Fetching videos Using MySql annd php - php

Question

I'm working on a website that takes a user uploaded video and puts the name, size, type, path, and tmp_name into a MySQL database. The upload.php file is below,
<?php
$is_form_submitted = (isset($_POST['submit']))?true:false;
if($is_form_submitted)
{
//defines variables
$name=$_FILES['file']['name'];
$type=$_FILES['file']['type'];
$size=$_FILES['file']['size'];
$tmp_name=$_FILES['file']['tmp_name'];
$target_path="videos/";
$allowedTypes = array("video/wmv","video/avi",
"video/mpeg","video/mpg","video/mp4");
$is_valid_type = (in_array($_FILES['file']['type'], $allowedTypes))?true:false;
if ( $is_valid_type&& ($_FILES["file"]["size"] < 20000000000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";
mysql_query("INSERT INTO vids(name, type, size, tmp_name, target_path)
VALUES('$name', '$type', '$size', '$tmp_name', '$target_path')");
if (file_exists("images/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"videos/" . $_FILES["file"]["name"]);
echo "Stored in: " . "videos/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}
}
?>
And everything uploads properly but when I go and try to fetch the name and path of the video, it says that the video player has found no videos that are supported, so how would I fetch a random video from the database and put it as the source of the video player?
(the video file is playable in the player, so it is not the video's fault)
Here is the php code within the document code
<?php
$vid_url = "videos/";
$result = mysql_query("SELECT * FROM `vids` WHERE 1");
while($row = mysql_fetch_assoc($result))
{
echo
<div name="video">
<video width="100%" height="100%" controls>
<source src=".$vid_url.$row."type="video/mp4">
Error: Video Not working
</object>
</video>
</div>';
}
?>
And where I am storing the videos is a directory called videos

Answer 1

I figured it out in case anyone wants to reference this
<?php
//Connects to database
$host="################"; // Host name
$username="##########"; // Mysql username
$password="###########"; // Mysql password
$db_name="#######"; // Database name
$tbl_name="####"; // Table name
// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");
//Tells variable video where to get the name from
$vid_url = "videos/";
$result = mysql_query("SELECT * FROM vids ORDER BY RAND() LIMIT 1");
$row = mysql_fetch_assoc($result);
$video = $vid_url.$row["name"];
<?