MySQL/PHP: Insert form array into database? - php

I am a PHP newbie having a problem inserting an array from a form into the database using foreach statement.
I am trying to create a form that accepts Score, Grade and Comment for each subject. However,only the last subject gets inserted into the database. The list of subjects is loaded from previously registered subjects (I have no problem with that). My problem is getting all the subjects to save back to database.
This is the form i use:
<legend>ENTER RESULTS:</legend>
<input type="hidden" name="results[]" value= "<?php foreach ($subjects as $subject):?>
<ul>
<li> <input type="text" name="subject_name" size="10" value ="<?php htmlout($subject['subject_name']); ?>"/>
</label>
<label for="subject_score">SCORE:</label>
<input type="text" name="subject_score" size="5" value = "<?php
htmlout($subject_score);?>"/> <label for="subject_score">GRADE:</label>
<input type="text" name="subject_grade" size="5" value = "<?php
htmlout($subject_grade);?>"/><label for="subject_grade">COMMENT:</label>
<input type="text" name="subject_comment" size="30" value = "<?php
htmlout($subject_comment);?>"/> </div></li>
<?php endforeach; ?>
<input type="hidden" name="student_id" value="<?php
htmlout($student_id); ?>
</fieldset>
This is the php code i use:
if (isset($_GET['result']))
{
try
{
$sql = 'INSERT INTO results SET
student_id = :student_id,
subject_name = :subject_name,
subject_grade = :subject_score,
subject_grade = :subject_grade,
subject_comment = :subject_comment';
$s = $pdo->prepare($sql);
foreach ($_POST['results'] as $result)
{
$s->bindValue(':student_id',$_POST['student_id']);
$s->bindValue(':subject_name', $_POST['subject_name']);
$s->bindValue(':subject_score', $_POST['subject_score']);
$s->bindValue(':subject_grade', $_POST['subject_grade']);
$s->bindValue(':subject_comment', $_POST['subject_comment']);
$s->execute();
}
}
catch (PDOException $e)
{
$error = 'Could not Register the Student for the Subjects, Please try again'.$e->GetMessage();
include 'error.html.php';
exit();
}
echo 'Success';

you can use form element in array like subject_score[]
your form should be like
foreach
<input type="text" name="subject_name[]" size="10" value ="<?php htmlout($subject['subject_name']); ?>"/>
</label>
<label for="subject_score">SCORE:</label>
<input type="text" name="subject_score[]" size="5" value = "<?php
htmlout($subject_score);?>"/> <label for="subject_score">GRADE:</label>
<input type="text" name="subject_grade[]" size="5" value = "<?php
htmlout($subject_grade);?>"/><label for="subject_grade">COMMENT:</label>
<input type="text" name="subject_comment[]" size="30" value = "<?php
htmlout($subject_comment);?>"/> </div></li>
endforeach
then you can collect those value like below
foreach($_POST['subject_name'] as $key=>$val){
//val will hold subject name
}

Related

PHP- how to get values from checked checkboxes and corresponding textboxes

I want to get three values separated by a comma when the form is submitted. The value from the checkbox, textbox 1 and textbox 2.
This is my code that retrieves values from mysql database and generates checkboxes and two corresponding textboxes.
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<?php
$query = "SELECT * FROM subject";
$data = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($data)){
$s = $row['sub'];
echo $s;
?>
<input type="checkbox" name="req_sub[]" value= "<?php echo $s; ?>" />
<input type="text" name="<?php echo $s; ?>" placeholder="Total Number" />
<input type="text" name="<?php echo $s; ?>" placeholder="Pass Number" />
<?php
}
?>
<input type="submit" name="submit" value="Add">
</form>
Suppose the user checks the first three boxes , and enters the values like in this picture -
when I click add, I get the values --
Physics
Math
Chemistry
by using the code below:
<?php
if (isset($_POST['submit'])) {
if (!empty($_POST['req_sub'])) {
foreach ($_POST['req_sub'] as $selected) {
echo $selected."</br>";
}
}
}
?>
but how do I get the values like this-
Physics,40,30
Math,40,30
Chemistry,30,25
I want this output in a variable so that I can store it in my database table.
I have spent several hours behind this in last few days. Please help me with this one.
you need to assign unique names to the <input type="text" ... /> so you can recieve its values in the PHP.
Second, you need to write PHP code, that's concatenating those values.
For example, your HTML code might be:
<input type="checkbox" name="req_sub[]" value= "<?php echo $s; ?>" />
<input type="text" name="total[<?php echo $s; ?>]" placeholder="Total Number" />
<input type="text" name="pass[<?php echo $s; ?>]" placeholder="Pass Number" />
and your PHP code might be:
if (isset($_POST['submit'])) {
if (!empty($_POST['req_sub'])) {
foreach ($_POST['req_sub'] as $selected) {
$total = $_POST['total'][$selected];
$pass = $_POST['pass'][$selected];
$var = $selected . ',' . $total . ',' . $pass;
echo $var . '<br />';
}
}
}

PHP MYSQL Next AND Previous row

Basically I have a table with data, and I have a form with boxes and stuff, and what I am trying to do is when the I click on the next or previous button, it will take the next record from the database. I can do the first and the last record, but I cant manage to figure the in between. this what I have.
$sql="SELECT * FROM Emails where ID > 1 ORDER BY UserEmail LIMIT 1";
if ($result=mysqli_query($connection,$sql))
{
// Return the number of rows in result set
$rowcount=mysqli_num_rows($result);
while( $row = mysqli_fetch_array( $result ) )
{
$Email_Field = $row['UserEmail']; //primary key
$Name_Field = $row['UserName'];
$UserTel = $row['UserTel'];
$Drop_Down = $row['Drop_down'];
$MessageType = $row['MessageType'];
$Comments = $row['Comments'];
$SubjectOther = $row['SubjectOther'];
$Check = $row['Request'];
}
<form method="POST" action="Controller_leads.php">
<p><strong>What kind of comment would you like to send?</strong></p>
<input type="radio" <?php if ($MessageType == "Complaint") echo "checked"; ?> name="MessageType" value="Complaint">Complaint
<input type="radio" <?php if ($MessageType == "Problem") echo "checked"; ?> name="MessageType" value="Problem">Problem
<input type="radio" <?php if ($MessageType == "Suggestion") echo "checked"; ?> name="MessageType" value="Suggestion">Suggestion
<br>
<p><strong>What about us do you want to comment on?</strong></p>
<select name="Drop_Down" size="1">
<option value ="Web Site" <?php if ($Drop_Down == "Web Site") echo selected ?>>Web Site</option>
<option value ="Office Hours" <?php if ($Drop_Down == "Office hours") echo selected ?>>Office Hours</option>
<option value ="Pamphlet" <?php if ($Drop_Down == "Pamphlet") echo selected ?>>Pamphlet</option>
</select>
Other: <input type="text" size="26" maxlength="256" name="SubjectOther" value="<?php echo $SubjectOther ?>">
<p><strong>Enter your comments in the space provided below:</strong></p>
<textarea name="Comments" rows="5" cols="42"><?php echo $Comments;?></textarea><br><br>
<strong>Tell us how to get in touch with you:</strong><br><br>
<table>
<tr><td width="45"> Name </td> <td><input type="text" size="35" maxlength="256" name="UserName" value="<?php echo $Name_Field ?> "></td></tr>
<tr><td width="45"> E-mail </td> <td><input type="text" size="35" maxlength="256" name="UserEmail" value="<?php echo $Email_Field ?>"></td></tr>
<tr><td width="45"> Telephone</td> <td><input type="text" size="35" maxlength="256" name="UserTel" value="<?php echo $UserTel ?>"></td></tr>
</table>
<br>
<input type="checkbox" name="Check" <?php if ($Check == "Contact Requested") echo checked; ?> value="Contact Requested">Please contact me as soon as possible regarding this matter
<br><br>
<input type="submit" value="First" name="first">
<input type="submit" value="Next" name="next">
<input type="submit" value="Previous" name="previous">
<input type="submit" value="Last" name="last"> code here
Try adding an offset to the query. On each next click add one to $offset, on each previous, subtract one from offset. Then, include offset in the query like this:
# get the current offset
# initial value
$offset = 1;
# if we have an offset from a previous or next click, use that
if (isset($_POST['offset'])) {
# validate this input to protect against sql injection
if (is_int($_POST['offset'])) {
$offset = $_POST['offset'];
}
# now that we have our current value, see if we need to get the next or previous
if ($_POST['submit']=="Next") {
# next, add one offset
$offset++;
} else if ($_POST['submit']=="Previous") {
# previous, go back one if we are greater than one
if ($offset > 1) {
$offset--;
}
}
}
# query time, give me one result (LIMIT 1), staring at record $offset
$sql = "select SELECT * FROM Emails where UserEmail > 1
ORDER BY UserEmail LIMIT 1, $offset";
In your form add this:
<input type="hidden" name="offset" value="<?php echo $offset; ?>">
On a different note, UserEmail > 1 seems weird, but I don't know your data.

PHP inserting multiple checkbox AND textbox arrays into MySQL Database

I'm having trouble with the array results in my php. My first problem is this :
It shows everything even if the checkbox isn't checked. My second problem is that it won't insert the values to the database even though it's connected to the database (as you can see in the previous screenshot, it says "connected successfully").
This is my html form:
<form method="POST">
<input type="hidden" name="item[]" value="cupcake">
<input type="text" name="items" value="cupcake" readonly><br>
<b>Price :</b> <span name="price" value="3.00">$17.00</span><br>
Quantity: <input tabindex="1" name="quantity[]" min="0" max="5" type="number" class="quantity" value="1" /><br>
<input tabindex="1" name="checkbox[]" type="checkbox" value="17" /><span>Add to Cart</span></label></div></div></td><br>
<input type="hidden" name="item[]" value="cake">
<input type="text" name="items" value="cake" readonly><br>
<b>Price :</b> <span name="price" value="20.00">$20.00</span><br>
Quantity: <input tabindex="1" name="quantity[]" min="0" max="5" type="number" class="quantity" value="1" /><br>
<input tabindex="1" name="checkbox[]" type="checkbox" value="20" /><span>Add to Cart</span></label></div></div></td><br>
<input type="submit" name="insertBT"><br>
</form>
PHP:
if(isset($_POST['insertBT']))
{
class db_conn
{
public function create_conn($servername, $username, $password, $db)
{
global $conn;
$conn = new mysqli ($servername, $username, $password, $db);
}
public function check_conn()
{
global $conn;
if($conn->connect_error)
{
die ("Connection Failed : " . $conn->connect_error);
}
else
{
echo ("Connected Successfully <br>");
}
}
public function insert()
{
if(isset($_POST['checkbox'])) {
foreach($_POST['checkbox'] as $check) {
$check = implode(',', $_POST['checkbox']);
$name = implode(',', $_POST['item']);
$quantity = implode(',', $_POST['quantity']);
}
echo $check . "<br>";
echo $name . "<br>";
echo $quantity . "<br>";
mysql_query("INSERT INTO purchases(Product, Quantity, Price) VALUES('$name', '$quantity','$check')");
}
}
}
$obj1 = new db_conn;
$obj1->create_conn("localhost","root","", "dbtest");
$obj1->check_conn();
$obj1->insert();
}
You shouldn't be using implode. That puts a comma-separated list of everything in the form into each row that you insert, and repeats this for every box that's checked. You should just insert one item in each row, by indexing the arrays.
However, when you have a checkbox in a form, it only submits the ones that are checked. The result of this is that the indexes of the $_POST['checkbox'] array won't match up with the corresponding $_POST['item'] and $_POST['quantity'] elements. You need to put explicit indexes into the checkbox names so you can relate them.
<form method = "POST">
<input type = "hidden" name = "item[]" value = "cupcake">
<input type = "text" name = "items" value = "cupcake" readonly><br>
<b>Price :</b> <span name = "price" value = "3.00">$17.00</span><br>
Quantity: <input tabindex="1" name="quantity[]" min="0" max="5" type="number" class="quantity" value="1" /><br>
<input tabindex="1" name="checkbox[0]" type="checkbox" value="17" /><span>Add to Cart</span></label></div></div></td><br>
<input type = "hidden" name = "item[]" value = "cake">
<input type = "text" name = "items" value = "cake" readonly><br>
<b>Price :</b> <span name = "price" value = "20.00">$20.00</span><br>
Quantity: <input tabindex="1" name="quantity[]" min="0" max="5" type="number" class="quantity" value="1" /><br>
<input tabindex="1" name="checkbox[1]" type="checkbox" value="20" /><span>Add to Cart</span></label></div></div></td><br>
<input type = "submit" name = "insertBT"><br>
</form>
Then your PHP code can be like this:
$stmt = $conn->prepare("INSERT INTO purchases (Product, Quantity, Price) VALUES (?, ?, ?)");
$stmt->bind_param("sis", $name, $quantity, $price);
foreach ($_POST['checkbox'] as $i => $price) {
$name = $_POST['name'][$i];
$quantity = $_POST['quantity'][$i];
$stmt->execute();
}
BTW, putting the prices in your HTML seems like a bad idea. Nothing stops the user from modifying HTML using the web inspector before they submit the form, so they could lower the price. You should get the prices from the database when processing the form.
Also, notice that in your original code you opened the database connection using MySQLi, but then you tried to do the insert using mysql_query instead of $conn->query(). You can't mix APIs like that; myql_query can only be used when you open the connection with mysql_connect.

Update multiple SQL records using one PHP/MySQLi query

Is it possible to update multiple records in one MySQLi query?
There are 4 records to be updated (1 for each element level) when the submit button is clicked.
The results are posted to a separate PHP page which runs the query and returns the user back to the edit page. elementid is 1,2,3,4 and corresponds with Earth, wind, fire, water. These never change (hence readonly or hidden)
<form id="edituser" name="edituser" method="post" action="applylevelchanges.php">
<fieldset>
<legend>Edit Element Level</legend>
<?php
while($userdetails->fetch())
{?>
<input name="clientid" id="clientid" type="text" size="8" value="<?php echo $clientid; ?>" hidden />
<input name="elementid" id="elementid" type="text" size="8" value="<?php echo $elementid;?>" hidden />
<input name="elemname" id="elemname" type="text" size="15" value="<?php echo $elemname; ?>" readonly />
<input name="elemlevel" id="elemlevel" type="text" size="8" required value="<?php echo $elemlevel; ?>" /></br>
</br>
<?php }?>
</fieldset>
<button type="submit">Edit Student Levels</button>
</form>
And the code to apply the changes
<?php
if (isset($_POST['clientid']) && isset($_POST['elementid']) && isset($_POST['elemname']) && isset($_POST['elemlevel'])) {
$db = createConnection();
$clientid = $_POST['clientid'];
$elementid = $_POST['elementid'];
$elemname = $_POST['elemname'];
$elemlevel = $_POST['elemlevel'];
$updatesql = "update stuelement set elemlevel=? where clientid=? and elementid=?";
$doupdate = $db->prepare($updatesql);
$doupdate->bind_param("iii", $elemlevel, $clientid, $elementid);
$doupdate->execute();
$doupdate->close();
$db->close();
header("location: edituserlevel.php");
exit;
} else {
echo "<p>Some parameters are missing, cannot update database</p>";
}

Table not updating after mysql query

I have an administrator.php which displays 300 records from a table called 'player'. Next to each record, there is an edit option which redirects you to edit.php and the 15 columns of that record (including the primary key - playerid) is displayed inside text boxes. Line of code below:
<a href='edit.php?playerid=".$query2['playerid']."'>Edit</a>
On edit.php you are able to change data of these columns. Upon submit, an update query is sent to update the table but unfortunately, it's not working. My error message continues to display ("testing for error..."); not sure why.
//Setups up the database connection
$link = mysql_connect("localhost", "root", "");
mysql_select_db("fantasymock", $link);
if(isset($_GET['playerid'])) {
$playerid = $_GET['playerid'];
//Query to display results in input box
$query1 = mysql_query("SELECT * from player WHERE playerid = '$playerid'");
$query2 = mysql_fetch_array($query1);
}
if(isset($_POST['submit'])) {
$playerid = $_POST['playerid'];
$preranking = $_POST['preranking'];
$playerlast = $_POST['playerlast'];
$playerfirst = $_POST['playerfirst'];
$position = $_POST['position'];
$battingavg = $_POST['battingavg'];
$run = $_POST['run'];
$homerun = $_POST['homerun'];
$rbi = $_POST['rbi'];
$sb = $_POST['sb'];
$win = $_POST['win'];
$save = $_POST['save'];
$strikeout = $_POST['strikeout'];
$era = $_POST['era'];
$whip = $_POST['whip'];
//Query to update dB
$query3 = mysql_query("UPDATE player SET playerid='$playerid', preranking='$preranking', playerlast='$playerlast', playerfirst='$playerfirst', position='$position', battingavg='$battingavg', run='$run', homerun='$homerun', rbi='$rbi', sb='$sb', win='$win', save='$save', strikeout='$strikeout', era='$era', whip='$whip' WHERE playerid='$playerid'");
header("Location: administrator.php");
} else {
echo "Testing For Error....";
}
?>
<form action="" method="POST">
Player ID:<input type="text" name="playerid" value="<?php echo $query2['playerid'];?>"/> <br/>
Preranking:<input type="text" name="preranking" value="<?php echo $query2['preranking'];?>"/> <br/>
Last Name:<input type="text" name="playerlast" value="<?php echo $query2['playerlast'];?>"/> <br/>
First Name:<input type="text" name="playerfirst" value="<?php echo $query2['playerfirst'];?>"/> <br/>
Position:<input type="text" name="position" value="<?php echo $query2['position'];?>"/> <br/>
Batting Avg:<input type="text" name="battingavg" value="<?php echo $query2['battingavg'];?>"/> <br/>
Runs:<input type="text" name="run" value="<?php echo $query2['run'];?>"/> <br/>
Homeruns:<input type="text" name="homerun" value="<?php echo $query2['homerun'];?>"/> <br/>
Rbi:<input type="text" name="rbi" value="<?php echo $query2['rbi'];?>"/> <br/>
Sb:<input type="text" name="sb" value="<?php echo $query2['sb'];?>"/> <br/>
Wins:<input type="text" name="win" value="<?php echo $query2['win'];?>"/> <br/>
Saves:<input type="text" name="save" value="<?php echo $query2['save'];?>"/> <br/>
Strikeouts:<input type="text" name="strikeout" value="<?php echo $query2['strikeout'];?>"/> <br/>
Era:<input type="text" name="era" value="<?php echo $query2['era'];?>"/> <br/>
Whip:<input type="text" name="whip" value="<?php echo $query2['whip'];?>"/> <br/>
<br>
<input type="submit" name="submit" value="submit">
</form>
FYI: Every column in the table and tablename is spelled correctly, I've triple checked before posting. And I'm aware of MySQL injection. Can someone see a problem? Thank you in advance!
EDIT: I just added an additional if statement if($query3) and it now works.
You are checking for POST variables, but you are getting to edit.php through a GET request. There isn't anything on $_POST. Therefore it drops down to the else of your if block and prints out Testing For Error...
Your script in getting into the else part. That means there nothing it is getting as $_POST['submit']. Make sure that your submit button must have a name attribute as submit.
<input type="submit" name="submit" value="" />
please check what showing in error.log file. You may insert these lines at your edit.php file
error_reporting(E_ALL);
ini_set('display_errors', 1);
to display error.
Replace your else part by this for more detailed mysql errors
else{ echo "Testing For Error...." .mysql_error(); }

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