PHP-PDO try/catch inserting dynamic html link - php

it seems i have run into a slight problem in my first shot at using PDO and prepared statements. Basically I am working on a profile page which includes an Inbox. I am using try/catch to produce the inbox:
<?php
$sqlin = $db->prepare("SELECT * FROM message WHERE recipientID = (SELECT id FROM members WHERE username = '$pageowner')");
try {
while($row = $sqlin->fetch(PDO::FETCH_ASSOC)){
?>
<br><?php echo $row['title'] ?>
<?php
}
}
catch(PDOException $e) {
die ($e->getMessage());
}
?>
So this is supposed to relate the user id to the recipient id, and then create links to the messages. When I run in browser no links are listed
Is this an issue within my try/catch syntax? maybe stopping the php and inserting the html?--I tried echoing out but ran into problems creating that code.

You have to start to try/catch the exception before the prepare() and after it. And please use prepared statement, with prepare() method. Otherwise, you are defeating the purpuse of PDO by directly placing your variables inside the query. Which does not make your script safer from mysql injection.
$pageOwner = 'some external data';
try {
$sqlin = $db->prepare("
SELECT * FROM message
WHERE recipientID = (
SELECT id
FROM members
WHERE username = ?
)
");
$sqlin->execute(array($pageOwner));
}catch(PDOException $e){
die ($e->getMessage());
}
while($row = $sqlin->fetch(PDO::FETCH_ASSOC)){
?>
<br><?= $row['title'] ?>
<?php } ?>

first, you shouldn't use try..catch here at all.
Instead, you have to call execute() and use prepared statements.
Also you have to separate your SQL from HTML.
Here is the proper code.
<?php
$sql = "SELECT m.* FROM message m, members mm WHERE recipientID = mm.id and username = ?";
$stm = $db->prepare($sql);
$stm->execute([$pageowner]);
$data = $stm->fetchAll();
?>
<?php foreach ($data as $row): ?>
<br><?=$row['title'] ?>
<?php endforeach ?>

Related

MySQL error 2002 when use INSERT INTO

I have a problem with mysql. When I execute this, that give me an error: No such file or directory 2002, but SELECT query work perfect and print typ on the screen. What can I solve this problem?
<?php
$con=mysqli_connect("db4free.net","****","****","*****");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$username = $_GET['username'];
$password = $_GET['password'];
$result = mysqli_query($con,"SELECT Typ FROM Uzytkownik where Login='$username' and Haslo='$password'");
$row = mysqli_fetch_array($result);
$data = $row[0];
if($data){
echo $data;
}
$que = "INSERT INTO Uzytkownik VALUES ('10','tr','t','a')";
if( !mysql_query($que) ) {
echo "ERROR!!: ".mysql_error().mysql_errno() ;
}
mysqli_close($con);
?>
Result of this:
testERROR!!: No such file or directory2002
EDIT Sorry, I pasted wrong code, but it was already changed
You cannot mix mysqli_* functions with mysql_* functions.
replace this:
if( !mysql_query($que) ) {
echo "ERROR!!: ".mysql_error().mysql_errno() ;
}
with
if( !mysqli_query($con, $que) ) {
echo "ERROR!!: ".mysqli_error($con) ;
}
In the insert query you should tell which columns you're inserting into.
$que = "INSERT INTO Uzytkownik(col1, col2, col3, col4) VALUES ('10','tr','t','a')";
Also note that most of your queries are vulnerable to sql-injections, you should use prepared statements to protect your code.
Example: Your select query looks like this:
"SELECT Typ FROM Uzytkownik where Login='$username' and Haslo='$password'".
If I were a user I could get in without using a password, by ending the sql statement within the username or within the password, I could drop the table and I could even drop the entire database if I were a blackhat in a bad mood.
Using prepared statements means that instead of using user-input-provided values you replace the user inputs with VALUES(?, ?) and then you can bind parameters that will then be executed and replace the placeholders.
Using PDO allows you to use named paramters, you should take a look at that.
Also note that you're mixing mysql_* and mysqli_* which are not the same library of functions, stick to one (otherwise it simply won't work) and mysqli_* is way better since mysql_* is deprecated. This could be causing your problem.

Delete record and count rows to check for result

So Im trying to delete a record from a table using php and sql and check whether it has been deleted using a rowcount() function in an if statement.
Im having problems on both fronts...
<?php
echo $_GET['id'];
if (isset($_GET['id'])) {
$trainingID = $_GET['id'];
}
else {
die('There was a problem with the ID given.');
}
// include the connection file
require_once('./includes/connection.inc.php');
$conn = dbConnect();
// prepare SQL statement
$sql = 'DELETE FROM `trainingCourses` WHERE `trainingID` = "$trainingID"';
$stmt = $conn->prepare($sql);
try {
$stmt->execute();
echo "deleted";
echo $stmt->rowcount();
//check number of rows affected by previous insert
if ($stmt->rowCount() == 1) {
$success = "$trainingID has been removed from the database.";
}
}
catch(PDOException $e){
echo $e;
echo 'Sorry, there was a problem with the database.';
}
?>
I currently get 3 things outputted from my echo's throughout my code, firstly i get T0001, which is the primary key of the record i want to delete from another page. Secondly i get "deleted" which is from an echo within my 'try' statement but the record doesn't actually delete from the database. This is backed up from the rowcount() function which outputs 0.
I can't seem to get this working and im sure it should be simple and is something i am just overlooking!
Will the try method default to the catch if the "if" statement in it fails? As im also unsure what should be output from a rowcount() when a row has been deleted?
Any help you could offer would be really helpful! Thanks!
echo'ing this line
$sql = 'DELETE FROM `trainingCourses` WHERE `trainingID` = "$trainingID"';
will treat $trainingID as string and not variable.
$sql = "DELETE FROM `trainingCourses` WHERE `trainingID` = '$trainingID'";
will do the work BUT its not safe (sql injections). You should use PDO to bind varaibles like this
$sth = $dbh->prepare("DELETE FROM `trainingCourses` WHERE `trainingID` = :id");
$sth->bindParam(":id",$trainingID);
$sth->execute();

Retrieving row from MySQL Database via PHP

Please bear with me, I'm new here - and I'm just starting out with PHP. To be honest, this is my first project, so please be merciful. :)
$row = mysql_fetch_array(mysql_query("SELECT message FROM data WHERE code = '". (int) $code ."' LIMIT 1"));
echo $row['message'];
Would this be enough to fetch the message from the database based upon a pre-defined '$code' variable? I have already successfully connected to the database.
This block of code seems to return nothing - just a blank space. :(
I would be grateful of any suggestions and help. :)
UPDATE:
Code now reads:
<?php
error_reporting(E_ALL);
// Start MySQL Connection
REMOVED FOR SECURITY
// Check if code exists
if(mysql_num_rows(mysql_query("SELECT code FROM data WHERE code = '$code'"))){
echo 'Hooray, that works!';
$row = mysql_fetch_array(mysql_query("SELECT message FROM data WHERE code = '". (int) $code ."' LIMIT 1")) or die(mysql_error());
echo $row['message'];
}
else {
echo 'That code could not be found. Please try again!';
}
mysql_close();
?>
It's best not to chain functions together like this since if the query fails the fetch will also appear to fail and cause an error message that may not actually indicate what the real problem was.
Also, don't wrap quotes around integer values in your SQL queries.
if(! $rs = mysql_query("SELECT message FROM data WHERE code = ". (int) $code ." LIMIT 1") ) {
die('query failed! ' . mysql_error());
}
$row = mysql_fetch_array($rs);
echo $row['message'];
And the standard "don't use mysql_* functions because deprecated blah blah blah"...
If you're still getting a blank response you might want to check that you're not getting 0 rows returned. Further testing would also include echoing out the query to see if it's formed properly, and running it yourself to see if it's returning the correct data.
Some comments:
Don't use mysql_*. It's deprecated. use either mysqli_* functions or the PDO Library
Whenever you enter a value into a query (here, $code), use either mysqli_real_escape_string or PDO's quote function to prevent SQL injection
Always check for errors.
Example using PDO:
//connect to database
$user = 'dbuser'; //mysql user name
$pass = 'dbpass'; //mysql password
$db = 'dbname'; //name of mysql database
$dsn = 'mysql:host=localhost;dbname='.$db;
try {
$con = new PDO($dsn, $user, $pass);
} catch (PDOException $e) {
echo 'Could not connect to database: ' . $e->getMessage();
die();
}
//escape code to prevent SQL injection
$code = $con->quote($code);
//prepare the SQL string
$sql = 'SELECT message FROM data WHERE code='.$code.' LIMIT 1';
//do the sql query
$res = $con->query($sql);
if(!$res) {
echo "something wrong with the query!";
echo $sql; //for development only; don't output SQL in live server!
die();
}
//get result
$row = $res->fetch(PDO::FETCH_ASSOC);
//output result
print_r($row);

mysql_query not working

Here's PHP code that I'm using:
$query="select * from `myTable` where `email`='$email' limit 0,1";
if(empty($conn))
{
echo "not connected".PHP_EOL;
}
$result = mysql_query($query,$conn);
$row = mysql_fetch_array($result);
if(empty($row))
{
....
When the query is executed in phpmyadmin, I get a single row selected.
However, when I execute the code in php, the row is always empty.
The same goes for several other queries that I've tried to execute. mysql_query always fails.
What could be wrong?
I do not feel there is enough of the code to see what is going on. But based on just what you are showing us, after you get the $result and assign it to $row you have a if statement
if(empty($row)) {...doing something secret...}
which means if something was returned like the row you are expecting NOTHING would happen because (empty($row)) would be false and not execute.
Try this using PDO:
<?php
$email = "example#example.com";
try {
//Instantiate PDO connection
$conn = new PDO("mysql:host=localhost;dbname=db_name", "user", "pass");
//Make PDO errors to throw exceptions, which are easier to handle
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//Make PDO to not emulate prepares, which adds to security
$conn->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$query = <<<MySQL
SELECT *
FROM `myTable`
WHERE `email`=:email
LIMIT 0,1;
MySQL;
//Prepare the statement
$stmt = $conn->prepare($query);
$stmt->bindParam(":email", $email, PDO::PARAM_STR);
$stmt->execute();
//Work with results
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
//Do stuff with $row
}
}
catch (PDOException $e) {
//Catch any PDOExceptions errors that were thrown during the operation
die("An error has occurred in the database: " . $e->getMessage());
}
Using mysql_* functions is highly discouraged. It's a guarantee to produce broken code. Please learn PDO or MySQLi from the links in the comment I gave you, and use those instead.
First, confirm $email's value. Echo it right before defining $query to make sure it's what you think it is.
If you've already done that, then you know that's the problem--instead, it's likely that your link identifier $conn is the problem. Instead of using a link identifier, try leaving the second parameter of your query empty, and instead run mysql_connect() at the beginning of your script. That's the best way to do things 99.5% of the time.
See: http://php.net/manual/en/function.mysql-connect.php

How to show SQL errors in SQLite?

Using SQLite in PHP (thus using PDO), I have this code:
try {
$db = new PDO("sqlite:C:\Program Files\Spiceworks\db\spiceworks_prod.db");
echo "Done.<br /><b>";
$query = "SELECT id FROM Devices LIMIT 5";
echo "Results: ";
$result = $db->query($query);
while ($row = $result->fetchArray()) {
print_r($row)."|";
}
}
catch(PDOException $e) {
echo $e->getMessage();
}
But that does not print out any data from the SQL. I know the database has data in it and the connection is valid. If I change the query to say:
$query = "SELECT BLAHid FROM FakeDevices LIMIT 5";
Nothing changes. Nothing from SQL gets printed out again, and I see no errors even though this is clearly an invalid SQL query.
In both situations, the "Done" and "Results" gets printed out okay. How can I print out SQL errors, like if the query is invalid?
You need to tell PDO to throw exceptions. You can do that by adding the following line after you connect to the database:
$db = new PDO("sqlite:C:\Program Files\Spiceworks\db\spiceworks_prod.db");
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
That way you can catch all exceptions except for a possible problem with the first line, the database connection itself.

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