PHP Button to carry out query and refresh page - php

Question

I have two buttons on my page (yes and no).
I have a function on another page 'choice.php' that updates a database based on this decision. This function takes 'yes' or 'no' as inputs. Therefore I would like each button to run the choice.php page, with 'yes' or 'no' depending on button pressed, and then refresh the current page. Currently I have tried (for 'yes'):
echo "<form></br>";
echo "<input type='button' value = 'yes' Method ='POST' ACTION = 'choice.php'>";
echo "</form>";
But I am unsure where to go from here. The choice.php page has:
function choice('yes'/'no');

Answer 1

The params should be comma separated, but you don't really need params when taking from superglobal array. However, you only need to call the function if 'yes' for example:
<form action="choice.php" method="post">
<input type="submit" name="choice" value="yes" />
<input type="submit" name="choice" value="no" /> <!-- You'd better use radio buttons -->
</form>
<?php
function choice() {
if ($db->query("UPDATE ..... ;")) {
return true;
}
return false;
}
if (isset($_POST['choice']) && $_POST['choice'] == 'yes') {
choice();
}
else {
echo 'no';
}
?>
Ofcourse you can have multiple if's, but I don't think it will help you enough:
if (isset($_POST['choice']) && $_POST['choice'] == 'yes') {
//something;
}
elseif (isset($_POST['choice']) && $_POST['choice'] == 'no') {
//something else;
}
elseif (isset($_POST['choice']) && $_POST['choice'] == 'maybe') {
//something else;
}
If you want the function to update db with the value from the user, you could use something like this:
function choice() {
$choices = array('yes', 'no', 'maybe', 'dunno'); //predefined choices
if (in_array($_POST['choice'], $choices)) { //checks if the user input is one of the predefined choices (yes, no, maybe or dunno)
if($db->query("UPDATE table1 SET userchoice = '{$_POST['choice']}' WHERE user_id = '{$_SESSION['id']}';")) {
return true;
}
}
return false;
}
if (isset($_POST['choice'])) choice(); //so here you don't need (not necessary, but you can) to check if the value is the one you want. If it's set, you call choice(), then the function checks if it's in the array of predefined choices, so if it is - it will update, if it's not it will return false

Answer 2

One way is to use header on your choice.php after your database operations finishes.
header('Location: *where your form page is*');
Another way is to do an ajax post using javascript

Answer 3

Suppose you have something like this:
<form method='POST' action='choice.php'>
<tr>
<td><input type="submit" name="answer" value="yes"></td>
<td><input type="submit" name="answer" value="no"></td>
</tr>
</form>
and in the PHP file you can use the POST method to check for the answer, whether it was yes or no
if($_POST['answer'] == 'yes') {
//do something
}
if($_POST['answer'] == 'no') {
//do something else
}