output all images from a directory - php - php

Question

I'm trying via php to pull all images from a directory and print them as < li < img src="url.. etc...
After doing a bit of research on SO, i found that the glob function should serve this purpose well, but i can't get it to work unfortunately. I think the problem is with me trying to echo the ID in the path? but being a bit of a newbie i can't seem to see my error.
<?
$dirname="images/companies/";
echo '$current['id']';
$images = glob($dirname."*.jpg");
foreach($images as $image) {
echo '<img src="'.$image.'" /><br />';
}
?>

Answer 1

You have no dir separator between $dirname."*.jpg", so unless your $current['id'] ends in a slash, glob won't work.
Try replacing $dirname."*.jpg" with $dirname."/*.jpg".
Also: your $dirname is relative to the current PHP working directory. To make sure that this works regardless of where PHP was called from, use $dirname=dirname(__FILE__)."/images/companies/".$current['id']

Answer 2

Make sure thar $dirname is relative to the current path or use absolute paths, e.g.:
$dirname = $_SERVER['DOCUMENT_ROOT']."/../some/path/images/companies/";
Make sure that your path is not missing a slash, it would if $current['id'] had no trailing slash, that you had to write:
$images = glob($dirname."/*.jpg");

Answer 3

Thaths the problem when oyu just steal code, but dont understand what it does.
If you want to scan a directory, you can use scandir(), which returns an array containing all the files it found, e.g.
$files = scandir("your/path/");
To show them, you simply use print_r(), its ugly and not formatted, but it does its purpose, if you want more, use echo and html/css:
echo "<pre>";
print_r($files);
echo "</pre>";
No finished code, think a bit for yourself.