Hello im trying to delete which ever value is selected in a drop down list.
I cant seem to understand what is going on
I have 2 pages 1 with my connection and functions to view the table in a drop down (which works) and a delete function (which doesn't seem to work) and another to call the function in and to delete which ever value is selected.
connection.php
<?php
//Connect to the database
function getSQLConnection() {
$mysqlConnection = new PDO('mysql:host=localhost;dbname=isad235_100000', "root", "");
return $mysqlConnection;
}
//Get all results from members table
function getResults($tablename) {
$sql = "SELECT * FROM " . $tablename;
$mysqlConnection = getSQLConnection();
$ResultSet = $mysqlConnection->query($sql);
return $ResultSet;
}
//Delete results from members table
function deleteValue($id) {
$sql = "DELETE FROM members WHERE member_id = '$id'";
$mysqlConnection = getSQLConnection();
$ResultSetting = $mysqlConnection->query($sql);
return $ResultSetting;
}
?>
delete.php
<?php
include_once 'connection.php';
?>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add</title>
</head>
<body>
<h1> Delete a Member from the Members Table. </h1>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method='post'>
Delete Member:
<select name='members' value='members'id="Mmembers">
<?php
$results = getResults('members');
if ($results) {
foreach ($results as $row) {
echo '<option value="' . $row['member_id'] . '">' . $row['name'] . '</option>';
}
}
else
echo '<option value="0"0"> No Data</option>';
?>
</select>
<input type="submit" id="delete" value="Delete"/>
<br/>
<br/>
</form>
<?php
if (isset($_POST['members'])) {
$ResultSetting = deleteValue(($_POST['members']));
}
?>
<br/>
<br/>
<form action='index.php' method='GET'>
Go Back:
<input type="submit" name="submit" value="Return"/>
</form>
<br/>
</body>
</html>
I ran your code and don't see any errors with it. Make sure the id column on your 'members' table is called 'member_id'. If there is a discrepancy in the name then the values for the option elements wouldn't be set. Also, the value you just deleted would still appear after the initial page submit. If you reload the page after the submit, you'll see the value has disappeared.
Related
update
Can anyone explain to me why I am getting duplicate messages instead of one?
how can I change my code so that when I type a comment and press "Comment" button, it will only display one message instead of duplicates! When I have one comment boxes it doesn't show duplicate comments, but if I have more than one then it starts duplicating!
COMMENT.INC.PHP
include 'cdbh.inc.php';
function setComments($con)
{
if (isset($_POST['commentSubmit'])) {
$uid = mysqli_real_escape_string($con,$_POST['uid']);
$date = mysqli_real_escape_string($con,$_POST['date']);
$message = mysqli_real_escape_string($con,$_POST['message']);
$sql = "INSERT INTO comments (uid, date, message) VALUES ('$uid','$date','$message')";
$result = mysqli_query($con,$sql);
}
}
function getComments($con)
{
$sql = "SELECT * FROM comments";
$result = mysqli_query($con,$sql);
while ($row=mysqli_fetch_assoc($result)) {
echo $row['uid'];
echo ":";
echo $row['message']."<br><br>";
}
}
page code
<?php
date_default_timezone_set('America/Los_Angeles');
include 'comment.inc.php';
include("connection.php");
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<link href="comment.css" rel ="stylesheet">
</head>
<body>
<?php
$sql="Select * from tbl_images";
$result=mysqli_query($connection,$sql);
while ($row=mysqli_fetch_array($result)) {
?>
<img src="images/<?php echo $row['images_name'] ?>" width="200px" height="200px">
<?php
echo "<form method ='POST' action ='".setComments($con)."'>
<input type ='hidden' name ='uid' value='unknown'>
<input type ='hidden' name ='date' value='".date('Y-m-d H:i:s')."'>
<textarea name='message'></textarea>
<button type ='submit' name='commentSubmit'>Comment</button>
</form>";
}
getComments($con);
?>
</body>
</html>
Maybe you are submiting all your forms instead of one..
check your database in order to know from what img comes each message.
If you have other code like javascript, you should post it.
I want to print the name and last name of an ID entered in the text box. Here is the PHP and HTML code:
<head>
<title>
Search your name by ID
</title>
</head>
<?php
if(isset($_POST["searchname"]))
{
$id = $_POST["searchname"];
$connect = new mysqli("localhost","adarsh","Yeah!","adarsh");
$a = mysql_query("Select * from users where id='$id'",$connect);
$row = mysql_fetch_assoc($a);
echo "$row[0] , $row[1] , $row[2]";
}
else
{
echo "error";
}
?>
<body>
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<input type="text" maxlength="6" name="searchname">
<input type="Submit" name="Submit">
</form>
</body>
Output when I enter ID:
, ,
There are entries in the MySQL table but I am unable to fetch them. What is wrong with my code?
UPDATE: I have also tried mysql_fetch_array but it is not working.
Main problem is that you're miximg mysqli and mysql. These are absolutely different APIs.
Assuming you have
$id = $_POST["searchname"];
$connect = new mysqli("localhost","adarsh","Yeah!","adarsh");
Next you should:
$result = $connect->query("Select * from users where id='$id'");
Then get results:
while ($row = $result->fetch_assoc()) {
var_dump($row);
}
And of course, instead of directly putting values into your query use prepared statements.
Update:
about mistakes:
Your main mistake is mixing apis. When you use mysql (which is deprecated and you mustn't use it anymore) you can't use any of mysqli functions and vice versa.
Next - as you create mysqli object with new, you should work in object-oriented style, i.e. calling methods from your mysqli object.
Try this:
<html>
<head>
<title>
Search your name by ID
</title>
</head>
<body>
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<input type="text" maxlength="6" name="searchname">
<input type="Submit" name="Submit">
</form>
</body>
</html>
<?php
if(isset($_POST["searchname"])){
$id = $_POST["searchname"];
$connect = mysql_connect("localhost","adarsh","Yeah!","adarsh");
$result = mysql_query("Select * from users where id='$id'",$connect);
$row = mysql_fetch_assoc($result);
print_R($row);
}else{
echo "there is something wrong";
}
I have a database setup to register members for a members only area of a site. I can echo all of the registered members with a checkbox so that I can choose to delete an individual member from an admin page, but I cant seem to figure out how to get the member chosen to be deleted when the submit button is clicked. I have tried to do it on a single page and on a 2 page process, first page lists the members with the checkbox which works to the point of choosing the member to be deleted, the difficulty I seem to be having is getting the members detail passed to the delete section of the code. Could anyone assist me please.
here is the delete_user.php which lists the members with a checkbox
<?php
include_once 'db_connect.php';
include_once 'functions.php';
sec_session_start();
//display users info with checkbox to delete
$sql = "SELECT * FROM `members` LIMIT 0, 30 ";
$result = mysqli_query($mysqli, $sql);
while($row = mysqli_fetch_array($result))
{
echo '<input type="checkbox" value="' .$row['username'] . '" name="delete[]" />';
// echo '<input type='checkbox' value='' .$row['adminid'] . '' name='delete[]' />';
echo ' ' .$row['username'];
echo ' ' .$row['email'];
echo '<br />';
}
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Delete Member</title>
</head>
<body>
<form>
<input name="submit" type="submit" formaction="delete_user.inc.php" formmethod="POST" value="Delete User">
</form>
</body>
</html>
here is the process page delete_user.inc.php
<?php
include_once 'db_connect.php';
include_once 'functions.php';
sec_session_start();
if ($_SERVER["REQUEST_METHOD"] == "POST") {
foreach($_POST['delete'] as $delete_user)
{
$sql = "DELETE FROM members WHERE memberid = '$delete_user'";
mysqli_query($mysqli, $sql) or die ('die now');
}
echo 'user has been deleted.<br />';
}
?>
You must render your checkboxes inside your form:
<?php
include_once 'db_connect.php';
include_once 'functions.php';
sec_session_start();
//display users info with checkbox to delete
$sql = "SELECT * FROM `members` LIMIT 0, 30 ";
$result = mysqli_query($mysqli, $sql);
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Delete Member</title>
</head>
<body>
<form type="POST" action="delete_user.inc.php">
<?php while($row = mysqli_fetch_array($result)): ?>
<label>
<?php echo $row['username']; ?> - <?php echo $row['email']; ?>
<input type="checkbox" value="<?php echo $row['memberid']; ?>" name="delete[]" />
</label>
<?php endwhile; ?>
<input name="submit" type="submit" value="Delete User" />
</form>
</body>
</html>
Then on your delete process:
<?php
include_once 'db_connect.php';
include_once 'functions.php';
sec_session_start();
if (isset($_POST['submit'])) {
foreach($_POST['delete'] as $delete_user) {
$sql = "DELETE FROM members WHERE memberid = ?";
$stmt = $mysqli->prepare($sql);
$stmt->bind_param('i', $delete_user);
$stmt->execute();
}
echo 'user has been deleted.<br />';
}
?>
I'm new to PHP and MySQL. I am trying to make a simple search form using which I would want to show the results from the database based on the input text entered in the form.
My code is like this:
Form.php
<!DOCTYPE html>
<html lang="en">
<html>
<head>
<title>test</title>
</head>
<body>
<form action="search.php" method="GET" id="form">
Name: <input type="text" name="name" >
Age:<input type="text" name="age">
Search<input type="submit" name="submit" id="Search" Value="Search">
</form>
</body>
</html>
Connect.php
<?php
$connect = mysql_connect('localhost','$user','$password');
if(!$connect){
die('Could not connect'.mysql_error() );
}
$db_selected = mysql_select_db('test');
if(!$db_selected){
die('wrong'.mysql_error() );
}
?>
Search.php
<?php
include("includes/connect.php");
$name=$_GET['name'];
echo $name;
$query = "SELECT * FROM `cats` WHERE name='\$name'";
$results= mysql_query($query);
if (!empty($results)){
echo "query successful" ;
exit;
}
$row=mysql_fetch_assoc($results);
echo "Age:".$row['age'];
echo "Name:".$row['name'];
?>
The echo $names ouputs the result correctly and so does echo "query successful".
However the
echo "Age:".$row['age'];
echo "Name:".$row['name'];
only echo's the string part and the query does not seem to fetch any results.
I tried changing the mysql_fetch_assoc to mysql_fetch_array, but it does not do anything either. Could anyone tell me what am i doing wrong here. My DB table has two columns and two rows.
You're escaping the $ in the variable by doing \$.
Try:
$query = "SELECT * FROM `cats` WHERE name='$name'";
EDIT
From the discussion below.
The problem with the undefined index is the fact that you are using $row['age'] when really, the column name in the database is Age. Therefore you must use $row['Age'] when referring to the item. The same goes for name.
$query = "SELECT * FROM `cats` WHERE name='" . $name . "'";
or without concatenation
$query = "SELECT * FROM `cats` WHERE name='$name'";
This should work:
$query = "SELECT * FROM cats WHERE name = '$name'";
Also, when you call "exit;" in the following block it will cancel the execution of the rest of your script:
if (!empty($results)){
echo "query successful" ;
exit;
}
I have a simple dropdown menu which posts the result to itself but when i choose one of the options in the drop down menu it does not echo back the result as expected.
I'm sure i've just missed out something simple but can't spot it. Any ideas? The form posts but does not echo back $user_settings.
<?php
include "functions.php";
connect();
$sql="SELECT user_id, user_realname FROM users ORDER BY user_realname ASC";
$result=mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
$name=$row['user_realname'];
$options.="<OPTION VALUE=>".$name.'</option>';
}
if(isset($_POST['submit'])){
$user_realname = $_POST['username_select'];
$user_select = mysql_query("SELECT user_id, user_realname FROM users WHERE user_realname = '$user_realname'")
or die ("Could not get user data");
while($row = mysql_fetch_array($user_select)){
$user_settings = $row['user_id'];
echo $user_settings;
}
}
?>
<html>
<head>
<body>
<form action="<?php echo $PHP_SELF;?>" method="POST">
<tr><label>Choose User to Edit</tr>
<tr><SELECT NAME="username_select"><OPTION VALUE=""></option>User's Name<?php echo $options;?></SELECT></label></tr>
<tr><input type="submit" value="submit" name="submit"></tr>
</form>
<?php echo $user_settings;?>
<br/>
Go Back
</body>
</head>
</html>
User $_SERVER['PHP_SELF'] instead of $PHP_SELF