Count the number of occurences of a particular value inside loop - php

Question

In array count all true where category is 1 after counting the category will move to 2 thn count all true and so on?
Array generated:
foreach($_POST as $key => $data)
{
$a = explode("_", $key);
$f = array(
'category' => $a[1],
'answer' => $data
);
$f_data[] = $f;
}
FROM
Array
(
[0] => Array
(
)
[1] => Array
(
[category] => 1
[answer] => true
)
[2] => Array
(
[category] => 1
[answer] => true
)
[3] => Array
(
[category] => 1
[answer] => true
)
[4] => Array
(
[category] => 1
[answer] => false
)
[5] => Array
(
[category] => 1
[answer] => false
)
[6] => Array
(
[category] => 1
[answer] => true
)
[7] => Array
(
[category] => 1
[answer] => true
)
[8] => Array
(
[category] => 2
[answer] => true
)
[9] => Array
(
[category] => 2
[answer] => true
)
[10] => Array
(
[category] => 2
[answer] => true
)
[11] => Array
(
[category] => 2
[answer] => false
)
[12] => Array
(
[category] => 2
[answer] => true
)
[13] => Array
(
[category] => 2
[answer] => true
)
)
To
array (
category: 1,
count: 5
),
array(
category: 2,
count: 5
)

Answer 1

This is the solution :
$return = array();
foreach($cont as $item) {
if($item['answer'] == 'true') {
$verify = false;
foreach($return as $key => $value) {
if($value['category'] == $item['category']) {
$return[$key]['count']++;
$verify = true;
break;
}
}
if(!$verify)
$return[] = array('category' => $item['category'], 'count' => 1);
}
}
And this is better solution...
$return = array();
foreach($cont as $item) {
if($item['answer'] == 'true') {
if(array_key_exists($item['category'], $return))
$return[$item['category']]++;
else
$return[$item['category']] = 1;
}
}

Answer 2

Untested, but I believe this is what you are after (pending any minor mistakes):
foreach($_POST as $key => $data)
{
$a = explode("_", $key);
$f[$a[1]]['category'] = $a[1];
if ($data == "true") {
$f[$a[1]]['answer']++;
}
}