In the following code, if I set $what to 'red', it doesn't find it, whereas it finds green and blue. Why and how to make it find red as well?
$where = 'red,green,blue';
$what = 'blue';
if (strpos($where, $what) == true) {
echo 'found';
}
strpos returns the index of the found string. In this case the index is 0 and your check for == true will fail. Try:
strpos($where, $what) !== false
The documentation provides more information.
strpos will return false if your string isn't there. Otherwise, it returns the position of your string.
In this case, 'red' is at the start of the string, which means that it's at position 0; and 0 evaluates to false.
You need to do a boolean compare on the result:
if(strpos($word, 'red') === false)
Related
I am trying to filter a specific column in an array in php using the code below:
(strpos( 'meeting',$event['categories'] ) == false )
It is not working actually. An example of what [categories] hold is:
$event['categories'] = 'meeting;skype'
Thanks in advance!
You need to flip the arguments to strpos():
if (strpos($event['categories'], 'meeting') === false) {
echo $event['categories'] . ' does not contain "meeting"';
}
Also, use strict comparison (=== vs ==), as meeting could be at the start of the string, and then strpos() would return 0, which would evaluate to false (which would be wrong in that case).
For reference, see:
http://php.net/manual/en/function.strpos.php
For an example, see:
https://3v4l.org/Ab4ud
I think you should use === not == and also flip the arguments
(strpos($event['categories'] , 'meeting') === false )
strpos could return 0 or false and when you use == then zero is like false
see compression operators
see strpos() docs
<?php
$event = ['categories' => 'meeting;skype'];
$needle = 'meeting';
$haystack = $event['categories'];
if( ($pos = strpos( $haystack, $needle )) === false){
echo "\n$needle not found in $haystack";
}
else
{
echo "\n$needle exists at position $pos in $haystack";
}
See demo
The two things to watch out for are the order of the parameters for strpos() as well as doing a strict comparison using the identity operator ("===") so that when the 'needle' appears at position zero of the 'haystack' it's not mistakenly deemed a false result which occurs if you use the equality operator ("=="), given that in PHP zero == false.
Good day,
I have the following string :
[Star]ALERT[Star]Domoos detects blabla[blabli]
For strange reasons, the code below does not detect the star at the very first character. I read in the php documentation that the first character has an index of 0. However, if I am looking for the '[', the function works very well.
What I am trying to achieve is to ensure that the first character of my string is really a * (star). Strangely, if I enter $pos1 = strpos($inputString, '*', 1), the star shown at position '6' would be returned.
I don't quite understand why my code does not work as expected (i.e. does not enter into the 'true' condition)
$inputString = '*ALERT*Domoos detects blabla[blabli]';
$pos1 = strpos($inputString, '*', 0);
if ($pos1 == True)
{
echo 'position' . $pos1;
}
Do you have any suggestion that would help me to overcome this issue?
Thanks a lot for your appreciated support.
change condition to
if ($pos1 != False)
{
echo 'position' . $pos1;
}
as strpos will return position at (integer) or False
If you look at the manual:
Find the numeric position of the first occurrence of needle in the
haystack string.
In your test case, the numeric position is 0 and 0 != true.
Also see the warning in the manual:
Warning This function may return Boolean FALSE, but may also return a
non-Boolean value which evaluates to FALSE. Please read the section on
Booleans for more information. Use the === operator for testing the
return value of this function.
So the condition you really want is:
if ($pos1 !== false)
You don't need strpos. As string is an array of characters so you can do like this
$inputString = '*ALERT*Domoos detects blabla[blabli]';
$compare_char= $inputString[0];
if($compare_char=="*"){
//do something.
}
As i suppose it is fast too rather than on searching through strpos
Actually issue is that when you are looking at 0 position the value which you get is 0 and when you are checking that in if condition with True, it will always fail because 0 will be evaluated as False. To resolve this you can use
if($pos1 !== False)
The function strpos returns false if there is no existence of what you search. So make a check like the following:
$inputString = '*ALERT*Domoos detects blabla[blabli]';
$pos1 = strpos($inputString, '*', 0);
return $pos1 !== false ? 'position ' . $pos1 : '..';
$pos1 returns 0 and this is treat as False so we cant take it as True so we can use here isset function.
$inputString = '*ALERT*Domoos detects blabla[blabli]';
$pos1 = strpos($inputString, '*',0);
if (isset($pos1))
{
echo 'position' . $pos1;
}
Right now I use stristr($q, $string) but if
$string = "one monkey can jump 66 times";
$q = "monkey 66";
I want to find out if this string contains both monkey and 66.
How can i do that?
you could use both stristr and strpos.
as it is reported in this post, the second method is faster and less memory intensive.
well, check this lines out:
// here there are your string and your keywords
$string = "one monkey can jump 66 times";
$q = "monkey 66";
// initializate an array from keywords in $q
$q = explode(" ", $q);
// for every keyword you entered
foreach($q as $value) {
// if strpos finds the value on the string and return true
if (strpos($string, $value))
// add the found value to a new array
$found[] = $value;
}
// if all the values are found and therefore added to the array,
// the new array should match the same object of the values array
if ($found === $q) {
// let's go through your path, super-man!
echo "ok, all q values are in string var, you can continue...";
}
if(stristr('monkey', $string) && stristr('66', $string)) {
//Do stuff
}
simply post your variable value by giving them a variable $monkey,$value ($monkey jumps $value) and then fetch its value
You can use the strpos() function which is used to find the occurrence of one string inside another one:
$a = 'How are you?';
if (strpos($a, 'are') !== false) {
echo 'true';
}
Note that the use of !== false is deliberate (neither != false nor === true will work); strpos() returns either the offset at which the needle string begins in the haystack string, or the boolean false if the needle isn't found. Since 0 is a valid offset and 0 is "falsey", we can't use simpler constructs like !strpos($a, 'are').
I know the $a variable with the tag is not properly formatted, however that's irrelevant to the issue.
The issue is that strpos is looking for a forward slash, /, in the value of each key in the array, but it is not printing.
$a = '<a target="" href="/test/url">test';
$a_expanded = explode("\"", $a);
echo print_r($a_expanded);
foreach($a_expanded as $num => $aspect) {
echo $aspect;
if ($contains_path = strpos($aspect, '/')) {
echo $a_expanded[$num];
}
}
It echos the array and each aspect, but will not echo the string with the forward slashes when found by strpos.
if ($contains_path = strpos($aspect, '/'))
should be
$contains_path = strpos($aspect, '/');
if ($contains_path !== false)
as strpos will return 0 when the string directly starts with a / (as it does, in your case). If strpos has no match, it returns false.
if (0) and if (false) are the same. So you need to do strict comparison (=== or !==) here.
The position of found string might be 0 which is counted as false, you need to compare as ===
if (false !== $contains_path = strpos($aspect, '/')) {
echo $a_expanded[$num];
}
strpos() could either return FALSE, 0, or a non-zero value.
If the needle occurs at the beginning of the haystack, strpos() returns 0.
If it occurs elsewhere, it returns the respective position of the needle in the haystack.
If needle wasn't found in the haystack, strpos() returns boolean FALSE.
I wasn't checking for strict equality, so the if statement always returned a falsey value, causing my code to not work.
if ($contains_path = strpos($aspect, '/'))
To fix the issue, you could use !==, which compares the type and value:
if ($contains_path = (strpos($aspect, '/') !== FALSE))
For more information, check the following links:
http://php.net/strpos
http://www.php.net/manual/en/language.operators.comparison.php
I'm trying to do some validation in PHP, and one of them is checking whether there is a specific word in the inputted string or not.
The problem is, my code seem to not working when I put the specified word first.
here's the code:
$word = "aa bb cc dd";
if(strpos($word, 'aa') == false)
{
echo "wrong input";
}
but if I change the $word to either bb aa cc dd or bb cc dd aa, it works. I wonder how to fix this though.
strpos will return false if your string isn't there. Otherwise, it returns the position of your string.
In this case, 'aa' is at the start of the string, which means that it's at position 0; and 0 evaluates to false.
You need to do a boolean compare on the result:
if(strpos($word, 'aa') === false)
That's because strpos returns the position of the word, in this case 0. 0 is falsey. == does not check for identical matches, === does. So use a triple equals.
It's even in the docs.
strpos is returning 0, as 'aa' is the 0th character. As 0 == false but does NOT === false (it is not boolean), you need to use === instead of ==.
You should use the strict comparison operator, this will match against the same type, so using === will check if it's a Boolean:
if(strpos($word, 'aa') === false)
{
echo "wrong input";
}
Using == is a loose comparison, anything can be stated true (apart from true, 1, string), e.g.
"false" == false // true
"false" === false // false
The reason why it's false because it's comparing a string against a Boolean which returns false.
Because the position of aa is 0, which equals to false.
You have to use:
if(strpos($word, 'aa') === false)
Add a space before search string and find more than 0 position
if(strpos(" ".$word, 'aa') > 0)
{
echo "Found it!";
}