In my PHP program, I'm using $_SERVER to log the page's date visited:
$dateStamp = $_SERVER['REQUEST_TIME'];
The result is that the $dateStamp variable contains a Unix timestamp like:
1385615749
What's the simplest way to convert it into a human-readable date/time (with year, month, day, hour, minutes, seconds)?
This number is called Unix time. Functions like date() can accept it as the optional second parameter to format it in readable time.
Example:
echo date('Y-m-d H:i:s', $_SERVER['REQUEST_TIME']);
If you omit the second parameter the current value of time() will be used.
echo date('Y-m-d H:i:s');
Your functional approch to convert timestamp into Human Readable format are as following
function convertDateTime($unixTime) {
$dt = new DateTime("#$unixTime");
return $dt->format('Y-m-d H:i:s');
}
$dateVarName = convertDateTime(1385615749);
echo $dateVarName;
Output :-
2013-11-28 05:15:49
Working Demo
<?php
$date = new DateTime();
$dateStamp = $_SERVER['REQUEST_TIME'];
$date->setTimestamp($dateStamp);
echo $date->format('U = Y-m-d H:i:s') . "\n";
?>
you can try this
<?php
$date = date_create();
$dateStamp = $_SERVER['REQUEST_TIME'];
date_timestamp_set($date, $dateStamp);
echo date_format($date, 'U = D-M-Y H:i:s') . "\n";
?>
this code will work for you
$dateStamp = $_SERVER['REQUEST_TIME'];
echo date('d-M-Y H:i:s',strtotime($dateStamp));
REQUEST_TIME - It is unix timestamp - The timestamp of the start of the request.
$dateStamp = $_SERVER['REQUEST_TIME'];
echo date('d m Y', $dateStamp);
OR
$date = new DateTime($dateStamp);
echo $date->format('Y-m-d');
Related
In my postgresql, the I have the following column named "created" that has the type timestamp with timezone
So I inserted the record according to the format as such which I believe is UTC.
2015-10-02 09:09:35+08
I am using php Carbon library so i did the following:
$date = Carbon\Carbon::parse('2015-10-02 09:09:35+08');
echo $date->->toDatetimeString();
//gives result as 2015-10-02 09:09:35
How can I use the library to echo the correct timezone which includes the adding of the +8 in the above datetime format? The timzezone that I am using is "Asia/Singapore".
The time should be printed to local timing which is 2015-10-02: 17:09:35:
Try this:
$timestamp = '2015-10-02 16:34:00';
$date = Carbon::createFromFormat('Y-m-d H:i:s', $timestamp, 'Asia/Singapore');
Try this using standard PHP:
$raw = '2015-10-02 09:09:35+08';
$date = substr($raw,0,19);
$tzOffset = (strlen($raw) > 19) ? substr($raw,-3) : 0;
$timestamp = strtotime($date) + (60 * 60 * $tzOffset);
$localTime = date('Y-m-d H:i:s',$timestamp);
echo 'local time:['.$localTime.']';
The result is:
local time:[2015-10-02 17:09:35]
This will also work without a time zone offset or a negative one.
You can do this using native php without using Carbon:
$time = '2015-10-02 16:34:00+08';
$date = DateTime::createFromFormat('Y-m-d H:i:s+O', $time);
print $date->format('Y-m-d H:i:s') . PHP_EOL;
$date->setTimeZone(new DateTimeZone('Asia/Singapore'));
print $date->format('Y-m-d H:i:s') . PHP_EOL;
$date->setTimeZone(new DateTimeZone('Etc/UTC'));
print $date->format('Y-m-d H:i:s') . PHP_EOL;
I have today date and i want to reduce hours\days from it. i get the "hours to reduce interval" in int that indicate number of days.
I tried something like this:
$today_date = date('Y-m-d H:i:s');
$temp_interval_date = $settings->days_back;
$interval_date = date('H',$temp_interval_date*24);
$final = $temp_interval_date - $interval_date;
My final goal is to get todaydate - interval period in this format
'Y-m-d H:i:s'
I am c# dude :)
Thanks
I'm not entirely clear on what you're asking but I think this is what you're looking for.
$date = new DateTime();
$date->sub(new DatePeriod('P'.$settings->days_back.'D'));
echo $date->format('Y-m-d H:i:s');
You can also do (if you're using PHP 5.2)
$date = new DateTime();
$date->modify('-' . $settings->days_back . ' days'));
echo $date->format('Y-m-d H:i:s');
reference
DateTime()
DatePeriod()
maybe this could be helpful:
echo date('Y-m-d', strtotime('-1 day', date('Y-m-d') ));
Another way to do it
<?php
$temp_interval_date = 2; //in hours (for example =2)
echo date('Y-m-d H:i:s', strtotime('-'.($temp_interval_date*24).' hours',strtotime(date('Y-m-d H:i:s'))));
?>
I have a user input where the user inputs time and date as '9.30am' and '01/02/2012'. I am trying to convert this to a unix timestamp to aid ordering when dragging the data back out of the database but strptime() is confusing me as I am unsure as to whether this is actually returning a unix timestamp that I need.
You can use: strtotime
PHP.net Example:
echo strtotime("now"), "\n";
echo strtotime("10 September 2000"), "\n";
echo strtotime("+1 day"), "\n";
echo strtotime("+1 week"), "\n";
echo strtotime("+1 week 2 days 4 hours 2 seconds"), "\n";
echo strtotime("next Thursday"), "\n";
echo strtotime("last Monday"), "\n";
Using PHP's built-in DateTime class...
$objDate = DateTime::createFromFormat('H:ia d/m/Y', '9:30am 1/2/2012');
$timestamp = $objDate->getTimestamp();
...returns a Unix timestamp.
Documentation:
PHP DateTime Class
a. DateTime::createFromFormat
b. DateTime::getTimestamp
To add your variables, use it like so...
$objDate = DateTime::createFromFormat('H:ia d/m/Y', "$time $date");
$timestamp = $objDate->getTimestamp();
Or...
$time_date = sprintf("%s %s", $time, $date); // concatenates into a single var
$objDate = DateTime::createFromFormat('H:ia d/m/Y', $time_date);
$timestamp = $objDate->getTimestamp();
Note: Make sure that your variables conform with the following...
$time = hh:mm (and "am" or "pm" is appended)
$date = dd/mm/yyyy
You could use strtotime()
Call it by putting in your variables.
strtotime("9.30 1/2/2012");
http://php.net/manual/en/function.strtotime.php
$date = DateTime::createFromFormat('H:ia d/m/Y' '9:30am 1/2/2012');
$timestamp = $date->getTimestamp();
Is what you are looking for. http://www.php.net/datetime
I have $adate; which contains:
Tue Jan 4 07:59:59 2011
I want to add to this date the following:
$duration=674165; // in seconds
Once the seconds are added I need the result back into date format.
I don't know what I'm doing, but I am getting odd results.
Note: both variables are dynamic. Now they are equal to the values given, but next query they will have different values.
If you are using php 5.3+ you can use a new way to do it.
<?php
$date = new DateTime();
echo $date->getTimestamp(). "<br>";
$date->add(new DateInterval('PT674165S')); // adds 674165 secs
echo $date->getTimestamp();
?>
Just use some nice PHP date/time functions:
$adate="Tue Jan 4 07:59:59 2011";
$duration=674165;
$dateinsec=strtotime($adate);
$newdate=$dateinsec+$duration;
echo date('D M H:i:s Y',$newdate);
Given the fact that $adate is a timestamp (if that's the case), you could do something like this:
$duration = 674165;
$result_date = strtotime(sprintf('+%d seconds', $duration), $adate);
echo date('Y-m-d H:i:s', $result_date);
// add 20 sec to now
$duration = 20;
echo date("Y-m-d H:i:s", strtotime("+$duration sec"));
Do this:
$seconds = 1;
$date_now = "2016-06-02 00:00:00";
echo date("Y-m-d H:i:s", (strtotime(date($date_now)) + $seconds));
$current_time_zone = 150;
date("Y-m-d H:i:s",strtotime(date("Y-m-d H:i:s"))+$current_time_zone);
I made this example for a timezone, but if you change some parts it may help you out:
$seconds_to_add = 30;
$time = new DateTime();
$time->setTimezone(new DateTimeZone('Europe/London'));
$time2 = $time->format("Y/m/d G:i:s");
$time->add(new DateInterval('PT' . $seconds_to_add . 'S'));
$timestamp = $time->format("Y/m/d G:i:s");
echo $timestamp;
echo '========';
echo $time2;
Result:
2018/06/17 3:16:23========2018/06/17 3:15:53
It would be easier with DateTime::modify
(new DateTime($str))->modify("+$duration seconds"); //$str is the date in string
I have trouble with strtotime() to resolve my problem of add dynamic data/time value in the current time
This was my solution:
$expires = 3600; //my dynamic time variable (static representation here)
$date = date_create(date('Y-m-d H:i:s')); //create a date/time variable (with the specified format - create your format, see (1))
echo date_format($date, 'Y-m-d H:i:s')."<br/>"; //shows the date/time variable without add seconds/time
date_add($date, date_interval_create_from_date_string($expires.' seconds')); //add dynamic quantity of seconds to data/time variable
echo date_format($date, 'Y-m-d H:i:s'); //shows the new data/time value
font: https://secure.php.net/manual/en/datetime.add.php (consult Object Oriented style too, the Elzo Valugi solution)
(1) https://secure.php.net/manual/en/function.date.php
I am trying to send the time to flash but set to the currently timezone. When you view the below even though the echo date, looks like its working the $time is the same. When i test in flash I get the extra hour added. Any help tips welcome on this one...
$format = "d/m/Y H:m:s";
$timezone = "Europe/Amsterdam";
date_default_timezone_set($timezone);
echo "<h1>Timezone ".$timezone."</h1>";
$date = date($format);
echo "<h3>Date: ".$date."<h3>";
$time = strtotime($date);
echo "<h3>Time: ".$time."<h3>";
$date2 = date($format, $time);
echo "<h3>Reverse: ".$date2."<h3>";
$timezone = "Europe/London";
date_default_timezone_set($timezone);
echo "<h1>Timezone ".$timezone."</h1>";
$date = date($format);
echo "<h3>Date: ".$date."<h3>";
$time = strtotime($date);
echo "<h3>Time: ".$time."<h3>";
$date2 = date($format, $time);
echo "<h3>Reverse: ".$date2."<h3>";
?>
Can't you use the PHP time() object for this? Pass this value:
time()."000" // note the trailing zeroes
Call that serverTime and pass it as a query string:
echo "myFlashFile.swf?serverTime=".time()."000";
Then in your Actionscript:
myDate = new Date();
myDate.setTime(serverTime);
Would some sort of mathematics solve the day? ie:
$time = date("U")+date("Z");
This would work for the timezone ahead, but not so good for behind