Parsing a string that contain Numbers PHP - php

Question

I have a string that contains 2 informations (1.A Boolean/2.Something(could be number, letter, special chars and could be of any length)).
2 is a user input.
Exemples:
(part 1)"true".(part 2)"321654987" => "true321654987"
Could also be
"false321654987" or "trueweiufv2345fewv"
What I need is a way of parsing trought the string to check first if 1 is true (if its false do nothing), if it is true I need to check if to following part is a positive number higher than 0 (must accepte any number higher than 0 even decimal BUT not bin or hex (well... could be 10 but its would mean ten not two)).
Here is what I tried:
//This part is'nt important it work as it should....
if(isset($_POST['validate']) && $_POST['validate'] == "divSystemePositionnement")
{
$array = json_decode($_POST['array'], true);
foreach($array as $key=>$value)
{
switch($key)
{
case "txtFSPLongRuban":
//This is the important stuff HERE.....
if(preg_match('#^false.*$#', $value))//If false do nothing
{}
else if(!preg_match('#^true[1-9][0-9]*$#', $value))//Check if true and if number higher than 0.
{
//Do stuff,
//Some more stuff
//Just a bit more stuff...
//Done! No more stuff to do.
}
break;
//Many more cases...
}
}
}
As you can see I use regEx to parse trought to string. But it does'nt match decimal number.
I know how to do a regEx to parse decimal this is'nt the question.
The question is:
is there already a function in php that match the parsing I need?
If not, do any of you know a more efficient way to do the parsing or should I just add to my regEx the decimal part?
I was thinking something like :
test = str_split($value, "true")
if(isNumeric(test[1]) && test[1] > 0)
//problem is that isNumeric accepte hex and a cant have letter in there only straight out int or decimal number higher than 0.
Any idea??
Thank you so much for the help!

Answer 1

Use substr : documentation
if(substr($value, 0, 4) == "true"){
$number_part = substr($value, 5);
if(((int) $number == $number) || ((float) $number == $number)){
//do something...
}
}

Answer 2

You can do this:
case "txtFSPLongRuban":
if (preg_match('~^true(?=.*[^0.])([0-9]+(?:\.[0-9]+)?)$~', $value, $match))
{
// do what you want with $match[1] that contains the not null number.
}
break;
The lookahead (?=.*[^0.]) checks if there is somewhere a character that is not a 0 or a .

Answer 3

This oughta do the trick, and handle both types of values:
preg_match('/^(true|false)(.*)$/', $value, $matches);
$real_val = $matches[2];
if ($matches[1] == 'true') {
... true stuff ...
} else if ($matches[1] == 'false') {
... false stuff ...
} else {
... file not found stuff ...
}

Answer 4

Have a try with:
else if(!preg_match('#^true([1-9][0-9]*(?:\.[0-9]*)?$#', $value))

Answer 5

Have a look at ctype_digit:
Checks if all of the characters in the provided string, text, are numerical.
To check for decimals you can use filter_var:
if (filter_var('123.45', FILTER_VALIDATE_FLOAT) !== false) {
echo 'Number';
}