback($regex, $replace, $str);
echo $val; // "2013-11-07 20:30:00"
$str = '07/11/2013';
$val = preg_replace_callback($regex, $replace, $str);
echo $val; // "2013-11-07 00:00:00"
To validate date and time try this:
$regex = '(\d{2})/(\d{2})/(\d{4}) (\d{2}):(\d{2}):(\d{2})';
Related
$cont=htmlspecialchars(file_get_contents("https://myanimelist.net/anime/30276/One_Punch_Man"));
function getBetween($string, $start = "", $end = ""){
if (strpos($string, $start)) { // required if $start not exist in $string
$startCharCount = strpos($string, $start) + strlen($start);
$firstSubStr = substr($string, $startCharCount, strlen($string));
$endCharCount = strpos($firstSubStr, $end);
if ($endCharCount == 0) {
$endCharCount = strlen($firstSubStr);
}
return substr($firstSubStr, 0, $endCharCount);
} else {
return '';
}
}
$name=getBetween($cont,'title',' - MyAnimeList.net');
//$name=preg_replace('/[^a-zA-Z0-9 \p{L}]/m', '', $name);
preg_replace('/(*UTF8)[\>\<]/m', '', $name);
trim($name," ");
//$name=str_replace("gt", "", $name);
echo $name;
i want to find the text between title tags. how to do this?
for example in this page title contains 'One Punch Man - MyAnimeList.net' i want to get that
Just use string replace function:
$string = '<BoomBox>';
$string = str_replace('<', '', $string);
$string = str_replace('>', '', $string);
echo $string; // output: Boombox
http://php.net/manual/en/function.str-replace.php
You edited your answer, and we can now see you are dealing with XML/HTML. It's always better to work with the DOM classes. Never use regex! There is a famous Stack Overflow post explaining why never to parse html with regex. Try this solution instead:
<?php
$dom = new DOMDocument();
$dom->loadHTML('<title>BoomBox</title>');
echo $dom->getElementsByTagName('title')->item(0)->textContent;
http://php.net/manual/en/class.domdocument.php
http://php.net/manual/en/class.domnode.php
See it working here https://3v4l.org/EjPQd
You can use preg_replace();, or strip_tags();.
Example preg_replace();:
$str = '> One Punch Man';
$new = preg_replace('/[^a-zA-Z0-9 \p{L}]/m', '', $str);
echo $new;
Output: One Punch Man
Above example will only allow a-z, A-Z and 0-9. You can expand this.
Example strip_tags();:
$str = '<title> BoomBox </title>';
$another = strip_tags($str);
echo $another;
Output: BoomBox
Documentation:
http://php.net/manual/en/function.preg-replace.php // preg_replace();
http://php.net/manual/en/function.strip-tags.php // strip_tags();
You can also use a single call to str_replace with the ['<','>'] as the search argument:
$string = '<BoomBox>';
echo str_replace(['<', '>'], '', $string) . PHP_EOL;
// => Boombox
Or, you may use a regex with preg_replace (especially, if you plan on adding more restrictions for in-context matching to it):
echo preg_replace('~[<>]~', '', $string);
// => Boombox
See the PHP demo.
$string = 'Hello [user=1]';
$bbc = array('/\[user=(.*?)\]/is');
$replace = array(user('textlink',$1));
$s = preg_replace($bbc , $replace, $string);
echo $s
How do I change $1 in preg_replace with a function?
If I understand you correctly, you want to execute user() function on each match? As mentioned in comments, use the preg_replace_callback() function.
<?php
$string = 'Hello [user=1]';
$s = preg_replace_callback(
'/\[user=(.*?)\]/is',
function($m) {return user('textlink', $m[1]);},
$string
);
echo $s;
You may use a preg_replace_callback_array:
$string = 'Hello [user=1]';
$bbc = array(
'/\[user=(.*?)\]/is' => function ($m) {
return user('textlink',$m[1]);
});
$s = preg_replace_callback_array($bbc, $string);
echo $s;
See PHP demo.
You may add up the patterns and callbacks to $bbc.
I am using regular expression for getting multiple patterns from a given string.
Here, I will explain you clearly.
$string = "about us";
$newtag = preg_replace("/ /", "_", $string);
print_r($newtag);
The above is my code.
Here, i am finding the space in a word and replacing the space with the special character what ever i need, right??
Now, I need a regular expression that gives me patterns like
about_us, about-us, aboutus as output if i give about us as input.
Is this possible to do.
Please help me in that.
Thanks in advance!
And finally, my answer is
$string = "contact_us";
$a = array('-','_',' ');
foreach($a as $b){
if(strpos($string,$b)){
$separators = array('-','_','',' ');
$outputs = array();
foreach ($separators as $sep) {
$outputs[] = preg_replace("/".$b."/", $sep, $string);
}
print_r($outputs);
}
}
exit;
You need to do a loop to handle multiple possible outputs :
$separators = array('-','_','');
$string = "about us";
$outputs = array();
foreach ($separators as $sep) {
$outputs[] = preg_replace("/ /", $sep, $string);
}
print_r($outputs);
You can try without regex:
$string = 'about us';
$specialChar = '-'; // or any other
$newtag = implode($specialChar, explode(' ', $string));
If you put special characters into an array:
$specialChars = array('_', '-', '');
$newtags = array();
foreach ($specialChars as $specialChar) {
$newtags[] = implode($specialChar, explode(' ', $string));
}
Also you can use just str_replace()
foreach ($specialChars as $specialChar) {
$newtags[] = str_replace(' ', $specialChar, $string);
}
Not knowing exactly what you want to do I expect that you might want to replace any occurrence of a non-word (1 or more times) with a single dash.
e.g.
preg_replace('/\W+/', '-', $string);
If you just want to replace the space, use \s
<?php
$string = "about us";
$replacewith = "_";
$newtag = preg_replace("/\s/", $replacewith, $string);
print_r($newtag);
?>
I am not sure that regexes are the good tool for that. However you can simply define this kind of function:
function rep($str) {
return array( strtr($str, ' ', '_'),
strtr($str, ' ', '-'),
str_replace(' ', '', $str) );
}
$result = rep('about us');
print_r($result);
Matches any character that is not a word character
$string = "about us";
$newtag = preg_replace("/(\W)/g", "_", $string);
print_r($newtag);
in case its just that... you would get problems if it's a longer string :)
How do i create a function replaceMe() in php that would turn:
$str = 'This is a very long string';
into:
'This is a very long STRING?'
can someone help me?
You apparently want to do a regular expression substitution, anchored at the end of the line. Use preg_replace:
$str = 'This is a very long string';
# This is a very long LINE
echo preg_replace("/string$/", "LINE", $str);
For a general case, you can provide a callback instead of a replacement string, and simply uppercase the matched substring with preg_replace_callback:
$str = 'This is a very long blah';
function word_to_upper($match) {
return strtoupper($match[1]);
}
# This is a very long BLAH
echo preg_replace_callback("/(\w+)$/", "word_to_upper", $str);
If you're using PHP 5.4 or greater, you can supply the callback as an anonymous function:
echo preg_replace_callback("/(\w+)$/", function ($match) {
return strtoupper($match[1])
}, $str);
This works:
$str = 'This is a very long string';
echo $str."<br/>";
function replaceMe($str = "")
{
$words = explode(" ",$str);
$totalwords = count($words)-1;
$lastword = $words[$totalwords];
$words[$totalwords] = strtoupper($lastword);
$str = implode(" ",$words);
return $str;
}
echo replaceMe($str);
?>
Output:
This is a very long string
This is a very long STRING
$str = 'This is a very long string.';
function lastWordUpper($str){
$temp = strrev($str);
$last = explode(" ", $temp, 2);
return strrev(strtoupper($last[0]). ' ' .$last[1]) ;
}
echo lastWordUpper($str);
I have a doubt again on RegEx in Php.
Assume that I have a line like this
716/52 ; 250/491.1; 356/398; 382/144
I want the output to be
Replace all semi-colon with comma. I think I can do this using
$myline= str_replace(";", ",", $myline);
Interchange the numbers and replace '/' with a comma. That is, 716/52 will become 52,716. This is where I get stuck.
So, the output should be
52,716 , 491.1,250, 398,356, 144,382
I know that using sed, I can achieve it as
1,$s/^classcode:[\t ]\+\([0-9]\+\)\/\([0-9]\+\)/classcode: \2\,\1/
But, how do I do it using preg_match in php?
$str = '716/52 ; 250/491.1; 356/398; 382/144';
$str = str_replace(';', ',', $str);
$res = preg_replace_callback('~[\d.]+/[\d.]+~', 'reverse', $str);
function reverse($matches)
{
$parts = explode('/', $matches[0]);
return $parts[1] . ',' . $parts[0];
}
var_dump($res);
And working sample: http://ideone.com/BeS9j
UPD: PHP 5.3 version with anonymous functions
$str = '716/52 ; 250/491.1; 356/398; 382/144';
$str = str_replace(';', ',', $str);
$res = preg_replace_callback('~[\d.]+/[\d.]+~', function ($matches) {
$parts = explode('/', $matches[0]);
return $parts[1] . ',' . $parts[0];
}, $str);
var_dump($res);
As an alternative to Regexen you could try this:
echo join(', ', array_map(
function ($s) { return join(',', array_reverse(explode('/', trim($s)))); },
explode(';', $string)));
$str = '716/52 ; 250/491.1; 356/398; 382/144';
$str = preg_replace('(\d+(?:\.\d+)?)\/(\d+(?:\.\d+)?)', '$2,$1', $str);
$str = str_replace(';', ',', $str);
Uses two capture groups, replacing them in reverse order. See it here.