If i have a varible
// in minutes
$min = 40;
And i want to add it to a strotime formatted time
$strtTime = $strtotime('now') + $min;
whats the correct way to do this?
You can do this:
strtotime("+{$min} minutes");
There's not much to it:
echo strtotime("+40 minutes");
See it in action
Well, look at the documentation. It tells you how to use the function.
$future = strtotime('+40 minutes');
You can also be a little more concrete and include where to start from.
$future = strtotime('now + 40 minutes');
While the above is a lot easier you could also do it manually. It just involves some basic arithmetic:
$now = time(); // Seconds since 1970-01-01 00:00:00
$minutes = 40;
$seconds = ($minutes * 60); // 2400 seconds
$future = ($now + $seconds);
$min = 40;
And i want to add it to a strotime formatted time
$strtTime = strtotime("+".$min." minutes", strtotime('now'));//eg +40 minutes
Related
I have a system which I need to add a certain amount of fractional hours.
I've been searching and this is what I got, by far it's the most accurate method, but still doesn't give me the answer I need
function calculateHours($hours){
$now = new DateTime("2017-10-25 10:23:00");
$time = array();
$time = explode(".", $hours);
$time [1] += $time [0]*60;
$now->modify("+".$time[1]." hours");
return $now;
}
$diff = 119.23;
$answer = calculateHours($diff);
echo $answer ->format('Y-m-d H:i:s');
The answer that I want to reach is "2017-11-09 11:00:00" and I receive "2017-10-25 12:22:23" instead
Adding the hours is not correct. When you multiply hours times 60 it will make minutes.
This code should work.
function calculateHours($hours){
$now = new DateTime("2017-10-25 10:23:00");
$time = explode(".", $hours);
$time[1] += $time[0]*60;
$now->modify("+".$time[1]." minutes");
return $now;
}
$diff = 119.23;
$answer = calculateHours($diff);
echo $answer->format('Y-m-d H:i:s');
Result is 2017-10-30 09:46:00
You should use DateInterval php class to create an inverval with x seconds from your $hours variable.
Then you just have to use the datetime add interval method to modify your date
Please take a look a this example
function calculateHours($hours){
$now = new DateTime("2017-10-25 10:23:00");
var_dump($now);
$timeParts = explode(".", $hours);
// Where 23 is a percentage of on hour
$minutes = $timeParts[0] * 60 + round($time[1] * 60 / 100);
// Where 23 is the number of minutes
$minutes = $timeParts[0] * 60 + $time[1];
$interval = new DateInterval(sprintf('PT%dM', $minutes));
$now->add($interval);
echo $now->format('Y-m-d H:i:s');
return $now;
}
Use date_add
date_add($now, date_interval_create_from_date_string($tempo[1]' hours'));
or as object:
$now->add( DateInterval::createFromDateString($tempo[1].' hours'));
Say I have the following as a string:
$timeLeft = 00:02:30
I want to be able to subtract 1 second, turning it into 00:02:29.
I have tried
$timeLeft - 1;
But it does nothing.
How can I make it so I can subtract seconds from a string?
You need to convert it to a time, subtract 1 second and reformat, e.g.:
$timeLeft = '00:02:30';
$time = DateTime::createFromFormat('H:i:s', $timeLeft);
$time->sub(new DateInterval('PT1S'));
$timeLeft = $time->format('H:i:s');
Below is dirty code that performs the transformation "manually" by converting the time into seconds in case PHP 5.3+ is not available. It'll certainly misbehave it the number of seconds subtracted is greater than the total.
$timeLeft = '00:02:30';
list($hours, $minutes, $seconds) = explode(':', $timeLeft);
$seconds += $hours*3600 + $minutes*60;
unset($hours, $minutes);
$seconds -= 1; //subtraction
$hours = floor($seconds/3600);
$seconds %= 3600;
$minutes = floor($seconds/60);
$seconds %= 60;
$timeLeft = sprintf("%'02u:%'02u:%'02u", $hours, $minutes, $seconds);
Using strtotime is a good practical solution, but you have to watch out for DST changes:
$tz = date_default_timezone_get(); // save old timezone
date_default_timezone_set('UTC'); // switch to UTC
echo date('H:i:s', strtotime($timeleft) - 1); // perform calculation
date_default_timezone_set($tz); // restore old setting
The future time is :2012-05-26 00:00:00
supposed there are three variable: $hour $minute $second
now, i want to using the future time subtract now time. then give the left hour to $hour,give the left minute to $minute,give the left second to $second.
i am sorry i am new of php, now i get stucked how to do the math operation ? thank you
A very good resource for dates and time..
http://www.php.net/manual/en/function.time.php
-there are samples here doing something similar.
Check the date_diff function. There's the exact solution to what you're asking there.
And here's the page (DateInterval::format) documenting how you can format the output.
$now = date_create();
// use "now" and necessary DateTimeZone in the arguments
$otherDate = date_create('2020-04-13');
$interval = date_diff($now, $futureDate);
echo $interval->format('%a days');
The following are the math operations for the difference in hours,minutes and seconds
$future_datetime = '2012-05-26 00:00:00';
$future = strtotime($future_datetime); //future datetime in seconds
$now_datetime = date('Y-m-d H:i:s');
$now = date('U'); //now datetime in seconds
//The math for calculating the difference in hours, minutes and seconds
$difference = $future - $now;
$second = 1;
$minute = 60 * $second;
$hour = 60 * $minute;
$difference_hours = floor($difference/$hour);
$remainder = $difference - ($difference_hours * $hour);
$difference_minutes = floor($remainder/$minute);
$remainder = $remainder - ($difference_minutes * $minute);
$difference_seconds = $remainder;
echo "The difference between $future_datetime and $now_datetime is $difference_hours hours, $difference_minutes minutes and $difference_seconds seconds";
I have a created_at date saved liked this "2011-09-23 19:10:18" And I want to get the days and hours left
until the date is reached. How do I do that? and column name in database remain days automatically update daily with remain days, please solve this
PHP fragment:
<?php
//Convert to date
$datestr="2011-09-23 19:10:18";//Your date
$date=strtotime($datestr);//Converted to a PHP date (a second count)
//Calculate difference
$diff=$date-time();//time returns current time in seconds
$days=floor($diff/(60*60*24));//seconds/minute*minutes/hour*hours/day)
$hours=round(($diff-$days*60*60*24)/(60*60));
//Report
echo "$days days $hours hours remain<br />";
?>
Note the hour-round and no minutes/seconds consideration means it can be slightly inaccurate.
This should seed your endeavor.
getdate(strtotime("2011-09-23 19:10:18"))
Full conversion:
$seconds = strtotime("2011-09-23 19:10:18") - time();
$days = floor($seconds / 86400);
$seconds %= 86400;
$hours = floor($seconds / 3600);
$seconds %= 3600;
$minutes = floor($seconds / 60);
$seconds %= 60;
echo "$days days and $hours hours and $minutes minutes and $seconds seconds";
as of PHP 5.3.0 you could use build-in Date object:
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
http://www.php.net/manual/en/book.datetime.php
it would be something like
echo $date = date("Y-m-d H:i:s");echo "\n";
$original=time($date);
$modified = "2011-09-23 19:10:18";
echo date("Y-m-d H:i:s",$modified);echo "\n";
The easiest way is improved answer from CountZero. I used this solution for counter for time remaining before expiration of offer. Addition to first three lines of CountZero code:
$days = $interval->d;
$hours = $interval->h;
$minutes = $interval->i;
$seconds = $interval->s;
And now, you can use string functions to moderate your return values, to merge all or add '0' or '00' in front of the values.
You can find current date and time using date() function and then subtract
$x = 2011-09-23 - current_date
this will give you no. of days left.
Do same with time as well ..
Hope this helps
I have two dates, formated like "Y-m-d H:i:s". I need to compare these two dates and figure out the hour difference.
You can convert them to timestamps and go from there:
$hourdiff = round((strtotime($time1) - strtotime($time2))/3600, 1);
Dividing by 3600 because there are 3600 seconds in one hour and using round() to avoid having a lot of decimal places.
You can use DateTime class also -
$d1= new DateTime("06-08-2015 01:33:26pm"); // first date
$d2= new DateTime("06-07-2015 10:33:26am"); // second date
$interval= $d1->diff($d2); // get difference between two dates
echo ($interval->days * 24) + $interval->h; // convert days to hours and add hours from difference
As an addition to accepted answer I would like to remind that \DateTime::diff is available!
$f = 'Y-m-d H:i:s';
$d1 = \DateTime::createFromFormat($date1, $f);
$d2 = \DateTime::createFromFormat($date2, $f);
/**
* #var \DateInterval $diff
*/
$diff = $d2->diff($d1);
$hours = $diff->h + ($diff->days * 24); // + ($diff->m > 30 ? 1 : 0) to be more precise
\DateInterval documentation.
$seconds = strtotime($date2) - strtotime($date1);
$hours = $seconds / 60 / 60;
You can try this :
$time1 = new DateTime('06:56:58');
$time2 = new DateTime('15:35:00');
$time_diff = $time1->diff($time2);
echo $time_diff->h.' hours';
echo $time_diff->i.' minutes';
echo $time_diff->s.' seconds';
Output:
8 hours 38 minutes 2 seconds
The problem is that using these values the result is 167 and it should be 168:
$date1 = "2014-03-07 05:49:23";
$date2 = "2014-03-14 05:49:23";
$seconds = strtotime($date2) - strtotime($date1);
$hours = $seconds / 60 / 60;
$date1 = date_create('2016-12-12 09:00:00');
$date2 = date_create('2016-12-12 11:00:00');
$diff = date_diff($date1,$date2);
$hour = $diff->h;
This is because of day time saving.
Daylight Saving Time (United States) 2014 began at 2:00 AM on
Sunday, March 9.
You lose one hour during the period from $date1 = "2014-03-07 05:49:23" to
$date2 = "2014-03-14 05:49:23";
You can try this:
$dayinpass = "2016-09-23 20:09:12";
$today = time();
$dayinpass= strtotime($dayinpass);
echo round(abs($today-$dayinpass)/60/60);
You can use strtotime() to parse your strings and do the difference between the two of them.
Resources :
php.net - strtotime()