CreateQuery Doctrine Symfony 2 StateFieldPathExpression - php

Question

I have this Query in MySql
SELECT l.id as like_id, l.spotted_id as spotted_id,count(l.spotted_id) as numero_likes
FROM sn_like_spotted l
LEFT JOIN prof_foto f
ON f.id = l.spotted_id
LEFT JOIN sn_profilo p
ON f.profilo_id = p.id
WHERE p.id = 3
GROUP BY l.spotted_id
ORDER BY numero_likes DESC LIMIT 0,10
I try to do this in Doctrine
public function getFoo($profilo_id){
$em = $this->getEntityManager();
$query = $em->createQuery('
SELECT l.id as like_id, l.spotted_id as spotted_id,count(l.spotted_id) as numero_likes
FROM SNLikeBundle:LikeSpotted l
LEFT JOIN SNFotoBundle:Foto f
WITH f.id = l.spotted_id
LEFT JOIN SNProfiloBundle:Profilo p
WITH f.profilo_id = p.id
WHERE p.id = :profilo_id
GROUP BY l.spotted_id
ORDER BY numero_likes DESC
')->setFirstResults(0)
->setMaxResults(10)
->setParameter('profilo_id', $profilo_id);
$results = $query->getResult();
return $results;
}
Then i have this error
[Semantical Error] line 0, col 36 near 'spotted_id as': Error: Class SN\LikeBundle\Entity\LikeSpotted has no field or association named spotted_id
I change SELECT in:
SELECT l.id as like_id, l.spotted as spotted_id,count(l.spotted) as numero_likes
and I have this Error:
[Semantical Error] line 0, col 36 near 'spotted as spotted_id,count(l.spotted)': Error: Invalid PathExpression. Must be a StateFieldPathExpression.
Then i Try With IDENTITY
SELECT IDENTITY l.id as like_id, l.spotted as spotted_id,count(l.spotted) as numero_likes
But i Have This Error
[Syntax Error] line 0, col 26: Error: Expected Doctrine\ORM\Query\Lexer::T_FROM, got '.'
I try to create also in QueryBuilder (more criteria, same result)
$q = $this->createQueryBuilder('l');
$q->leftJoin("l.spotted", 's');
$q->leftJoin("s.profilo", 'p');
$q->leftJoin("p.utente", 'u');
$q->where('(s.foto_eliminata IS NULL OR s.foto_eliminata != 1)');
$q->andWhere('p.fase_registrazione = :fase');
$q->andWhere('u.locked = :false');
$q->andWhere('p.id = :profilo_id');
$q->setParameter(':fase', 100);
$q->setParameter('false', false);
$q->setParameter('profilo_id', $profilo_id);
$q->groupBy('l.spotted');
$q->orderBy($q->expr()->count('l.spotted'), 'desc');
$q->setMaxResults(10);
$dql = $q->getQuery();
$results = $dql->execute();
return $results;
My error is
[Syntax Error] line 0, col 285: Error: Expected end of string, got '('
The problem is in
$q->orderBy($q->expr()->count('l.spotted'), 'desc');

Answer 1

For CreateBuilder Case I Resolved:
$q = $this->createQueryBuilder('l');
$q->addSelect('count(l.spotted) as numero_likes');
$q->leftJoin("l.spotted", 's');
$q->leftJoin("s.profilo", 'p');
$q->leftJoin("p.utente", 'u');
$q->where('(s.foto_eliminata IS NULL OR s.foto_eliminata != 1)');
$q->andWhere('p.fase_registrazione = :fase');
$q->andWhere('u.locked = :false');
$q->andWhere('p.id = :profilo_id');
$q->setParameter(':fase', 100);
$q->setParameter('false', false);
$q->setParameter('profilo_id', $profilo_id);
$q->groupBy('l.spotted');
$q->addOrderBy('numero_likes','DESC');
$q->setMaxResults(10);
$dql = $q->getQuery();
$results = $dql->execute();
return $results;
if i don't want numero_likes in my results i can do this:
$q->addSelect('count(l.spotted) as HIDDEN numero_likes');
But i'd like how can i do this in createQuery