I trying to get all user with same ip from database - php

Question

I am trying to find all user having same ip in database
and i tried few ways.
Now i am trying this but its only giving me one user
here is my short example of php code:
<?php
$CheckQuery = mysqli_query($GLOBALS["___mysqli_ston"],
"SELECT * FROM `logedfeeds`
WHERE ip='127.0.0.1'
GROUP BY user_id
ORDER BY `id`
DESC LIMIT 1000000");
//create table
$step1 = '<center><table border="1"><tr><td><b>UserID</b></td></tr>';
while($row = mysqli_fetch_assoc($CheckQuery)){
$userip = $row['user_id'];
$step2 = '<tr><td>' . $userip . '</td></tr>';
}
echo "$step1 $step2 </table></center>";
?>
I am trying this code but not seems to work.

Answer 1

You're overwriting your $step2 variable
change your code so it becomes
<?php
$CheckQuery = mysqli_query($GLOBALS["___mysqli_ston"],
"SELECT * FROM `logedfeeds`
WHERE ip='127.0.0.1'
GROUP BY user_id
ORDER BY `id`
DESC LIMIT 1000000");
//create table
$step1 = '<center><table border="1"><tr><td><b>UserID</b></td></tr>';
$step2 = '';
while($row = mysqli_fetch_assoc($CheckQuery)){
$userip = $row['user_id'];
$step2 .= '<tr><td>' . $userip . '</td></tr>';
}
echo "$step1 $step2 </table></center>";
?>
You first declare the $step2 variable outside your while loop and keep concatenating it then you echo it outside the loop.

Answer 2

Try this query:
SELECT * FROM logedfeeds
WHERE ip LIKE '%127.0.0.1%'
GROUP BY user_id
ORDER BY id
DESC LIMIT 1000000