how to create link depending on user input - php

Question

This is the code for the user to post the post.
if(islet($_POST['submit'])) {
$name = $_POST['name'];
$keywords = $_POST['keywords'];
$description = $_POST['description'];
if(islet($_GET['user_id'])) {
$_SESSION['user_id'] = $_GET['user_id'];
} //Then I just have a inset into statement for my database with these 4 variables.
}
I have a web form that creates a post by the user. I now want to make the user able to go back to a page dedicated to that post for them to edit, add on to etc.

Answer 1

Here is the high level solution:
You need to create a page that expects a post_id as a parameter of the query string. That page will be accessed like this: http://yoursite.com/show-post.php?post_id=136
In PHP, retrieve that post_id: $_GET['post_id']
From that post id, pull from the DB the information associated to that id. Something like SELECT * FROM post WHERE post_id = $_GET['post_id'].
Then display the post using the information returned by the SQL query.
If you want to show a list of posts from the current user, create another page http://yoursite.com/my-posts.php.
From that page, write a SQL query based on the current user id: SELECT * FROM post WHERE user_id = $_SESSION['user_id'] (assuming you have a user_id in the post table, and the user has authenticated and his id was stored in the session).
That will fetch you a list of posts, loop through them to get their details.
Please note that you should escape the parameter passed in the query string. There are many ways to do this so I won't go into it here.
EDIT:
This is how you generate the links:
<?php foreach ($mysql_result as $row) { ?>
link
<?php } ?>
Then, in edit-post.php, you can get the post_id by doing $postId = $_GET['post_id'];, and then use it in the query to fetch ALL the information about that one particular post.

Answer 2

Make sure you have a unique ID column in your database - call it 'postid', and set it to autoincrement with every new entry.
That way you'll be sure to have a unique identifier for each entry you insert in to the database.
You then need to retrieve a list of items in the database, including the postid, and for each row in the database provide a link to display it.
If a postid is selected in the url, then display information for that post. If it isn't, then show a list:
<?
$dbh = new PDO('mysql:host=localhost;dbname=databasename;charset=utf8', 'username', 'password');
///No post id selected, display a list of everything
if(!$_GET['postid']) {
print "You're listing all the rows in the database<br/>";
$query = $dbh->prepare("SELECT `postid`,`name` FROM `table` ORDER by postid ASC");
$query->execute();
while ($row = $query->fetch(PDO::FETCH_ASSOC)) {
print "".$row['name']."<br/>";
}
} else { //A post ID is selected
$postid = $_GET['postid'];
Print "Select from the database where postid = ".$postid;
$query = $dbh->prepare("SELECT `postid`, `name`, `keywords`, `description` FROM `table` WHERE `postid` = '$postid' LIMIT 1");
$query->execute();
while ($row = $query->fetch(PDO::FETCH_ASSOC)) {
$name = $row['name'];
$keywords = $row['keywords'];
$description = $row['description'];
print 'Displaying details for '.$name.': '.$keywords.', '.$description.' - create edit links here... <br/><br/>';
}
} //End post id is selected
?>