I want to display 30 same div. So I am taking for loop with showing 30 div. Now I want div in only one line. If the div is out of screen then it will show horizontal scroll bar.
The code is:
<div id="sort-able" >
<?php for($j=0;$j<30;$j++){?>
<div class = "dragg-able" >Home - <?php echo $j;?></div>
<?php } ?>
</div>
<div id="sort-able" style="width: 100%; overflow-x: scroll; white-space:nowrap;" >
<?php for($j=0;$j<30;$j++){?>
<div class = "dragg-able" style="display:inline; ">Home - <?php echo $j;?></div>
<?php } ?>
</div>
Example: http://kelostrada.pl/test.php
Related
hi this is my code which display images from mysql database
<?php
error_reporting(0);
include_once 'dbconfig.php';
$id=$_POST['id'];
$q="select * from services ";
$qq=mysql_query($q)
or die(mysql_error());
while($row=mysql_fetch_array($qq)){
$s1=$row[image];
?>
<?php
$p1="admin/services/uploads-services/";
echo '<img src="'.$p1.$s1.'" class="img-responsive" alt="Blog Image">'; ?>
<?php } ?>
it appears in vertical way but i want to make it appear in horizontal way
how can i do this ?
If you want images to be in same row, add display: inline-block to them.
.img-responsive {
display: inline-block;
}
Probably because you visualize the images not in a defined col. If you want to visualize 3 images at a line, you should have
<div class="col-md-12">
<div class="col-md-4">
put your image here
</div>
<div class="col-md-4">
put your image here
</div>
<div class="col-md-4">
put your image here
</div>
<div style="width: 1000px;height: 200px;float: left;opacity:0.9;border-color:#cc3e19;border-style:solid;margin-bottom:30px">
<div style="width: 500px;height: 100px;float:left;">
<?php for ($i = 1;$i<=$Breview;$i++) {
print '<span class = "reviewSpan" >★</span>';
}
?>
</div>
</div>
<style>
.reviewSpan{
color: #FFFF00;
}
</style>
I need to add <h2> tag around <span> tag to make star icon bigger but it prints stars vertically , how can i avoid it and make them print horizontally
Try below code-css
<span style="font-size: 50px;">★</span>
i created a header.php for my web site.
For my menu, i created 5 buttons.
When i press on a button it redirect me on the page associated to it.
Until now everything fine.
What i want is, on the current page, my button of the page associated to it change to an other color or background image.
I dont know if we can do that and if i explain myself well.
here my header.php
<div id="main_menu">
<div id="menu_blog"><button onclick="location.href='blog.html'"><h1>Trucs/Astuces</h1></button></div>
<div id="menu_contact"><button onclick="location.href='/contact.php'"><h1>Contact</h1></button></div>
<div id="menu_soumission"><button onclick="location.href='/soumission.php'"><h1>Soumission</h1></button></div>
<div id="menu_realisation"><button onclick="location.href='/realisations.php'">
<h1>Réalisations</h1></button></div>
<div id="menu_service"><button onclick="location.href='/services.php'">
<h1>Services</h1></button></div>
<div id="menu_a_propos"><button onclick="location.href='/a_propos.php'"><h1>L'entreprise</h1></button></div>
</div>
Simple way is use CSS
#yourbutton:hover{
background-color: red;
}
or
#yourbutton:active{
background-color: red;
}
Pass a GET value with each link
<div id="menu_contact"><button onclick="location.href='/contact.php?active=1'"><h1>Contact</h1></button></div>
check the value of active in the button
< button <?php if ($_GET['active']==1) echo 'class="active"'; ?> ..../>
then make a css style for active class
.active{
/*your style here*/
}
Your PHP page:
<div id="main_menu">
<div id="menu_blog">
<button onclick="location.href='/blog.html'" <?php if($_SERVER['REQUEST_URI'] == '/blog.html'){echo 'class="currentPage"'; }?>>
<h1>Trucs/Astuces</h1>
</button>
</div>
… and so on for each menu item ...
</div>
Your CSS:
button.currentPage{
background-color: red;
}
Short version:
add $current_location to every page and name it after it
<?php
$current_location = "a_propos" ;
?>
Check if location is correct, then change background color
<div id="main_menu">
<div id="menu_a_propos"><button <?php if ($current_location == "a_propos");?> style=" background-color: red;"<?php };?> onclick="location.href='/a_propos.php'"><h1>L'entreprise</h1></button></div>
</div>
I want to create tabs that function like toggles, but instead only one toggle can be active at one time. The content of the tab also needs to be above the the tabs themselves. The problem is I am using a loop to generate the content as well as the tabs themselves.
I've got a nice javascript code right here that works perfectly fine. I understand this perfectly as well. The only problem is that it obviously doesn't disable other toggles when another one is clicked. Also having one "tab" / "toggle" always active. Code that could probably check the div id with a prefix of "post" and make all div id's with "post" to display:none besides the one that was clicked on. That would be perfect if that could be possible. Another way I could think of this is putting all the generated content into a container, and it simply disables all id's in the container besides the one that was clicked.
If this code can be modified to achieve that, it would be great. This is some very simple code that I understand very clearly. All I need is that it behaves more like tabs where only one can be active at once.
<script type="text/javascript">
function toggleMeMirror(a){
var e=document.getElementById(a);
if(!e) return true;
if(e.style.display=="none"){
e.style.display="inline"
} else {
e.style.display="none"
}
return true;
}
</script>
HTML / PHP
Loop 1 - The Content
<?php while ($queryepisodemirrors->have_posts()) : $queryepisodemirrors->the_post(); ?>
<?php if(get_post_meta(get_the_ID(), 'parentIDmirror', true) == $postIDCheck) { ?>
<div id="post-<?php the_ID(); ?>" style="display:none;">
<center><?php the_title(); ?><br /><br />
<?php echo get_post_meta(get_the_ID(), 'mirror_embed_code', true); ?>
<?php wprp(true);?>
</center>
</div>
<?php } ?>
<?php endwhile; ?>
Loop 2 - The actual toggles / tabs
<?php while ($queryepisodemirrors->have_posts()) : $queryepisodemirrors->the_post(); ?>
<?php if(get_post_meta(get_the_ID(), 'parentIDmirror', true) == $postIDCheck) { ?>
<div style="float: left; padding: 4px;">
<center>
<div class="post-<?php the_ID(); ?>" onclick="return toggleMeMirror('post-<?php the_ID(); ?>')" >
<div style="overflow: hidden; width: 150px; height: 100px;">
<div style="background: rgb(0, 0, 0) transparent; /* fallback color */ background: rgba(0, 0, 0, 0.8); color: white; padding: 2px;">
<center>
<?php echo get_post_meta(get_the_ID(), 'video_provider', true);
echo ' Mirror';?>
</center>
</div>
<img src="<?php echo $thumbnail_src; ?>" width="150px"/>
</div>
</div>
</center>
</div>
<?php } ?>
<?php endwhile; ?>
This is also tagged jquery so I'll just recommend that you include the jquery library and include:
$('.someclass').hide();
as the first line in the toggleMeMirror function.
Then, make sure that each of your looped content divs exist in the class "someclass".
like:
foreach($this as $that) {
print "<div class='someclass'>$that</div>";
}
then
function toggleMeMirror(a){
// hide all
$('.someclass').hide();
// show one
var e=document.getElementById(a);
if(!e) return true;
if(e.style.display=="none"){
e.style.display="inline"
} else {
e.style.display="none"
}
return true;
}
You can try something like this DEMO
HTML Code
<div id="one"><img src='http://img.widgetbox.com/thumbs/302/8fb0669c-72ee-454d-a08f-9700b8a5270a.png?4' height='50px' widht='50px' ></div><br>
<div id="two"><img src='http://ww2.valdosta.edu/~mecarter/Spongebob%20Reading.png' height='50px' widht='50px' ></div><br>
<div id="three"><img src='http://www.cliffdweller.com/blogPhotos/wrappingpaperbase/Spongebob%20Waving.png' height='50px' widht='50px' ></div><br><br>
<div id="thumb"><img src='http://img.widgetbox.com/thumbs/302/8fb0669c-72ee-454d-a08f-9700b8a5270a.png?4' height='200px' widht='200px' ></div>
jQuery
$("#one").click(function() {
$("#thumb").html("<img src='http://img.widgetbox.com/thumbs/302/8fb0669c-72ee-454d-a08f-9700b8a5270a.png?4' height='200px' widht='200px' >");
});
$("#two").click(function() {
$("#thumb").html("<img src='http://ww2.valdosta.edu/~mecarter/Spongebob%20Reading.png' height='200px' widht='200px' >");
});
$("#three").click(function() {
$("#thumb").html("<img src='http://www.cliffdweller.com/blogPhotos/wrappingpaperbase/Spongebob%20Waving.png' height='200px' widht='200px' >");
});
So I want to position my a meta-data div in the corner of every post image, but all the images are different sizes. How do I do this?
Heres an example of what I need:
This is the loop:
<div id="images">
<?php wp_get_attachment_image(); ?>
</div>
<div id="date">
<?php get_the_date(); ?>
</div>
I posted this # wordpress.stackexchange but they said to post it here
It doesn't matter what size the image is. You have to give the container div a position:relative and the corner div a position:absolute with top:0 and left:0
HTML:
<div id="images"><?php wp_get_attachment_image(); ?>
<div id="date"><?php get_the_date(); ?></div>
</div>
*note date is inside the image tag!
CSS:
#images{
position:relative;
}
#date{
position:absolute;
top:0;
left:0;
}