How to Select Specific Info From MySQL - php

Question

I'm trying to a number from a specific table, row, and column but can't seem to get it right.
The table is tblproducts. The column is qty. And I need to select where id is 13.
This is the code I'm using but it isn't returning anything:
<?php
$con=mysqli_connect("localhost","blank","blank","blank");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT qty FROM tblproducts");
while($row = mysqli_fetch_array($result))
{
echo $row['13'];
}
mysqli_close($con);
?>
Any help would be appreciated

Answer 1

do it all in the query like so
SELECT qty FROM tblproducts where id =13
no loop needed
$result = mysqli_query($con,"SELECT qty FROM tblproducts where id =13");
$row = mysqli_fetch_assoc($result);
echo $row['qty'];

Answer 2

Your sql syntax is a bit off, see my corrections. Your echo of the row['13'] also looks suspicous. You can use print_r() to print arrays to find which key you need to use. It is probably $row['qty'].
<?php
$con=mysqli_connect("localhost","blank","blank","blank");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT qty FROM tblproducts where id = 13");
while($row = mysqli_fetch_array($result))
{
print_r($row); // You can use print_r to have a look at your full array. The index '13' might not be what you where looking for.
}
mysqli_close($con);
?>