User levels with PHP - php

Question

What I'm trying to do is make it so that when a specific user level is set in my Database it shows up specific text. Here is my code.
$userget = mysql_query("SELECT * FROM `usertable` WHERE `username`='".$_SESSION['user']."'");
$user = mysql_fetch_array($userget);
function getUserlevel() {
if($user['userlevel'] == '1') { echo "Regular User"; }
elseif($user['userlevel'] == '2') { echo "Moderator"; }
elseif($user['userlevel'] == '3') { echo "Administrator"; }
else { echo "Undefined"; }
}
I know the function is working, because the Echo of Undefined works, which I set up as a test but the others are not working despite my user level being set to 3 and only echoing Undefined. A session is also set for when the user is logged in.
This is when the function is called.
<div class="userData">Welcome Back, <?php echo $_SESSION['user']; ?><hr /><?php
getUserlevel(); ?></div>

Answer 1

Ok, I'm going to take a stab at:
getUserlevel($user['userlevel']);
function getUserlevel($usrlvl) {
if($usrlvl == '1') { echo "Regular User"; }
elseif($usrlvl == '2') { echo "Moderator"; }
elseif($usrlvl == '3') { echo "Administrator"; }
else { echo "Undefined"; }
}

Answer 2

I just included query into function, and its working :P
<?php
function getUserlevel() {
$userget = mysql_query("SELECT * FROM `users` WHERE `username`='".$_SESSION['username']."'");
$user = mysql_fetch_array($userget);
if($user['user_level'] == 1) { echo "Regular User"; }
elseif($user['user_level'] == 2) { echo "Moderator"; }
elseif($user['user_level'] == 3) { echo "Administrator"; }
else { echo "Error"; }
}
?>

Answer 3

You can not access $user as $user[userlevel] because mysql_fetch_array return an array. Does username is unique if not use an id instead of using username. So you should write the function as below
function getUserlevel()
{
foreach($user as $u)
{
if($u['userlevel'] == 1){echo "Regular User";}
else if($u['userlevel'] == 2){echo "Moderator";}
else if($u['userlevel'] == 3){echo "Administrator";}
else{echo "Undefined";}
}
}
If it does not work make sure you have write a vaild mysql query