PHP foreach set row name as new variable - php

Question

My Php function loops trough the mysql table and for each row it sets the row name as $var and the row value to $val.
foreach($row as $var => $val) {...
Now I want to set the received rowname ($var) as a new variable.
This example is not right but to explain my thoughts ; $name$var = $val
If $var would be = rowname1
then the new variable would be $rowname1 = value1
Any ideas how to achieve this ?
Thanks.

Answer 1

You can use variable variables to do that:
foreach(...) {
$$var = $val;
}
But cleaner would be to use an array:
foreach(...) {
$var_names[] = array($var => $val);
}

Answer 2

<?php
$array = array(
'go' => 'something1',
'go2' => 'something2',
'go3' => 'something3',
'go4' => 'something4',
'go5' => 'something5',
);
foreach ($array as $key => $val) {
${$key} = $val;
}
print $go;
?>
EXAMPLE
or you could use the $$ way explained here:
Read more about Variable Variables...

Answer 3

You can use it like ${$var} = $val. Curly brackets are there just for convenience and readability. $$var = $val should also work.

Answer 4

You can create variables with dynamic names on the fly using strings! This is supported in the documentation provided here
A quick example:
// This now holds the string hello
$variableName = 'hello';
// This creates the variable 'hello' and contains the value test
$$variableName = "test";
echo $hello;
With the above example complete you will be able to create a variable name with the key + value strings as follows:
$count = 1;
foreach($row as $var => $val)
{
$varName = $var.$count;
$$varName = $val;
$count++;
}
This will create column_name1, column_name2 etc.
I feel the need to add a little discretion as this is not common or best practice. The best way to handle this information would be to take the $key => $val pair and store it into a separate variable or parse through them. By doing this you are basically throwing away all of the ease of use that is using arrays.
Also, side note:
You can also dynamically call on methods this way.
function test()
{
echo "test yar";
}
$method = "test";
$method();