Is it possible to retrieve the rowid of the last inserted Oracle row in PHP? I was trying:
$statement = oci_parse($conn, "INSERT INTO myTable (...) VALUES ( ...)");
$results = oci_execute($statement);
while($row = oci_fetch_assoc($statement)) {
$rowid = $row['ROWID'];
}
With no luck. I'm getting the error define not done before fetch or execute and fetch at the fetch line.
Declare:
$var = "AAAV1vAAGAAIb4CAAC";
Use:
INSERT INTO myTable (...) VALUES ( ...)
RETURNING RowId INTO :p_val
Bind your variable to a PHP variable:
oci_bind_by_name($statement, ":p_val", $val, 18);
As the previous answer was not really clear to me because it lacks some important information I will point out a similar approach.
In your SQL statement, add the RETURNING INTOclause.
$statement = oci_parse($conn, "INSERT INTO myTable (...) VALUES ( ...) RETURNING ID INTO :id");
Here ID is the name of the column you want to return. Before executing the $statement, you need to bind a PHP variable to your return value. Here I used $returnId (you don't need to declare it beforehand or assign any default value).
oci_bind_by_name($statement, ":id", $returnId);
Only after binding the variable, the statement can be executed.
$success = #oci_execute($statement);
$returnId now has the value of the ID column inserted previously.
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Is it possible to retrieve the rowid of the last inserted Oracle row in PHP? I was trying:
$statement = oci_parse($conn, "INSERT INTO myTable (...) VALUES ( ...)");
$results = oci_execute($statement);
while($row = oci_fetch_assoc($statement)) {
$rowid = $row['ROWID'];
}
With no luck. I'm getting the error define not done before fetch or execute and fetch at the fetch line.
Declare:
$var = "AAAV1vAAGAAIb4CAAC";
Use:
INSERT INTO myTable (...) VALUES ( ...)
RETURNING RowId INTO :p_val
Bind your variable to a PHP variable:
oci_bind_by_name($statement, ":p_val", $val, 18);
As the previous answer was not really clear to me because it lacks some important information I will point out a similar approach.
In your SQL statement, add the RETURNING INTOclause.
$statement = oci_parse($conn, "INSERT INTO myTable (...) VALUES ( ...) RETURNING ID INTO :id");
Here ID is the name of the column you want to return. Before executing the $statement, you need to bind a PHP variable to your return value. Here I used $returnId (you don't need to declare it beforehand or assign any default value).
oci_bind_by_name($statement, ":id", $returnId);
Only after binding the variable, the statement can be executed.
$success = #oci_execute($statement);
$returnId now has the value of the ID column inserted previously.
I have a query, and I want to get the last ID inserted. The field ID is the primary key and auto incrementing.
I know that I have to use this statement:
LAST_INSERT_ID()
That statement works with a query like this:
$query = "INSERT INTO `cell-place` (ID) VALUES (LAST_INSERT_ID())";
But if I want to get the ID using this statement:
$ID = LAST_INSERT_ID();
I get this error:
Fatal error: Call to undefined function LAST_INSERT_ID()
What am I doing wrong?
That's because that's an SQL function, not PHP. You can use PDO::lastInsertId().
Like:
$stmt = $db->prepare("...");
$stmt->execute();
$id = $db->lastInsertId();
If you want to do it with SQL instead of the PDO API, you would do it like a normal select query:
$stmt = $db->query("SELECT LAST_INSERT_ID()");
$lastId = $stmt->fetchColumn();
lastInsertId() only work after the INSERT query.
Correct:
$stmt = $this->conn->prepare("INSERT INTO users(userName,userEmail,userPass)
VALUES(?,?,?);");
$sonuc = $stmt->execute([$username,$email,$pass]);
$LAST_ID = $this->conn->lastInsertId();
Incorrect:
$stmt = $this->conn->prepare("SELECT * FROM users");
$sonuc = $stmt->execute();
$LAST_ID = $this->conn->lastInsertId(); //always return string(1)=0
You can get the id of the last transaction by running lastInsertId() method on the connection object($conn).
Like this $lid = $conn->lastInsertId();
Please check out the docs https://www.php.net/manual/en/language.oop5.basic.php
I'm sorry about my PHP skills, but I'm just not figuring out how to do this simple task which is INSERT a new row and save its ID into a variable.
Here's what I got:
// mysql inserting a new row
$sql = "INSERT INTO `order` (orderTitle, orderDescription, orderPrice,userID, categoryID)
VALUES('$title', '$description','$price','$userID','$category');";
$sql .= "SELECT LAST_INSERT_ID();";
$result = mysqli_multi_query($con,$sql);
$result_get_id= mysqli_next_result($con);
$row = mysqli_fetch_row($result_get_id);
$order_id = $row[0]; // <-- how to get this value??
I realized row[0] doesn't work, which is why I would like to know how to extract the LAST_INSERT_ID() value correctly.
A couple of things here...
Don't use mysqli_multi_query - it's unnecessary in your example. Use mysqli_query on the INSERT only. No need to query last insert id in SQL.
To get the last insert id, call mysqli_insert_id directly after your INSERT query. You can assign this to a variable, such as $order_id = mysqli_insert_id();
The database class you're using has built in functions for this e.g. mysqli_insert_id(), or for PDO $db->lastInsertId().
$mysqli->query("INSERT INTO order ... ");
printf ("Primary key of new record: %d.\n", $mysqli->insert_id);
http://php.net/manual/en/mysqli.insert-id.php
I'm using Lumen 5.1 and running raw SQL queries, using the DB facade.
How can I get the row's id after performed an insert query?
For example:
$rowId = DB::insert("insert into `customers` (name) values ('Tom')");
echo $rowId; // 1
The variable $rowId should then contains the db row's id.
I think you may have to get a handle to the underlying PDO object and then us that to get the new insert id like so
$pdo = DB::connection()->getPdo();
$result = DB::insert("insert into `customers` (name) values ('Tom')");
if ( $result ) {
$rowId = $pdo->lastInsertId();
}
Or maybe even simplier
$result = DB::insert("insert into `customers` (name) values ('Tom')");
if ( $result ) {
$rowId = DB::connection() -> getPdo() -> lastInsertId();
}
Not tested, just extrapolated from the manual
I need to insert encrypted values in mysql table, but when I use traditional pdo method to insert its inserting the data in wrong format. ex: I insert aes_encrypt(value, key) in place of inserting encrypted value its inserting this as string.
Following is the code :
$update = "insert into `$table` $cols values ".$values;
$dbh = $this->pdo->prepare($update);
$dbh->execute($colVals);
$arr = array("col"=>"aes_encrypt ($val, $DBKey)");
I know i am doing it wrong, but not able to find correct way.
You are almost there, here is a simplified version:
<?php
$sql = "insert into `users` (`username`,`password`) values (?, aes_encrypt(?, ?))";
$stmt = $this->pdo->prepare($sql);
// Do not use associative array
// Just set values in the order of the question marks in $sql
// $fill_array[0] = $_POST['username'] gets assigned to first ? mark
// $fill_array[1] = $_POST['password'] gets assigned to second ? mark
// $fill_array[2] = $DBKey gets assigned to third ? mark
$fill_array = array($_POST['username'], $_POST['password'], $DBKey); // Three values for 3 question marks
// Put your array of values into the execute
// MySQL will do all the escaping for you
// Your SQL will be compiled by MySQL itself (not PHP) and render something like this:
// insert into `users` (`username`,`password`) values ('a_username', aes_encrypt('my_password', 'SupersecretDBKey45368857'))
// If any single quotes, backslashes, double-dashes, etc are encountered then they get handled automatically
$stmt->execute($fill_array); // Returns boolean TRUE/FALSE
// Errors?
echo $stmt->errorCode().'<br><br>'; // Five zeros are good like this 00000 but HY001 is a common error
// How many inserted?
echo $stmt->rowCount();
?>
you can try it like this.
$sql = "INSERT INTO $table (col) VALUES (:col1)";
$q = $conn->prepare($sql);
$q->execute(array(':cols' => AES_ENCRYPT($val, $DBKey)));