get image height and width with php - php

Question

i have a little script that scans a directory and then echos out a list of all files (jpg's)
in that directory and lists it into html image links. it works pretty well.
is there a way i can get the image dimentions for each individual jpg?
i need my output to look something like this.
<img src="albm/1.jpg" width="333" height="460" />
<img src="albm/2.jpg" width="256" height="560" />
<img src="albm/3.jpg" width="327" height="580" />
here is my current script without the image dimentions.
<?php
$albm = $_REQUEST['albm'];
$dir = 'albums/'.$albm.'/';
$files = scandir($dir);
arsort($files);
foreach ($files as $file) {
if ($file != '.' && $file != '..') {
echo '<img src="' . $dir . $file . '"/>';
}
}
?>

Answer 1

<?php
$albm = $_REQUEST['albm'];
$dir = 'albums/'.$albm.'/';
$files = scandir($dir);
arsort($files);
foreach ($files as $file) {
if ($file != '.' && $file != '..') {
$info = getimagesize($dir . $file);
$width = $info[0];
$height = $info[1];
echo '<img src="' . $dir . $file . '"/>';
}
}
?>

Answer 2

Here how to use it:
$size = getimagesize($path);
$width = $size[0];
$height = $size[1];

Answer 3

You can simple use getimagesize(image location) function, it returns width,height,type and attributes. Here is the example
<?php
list($width, $height, $type, $attr) = getimagesize("image_name.jpg");
echo "Image width " .$width;
echo "<BR>";
echo "Image height " .$height;
echo "<BR>";
echo "Image type " .$type;
echo "<BR>";
echo "Attribute " .$attr;
?>