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Given today's date, is there an elegant way to get the previous Sunday's and the next Saturday's date?
So, given today's date of 12/12/2013, I would want to get back 12/8/2013 for the Sunday and 12/14/2013 for the Saturday.
If given a Sunday, for example 12/15/2013, I would want to get back 12/15/2013 for the Sunday and 12/21/2013 for the Saturday.
If given a Saturday, for example 12/21/2013, I would want to get back 12/15/2013 for the Sunday and 12/21/2013 for the Saturday.
And so on.
Any ideas?
DateTime() accepts relative formats:
echo (new DateTime('last Saturday'))->format("Y-m-d");
echo (new DateTime('next Saturday'))->format("Y-m-d");
See it in action
Related
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I want to show a message on my site if it's after 5:00 PM on Thursday, and the whole day Friday.
I managed to get the code to work for Friday, but don't have any idea how to also get it to show on Thursday after 5.
Here's what I have so far:
$d=date("D");
if ($d=="Fri")
{
echo 'Items may ship out after the weekend.';
}
How can I also get this to show on Thursday after 5:00?
Thanks!
You can try this:
$d=date("D");
if ($d=="Fri" || ($d=="Thu" && date("Hi")>="1700")) {
echo 'Items may ship out after the weekend.';
}
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In my application, the user gives 2 inputs — one is date and the other is time:
$date = date("d-M-Y");
$time=date("h:m:s");
How can I calculate a time stamp from these two variables in PHP?
actually i take the date form date picker and time from time oicker.....
If you want time stamp then use this
echo strtotime($date.' '.$time);
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I want to get date in following format Thursday, September 26, 2013.
The name of day should be full like Monday not like Mon and same for the month format.
How to get this format?
Use php date function as below.
echo date('l,F d,Y',strtotime($date));
Date Format
I got this like following way
$mydate=getdate(date("U"));
echo "$mydate[weekday], $mydate[month] $mydate[mday], $mydate[year]";
OR
$today = date(DATE_RFC822);
echo date('l,F d,Y',strtotime($today));
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I'm trying to get the day after the easter date:
date("d-m-y", strtotime(easter_date(), '+1 day'));
I don't understand, the date showed is still the same, but when I try this:
date("d-m-y", strtotime('+1 day'));
It works.
How can I do?
That's because easter_date() produces a unix timestamp:
1364713200
And strtotime() is meant for this like 'today' and 'tuesday next week';
If you just want to add a day to it, just add 86400 (this is how many seconds are in a day) to easter_date();
So: date("d-m-y", easter_date() + 86400);
The function easter_date() returns a UNIX timestamp (e.g. 123338898) whereas strtotime()'s first parameter must be a valid date/time string (e.g. 2013-05-30 23:59:59). Valid formats are explained in Date and Time Formats.
Additionally, from the PHP documentation for strtotime():
Using this function for mathematical operations is not advisable. It
is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and
later, or DateTime::modify() in PHP 5.2.
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i want to increment the current date by one month which is in d/m/Y format
but i have no idea about this,can any one give me a relevant example.
thanks in advance
In PHP you do this:
$time = strtotime("+1 month", time());
$date = date("d/m/Y", $time);