HTML form for PHP Image Upload Script - php

Question

Can anyone give me the html code for this php image upload script. I really need it please if anyone can help me on this I will be grateful to you.
Here is php code:
if(isset($_POST['upload'])) {
$allowed_filetypes = array('.jpg','.jpeg','.png','.gif');
$max_filesize = 10485760;
$upload_path = 'uploads/';
$description = $_POST['imgdesc'];
$filename = $_FILES['userfile']['name'];
$ext = substr($filename, strpos($filename,'.'), strlen($filename)-1);
if(!in_array($ext,$allowed_filetypes))
die('The file you attempted to upload is not allowed.');
if(filesize($_FILES['userfile']['tmp_name']) > $max_filesize)
die('The file you attempted to upload is too large.');
if(!is_writable($upload_path))
die('You cannot upload to the specified directory, please CHMOD it to 777.');
if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $filename)) {
$query = "INSERT INTO uploads (name, description) VALUES ($filename, $description)";
mysql_query($query);
echo 'Your file upload was successful!';
} else {
echo 'There was an error during the file upload. Please try again.';
}
}

Answer 1

I came across this exact code a while back
Here you go for html
<form action="/script.php" method="post" enctype="multipart/form-data">
<input type="file" name="userfile"/>
<input type="text" name="imgdec">
<button name="upload" type="submit" value="Submit">
</form>

Answer 2

<form name="myFrm" id="myFrm" action="uraction" method="post" enctype="multipart/form-data" >
<label for="upload" >Select Image</label><input type="file" id="upload" name="upload" accept="image/*">
<p/>
<input type="submit" value="Go" >
</form>
Bare minimum form to work for you

Answer 3

You can add
<input type="hidden" name="MAX_FILE_SIZE" value="10485760"/>
before the file input field. This form element set the maximum file size of the file input field and it is measured in bytes. This MAX_FILE_SIZE is applied to the file inputs that come after it. Remember, this does not indicate the total size of all the input files. See the following example:
<input type="hidden" name="MAX_FILE_SIZE" value="10000"/>
<!--for these two consecutive input fields, maximum file size is 10000 bytes -->
<input type="file" name="userfile1"/>
<input type="file" name="userfile2"/>
<input type="hidden" name="MAX_FILE_SIZE" value="50000"/>
<!--for this input field, maximum file size is 50000 bytes -->
<input type="file" name="userfile3"/>

Answer 4

Save below as index.php and create a folder in the same directory called images. Remember to chmod the images folder to 777 once on the server.
<?php
if(isset($_GET['do']) && $_GET['do'] == 'upload2') {
// Start
$allowed_filetypes = array('.jpg','.jpeg','.png','.gif');
$max_filesize = 10485760;
$upload_path = 'images/';
$filename = $_FILES['userfile']['name'];
$ext = substr($filename, strpos($filename,'.'), strlen($filename)-1);
if(!in_array($ext,$allowed_filetypes))
die('The file you attempted to upload is not allowed.');
if(filesize($_FILES['userfile']['tmp_name']) > $max_filesize)
die('The file you attempted to upload is too large.');
if(!is_writable($upload_path))
die('You cannot upload to the specified directory, please CHMOD it to 777.');
if(move_uploaded_file($_FILES['userfile']['tmp_name'],$upload_path . $filename)) {
// $query = "INSERT INTO uploads (name, description) VALUES ($filename, $description)";
// mysql_query($query);
echo 'Your file upload was successful!';
} else {
echo 'There was an error during the file upload. Please try again.';
}
// Finish
} elseif(isset($_GET['do']) && $_GET['do'] == 'upload1') {
echo '
<form action="index.php?do=upload2" method="post" enctype="multipart/form-data">
<input type="file" name="userfile"/>
<button name="upload" type="submit" value="Submit">
</form>
';
} else {
echo 'Link';
}
?>