I have a CakePHP project having 3 plugins: plugin1, plugin2, plugin3. These are simple plugins, I've just tried to split up my project into 3 smaller & easier parts.
Plugin1 has to use a model "Model1", where there is no db table for this table. And Cake is showing error :
"Missing Database Table
Error: Table models1 for model Model1 was not found in datasource default."
Here, table-name and Model-name are in correct convention. I don't want to create a table for this, since I don't need it. What to do now ?
You can set that model is without table by setting $useTable in the model (from CakeBook)
class Example extends AppModel {
public $useTable = false; // This model does not use a database table
}
Related
I have 3 tables in a database
Transaction {'id','bill_id','remark'}
Bills {'id','third_party','amount'}
ThirdParty {'id','company_name',remark}
The 'transaction' table has column bill_id coming from 'Bills' and Bills table has 'third_party' column which connected to ThirdParty table column -> 'id'
So here I am trying to fetch company_name using laravel eloquent relation
My Transaction model:
public function Bills()
{
return $this->hasOne('App\Bills','id','bill_id');
}
Bills:
public function third_party()
{
return $this->belongsTo('App\ThirdParty','third_party','id');
}
I am getting null value for company_name
Here is the query i am using
Transaction::with('Bills.third_party')->get();
And i have corrected in question (third_party_name) to company_name column name i wrote here was my old join query name which is visible in screenshot, basically i am trying to fetch company name.
Are you able to show all of your code? How does company_name get set to third_party_name?
You could probably also gain a lot by sticking to the laravel "conventions" or "suggested naming", this will give you a lot of functionality for free, and make your code easier to read, write and debug.
eg. Your relationship method names (Bills(), third_party()), but more importantly if you name your table fields in the "laravel way", you will get easier eloquent relationships as there will be no need to define the foreign keys etc.
I would be setting this up similar to:
Transaction {'id','bill_id','remark'}
Bills {'id','third_party_id','amount'} <- note the third_party_id
ThirdParty {'id','company_name',remark}
class Transaction extends Model
{
public function Bills()
{
return $this->hasOne('App\Bills');
}
}
class Bills extends Model
{
public function ThirdParty()
{
return $this->belongsTo('App\ThirdParty);
}
}
You should also define the inverse relationships.
It would be very beneficial to see the full code to see where the issue is.
Details
I have 3 tables :
catalog_downloads
export_frequencies
export_frequencies_catalog_downloads (Pivot Table)
Diagram
I am not sure if I set the relation between them correctly.
Please correct me if I am wrong.
Here is what I did
In CatalogDownload.php
public function export_frequencies(){
return $this->belongsToMany('ExportFrequency','export_frequencies_catalog_downloads','export_frequency_id','catalog_download_id');
}
In ExportFrequency.php
public function catalog_downloads(){
return $this->belongsToMany('CatalogDownload','export_frequencies_catalog_downloads','export_frequency_id','catalog_download_id');
}
Questions
According to my diagram - Did I assign the relationship correctly ?
I hope I didn't mix up between hasMany and belongsTo
Will I need a class or a model for a Pivot Table ?
Thanks
Since export_frequencies is in the CatalogDownload model you have to invert the ID's because the parameters of belongsToMany are as follows:
1. Name of the referenced (target) Model (ExportFrequency)
2. Name of the Pivot table
3. Name of the id colum of the referencing (local) Model (CatalogDownload in this case)
4. Name of the id colum of the referenced (target) Model (ExportFrequency in this case)
what leads to this function:
public function export_frequencies(){
return $this->belongsToMany('ExportFrequency','export_frequencies_catalog_downloads','export_frequency_id','catalog_download_id');
}
The other function was correct.
If you had some data in your pivot table, for instance a colum with the name someCounter then you will have to tell the relation to load that column when creating the pivot object like this:
public function export_frequencies(){
return $this->belongsToMany('ExportFrequency','export_frequencies_catalog_downloads','export_frequency_id','catalog_download_id')->withPivot('someCounter');
}
That will load the column and make it avalible like this:
$catalogDownload->export_frequencies()->first()->pivot->someCounter;
You will need a separate Pivot Model if you need to do some special handling for the fields or if that pivot itself has a relation of its own but then you might consider using a full blown model instead of a pure Pivot Model.
As an added note to the accepted answer, you are able to set up your many to many relationships without referencing the pivot table and the relevant id's as long as you follow a specific convention.
You can name your pivot table using singular references to the related tables, like 'catalog_download_export_frequency'. Notice the alphabetic order of the singular references.
Then you can simply do:
// CatalogDownload Model
public function exportFrequencies()
{
return $this->belongsToMany('ExportFrequency');
}
// ExportFrequency Model
public function catalogDownloads()
{
return $this->belongsToMany('CatalogDownload');
}
This will then allow you to run queries using the query builder or Eloquent like:
$catalogDownload->exportFrequencies()->get(); // Get all export frequencies for a specific CatalogDownload.
Or
$this->catalogDownload->with('exportFrequencies')->find($id); // Using eager loading and dependency injection, when CatalogDownload is assigned to $this->catalogDownload
Hope this helps!
I'm starting to learn Laravel. I've run through the example instructions from the site successfully and now I'm trying a second run through and I'm running into an issue.
I'm trying to connect to a database called zipCodes and has one table called zipCodeDetails.
In my Laravel project I have a model containing the following code:
<?php
class ZipCodeDetails extends Eloquent {}
And in my routes.php file I have the following code:
Route::get('zipCodes', function (){
$zipCodes = ZipCodeDetails::all();
return View::make('zipCodes')->with('zipCodes', $zipCodes);
});
The error I'm running into is when I try to load the URL:
http://localhost:8888/zipCodes
In my browser I'm getting the error code:
SQLSTATE[42S02]: Base table or view not found: 1146 Table 'zipcodes.zip_code_details' doesn't exist (SQL: select * from `zip_code_details`)
There's nothing written in my code where I define the database zipCodes as zipcodes or the table zipCodesDetails as zip_code_details. Something in laravel is changing the database and table names.
Does anyone know why this is happening and how I can prevent it? I don't want to just rename the database or table names because while that may get me by in testing it's not a viable solution in practice.
Thanks!
This is the behaviour that uses if no table is being explicitly defined. In your ZipCodeDetails class, you can set the table name that this model will be using.
class ZipCodeDetails extends Eloquent
{
protected $table = 'zipCodesDetails';
}
how can I access any table from database in my model?
For example, I have Indexcontroller and code inside it:
$results = $this->Index->query("SELECT COUNT(*) FROM my_own_table");
Error: Database table indices for model Index was not found.
So, as I understand, I can access only table with naming related to model/controller name. But what to do if I can't modify the table naming and I want to access it's data?
You're not limited to using a model that's directly associated with your controller (this is just default behaviour); you can use any model.
To achieve what you want, create a new model for this table, eg. MyOwnTable, and in your controller, you can add this property to the class:
public $uses = array('Index', 'MyOwnTable');
Now you can access MyOwnTable using CakePHP's built in ActiveRecord functionality:
$results = $this->MyOwnTable->find('count');
If you have other tables you want to access, simply create models for those and add them to the $uses property. (You can also use $this->loadModel('Model') inside the action if you prefer).
If you have a table name that isn't very readable (eg. my_tb_own_1_x or some such), you can call the model class something human readable (eg. MyTable), and add the $useTable property to the model:
public $useTable = 'my_tb_own_1_x';
/* and change the default primary key if you have an unusual one */
public $primaryKey = 'my_tb_own_1_x_idx_pk';
See the CakePHP manual for more info on how to change default model and controller behaviour:
1.3 - Model Attributes
2.0 - Model Attributes
1.3 - Controller Attributes
2.0 - Controller Attributes
Nope. You can access different tables. However, CakePHP stumbles over the fact that the table that is associated by default to the Index model doesn't exist.
In other words, the model Index expects a table 'indices' to exist (and an error is thrown when it doesn't). You can do one of two things:
Create a table indices
Add the following to your Index model: var $useTable = false;
If you have any use for an indices table I'd go with option 1. If you're not going to use the indices table, go with option 2.
If you go with either step 1 or 2, your example should start working.
I am trying to remove a table from CakePHP. All the tables were created with the cake bake function and I have removed the table from all the models. But when I remove the table from the database I get an error message:
Error: Database table channels_offers for model ChannelsOffer was not found.
Notice: If you want to customize this error message, create app/views/errors/missing_table.ctp
So how do I remove a table that was originally baked in?
Well, it appears that you still have a model called ChannelsOffer. You would need to add a property to your ChannelsOffer model. Here's an example
class ChannelsOffer extends AppModel {
// this tells the model not to use a table, alternatively you could supply your
// own table name here.
public $useTable = false;