HTML is still reading php code with <!----> - php

I have the following problem. I used the following code in my page to ignore some php code, but it seems that over the Thanksgiving weekend there was an update and it is no longer ignoring the code.
<!--
<div class="main">
<div class="main-sub">
<?php include('http://www.contractorsintelligence.com/contractors-license/includes-page-elements/navigation1.php');
?>
<div id="mid-top"><img src="" width="990" height="20" alt="Top Spacer"/></div>
<div id="mid_shdw">
-->
The rest of the html code is being ignored, but only php code is not being ignored. I know one of the ways is to include <!-- into the php function. But is there any other way to ignore the php code with the rest of the html code?

This is an HTML comment. It has no effect on the PHP code.
You should use PHP comments:
Block comment:
/*
BLOCK OF COMMENTED CODE
*/
Line comment:
// this is a commented line
The PHP code is interpreted by the server and is calculated "long" before it gets to the users browser. The HTML markup while still on the server, is just text. Only when the HTML arrives at the users browser does it get rendered (or ignored!). So your HTML comments did not matter to the server - it saw PHP code and ran it - the PHP interpreter is not programmed to recognize these strange <!-- symbols that you are giving it. ;)

Your PHP code will always be executed because it doesn't know about your HTML code that surrounds it.
The solution, if you your PHP code not to execute is to comment it out:
<!--
<div class="main">
<div class="main-sub">
<?
// php include('http://www.contractorsintelligence.com/contractors-license/includes-
// page-elements/navigation1.php');
?>
<div id="mid-top"><img src="" width="990" height="20" alt="Top Spacer"/></div>
<div id="mid_shdw">
-->

<?php /* comments */ ?>
The PHP is executed before the HTML is processed client-side.

If you want to ignore the PHP code, its your best bet to do it like this:
<?php
/* include('http://www.contractorsintelligence.com/contractors-license/includes-page-elements/navigation1.php'); */
?>
Whereas /* starts a comment and */ ends it.
PHP will parse the page before it is sent to the client (or browser). Therefore PHP is not 'interested' in <!-- or --> at all.
On the other hand, if the HTML code that is being included by your call to include() contains further HTML commentary (<!-- or -->) it may close your ignored code before the point you intended it to.
UPDATE
Your overall approach is a bit fuzzy. See here, if you want to use PHP to decide whether to show certain HTML code or not, you don't want to use HTML comments to accomplish that.
Try this instead:
<?php
if($result["r_approved"] != "APPROVED"){
?>
<div class="main">
<div class="main-sub">
<?php
include('http://www.contractorsintelligence.com/contractors-license/includes-page-elements/navigation1.php');
?>
</div>
<div id="mid-top">
<img src="https://www.contractorsintelligence.com/images/shadowbg-top.png" width="990" height="20" alt="Top Spacer"/>
</div>
<div id="mid_shdw"></div>
</div>
<?php
}
?>

You php page is executed and everything between <? ?> is executed. Php doesn't care about <!-- --> or any other tag except <? or <?php .
Then the browser doesn't display/load what is inside <!-- -->.
If you want to comment php, use // or /* ... */
<?php /* include('http://www.contractorsintelligence.com/contractors-license/includes-page-elements/navigation1.php'); */ ?>

Two things are happening at once which I think might be confusing:
Unless you wrap everything inside the php tags with /* */ or use // that code will be executed because it comes from the server.
The browser is the only one that parses the <!-- -->.
So your server is parsing the php and then the browser is hiding what was parsed.
Solution
<?php // include('http://www.contractorsintelligence.com/contractors-license/includes-page-elements/navigation1.php'); ?>

Thats because the <!-- isn't parsed by PHP, only by the browser. The easiest (but not always best readable) solution is
<?php if (false) { ?>
<b>This html will not be sent to browser</b>
<?php include('this will not be included'); ?>
<?php } // endif ?>

Related

PHP How To Display HTML+PHP Code Stored in MySQL

I am trying to store HTML and PHP in a MySQL text field and display it in PHP.
When it displays on site it renders as commented out tags:
<!--?php
if(isset($sp_msg) && $sp_msg != ''){
print '<div-->
This of course screws the whole page up.
How am I supposed to go about displaying this data correctly? I would like to eventually add this to a full functioning CMS so I would like to understand how to do this correctly.
page.php
<?php
require_once('library/autoload.php');
$pid = $_REQUEST['id'];
$page = $ct->get_page_info($pid);
$sp_msg = $page['special_msg'];
require_once('h.php');
?>
<div id="row">
<?php
print $page['page_content'];
?>
</div>
<?php
require_once('f.php');
?>
'page_content' stored in mysql as text
<h3>MY HEADER TEXT</h3>
<?php
if(isset($sp_msg) && $sp_msg != ''){
print '<div>'.$sp_msg.'</div>';
}
?>
<hr>
<p>paragraph text</p>
You need to eval the stored php code. When you print out the string stored in the MySQL you don't run it, you only print it.
<div id="row">
<?php
eval($page['page_content']);
?>
</div>
Warning:
I really don't recommend it. If any suspicious code can be entered into that DB it could cause really big problems. You can't check the PHP code if its not a crypto virus for example. This code will execute anything on the server.
See the PHP manual: eval

Add content to PHP file with PHP / edit PHP file with PHP

I'm building my own CMS system and I want to create new pages dynamicly from a template. Just like in wordpress when you add a new Page.
This is the template:
<?php require_once('backend-nav.php');?>
<div id="main">
<div id="main-content" class="xlarge">
<article id="article-wrapper">
// My content needs to go here!
</article>
<?php require_once('backend-sidebar.php')?>
</div>
</div><!-- End main content container -->
<?php require_once('backend-footer.php')?>
<?php } else {
echo '<div class="container">You have to be logged in to view this page:.
'Login'.'</div>';
}
?>
I have made a form to submit the content that I want on the page, and then use the following code to open the templatet php file and save it as a new file on the server with the content for the page
$doc = new DOMDocument();
$doc->loadHTMLFile("new_page.php");
$article = $doc->getElementById('article-wrapper');
$p = $doc->createElement('p');
$addP = $article->appendChild($p);
$content = $doc->createTextNode($page_content);
$addP->appendChild($content);
// the url for the page is also submitted to the form and later added to the menu, which works.
$doc->saveHTMLFile($page_url.'.php');
Since there is no loadPHP function I'd recon I use this one. It also worked for me when adding the link to my main menu, which is also a PHP file.
Now the content gets added to the file, and is saved accordingly but for some reason it fucks up the code in some places like this, some sign are replaced like ? and > etc.:
require_once('backend-header.php');
?>
<?php if (isset($_COOKIE['username'])) { ?>
<?php require_once('backend-nav.php');?>
<html>
<body>
<div id="main">
<div id="main-content" class="xlarge">
<article id="article-wrapper">
<p>test content added in p tags</p></article>
<?php require_once('backend-sidebar.php')?> </div><!-- End main content container -->
</div>
<?php require_once('backend-footer.php')?><?php } else {
echo '<div class="container">You have to be logged in to view this page: ' .
'Login'.'';
}?></body></html>
the PHP ending tag before the html end tag is replaced
I have also tried fread/write to alter the file but I probably are not using things the right way.
Is there a way to add code to php file with php, or a other way to get what I'm trying to do?
Thanks!
DOMDocument only use to read XML and HTML, these have a structure. When you insert PHP code into html file, it is not realy a html anymore. Let see an example below.
The html code:
<a>text</a>
There is a node that named "a" have a content. DOMDocument can understand it well.
But
<a><?php if (false) : ?>true</a><? else: ?>false</a><?php endif ?>
DOMDocument can not understand php and it will read the first < /a> as the closer of < a>. How about the second one, the reader may try to read by fixing it or just ignore it or append something to make it become structured. So, you can not use DOMDocument in this case. You could try to use file_get_contents and replace the content then use file_put_contents to write it back.

Insert PHP code after nth element with jQuery

I have the following code:
<div class="container"><div class="wrapper">
<p>Some Content/p>
<p>More Content</p>
<p>An Image</p>
<p>More Content</p>
<p>Even More Content</p>
<p>A Second Image</p>
</div></div>
I want to insert some PHP after the second paragraph. I have a JSFiddle that is working without the PHP code, using:
$('.wrapper p').eq(1).after('<div>hello</div>');
But as soon as I add the PHP code it stops working using:
$('.wrapper p').eq(1).after('<div>hello <?php wds_social_media_icons(); ?></div>');
What's going on? Can I just not use PHP with .after?
PHP is a server side language, it cannot be interpreted by the client browser.
You need to put all your PHP logic on your server.

PHP - using include, can i execute on a different div in the page?

I have a small problem, and I'll try to break it down into a smaller one so I can explain it properly.
I'm working on a web application and I have a couple of divs, such as this:
<div class="1">
//search bar
</div>
<div class="2">
include_once 'actioncontroller.php';
</div>
<div class="3">
</div>
In the actioncontroller.php I'm having an action controller which decides what action to take depending on what's pressed on the page. I've put it in the second div because ultimately that's where I want to print everything.
My question is, is there any way that I can use the code from the second div in the first one, without it printing it there? Basically I want the search bar from div one to do/print the same thing as the one in div 2 does, but I know(think) that PHP can't see code above the include_once, and if I include the actioncontroller.php in the first div it will print it there, instead of printing it in the second one, as I want.
Hope I was clear enough, it's not a problem of coding, it's just a matter of how can I read the script in the first div and then run it in the second one...
Thanks in advance
My question is, is there any way that I can use the code from the second div in the first one, without it printing it there?
Yes, but the best solution is to change the code you've already written. In the long-term, it is vitally important that you minimize your "procedural" PHP code, so that nothing ever happens simply by include/require-ing a file.
Trust me on this, it works for toy project, but it always leads to insanity and pain in the end. For example, don't put this in a file:
<?php
echo("Header section");
This is bad because you have no choice about when it prints. This is a step up:
<?php
function WriteHeader(){
echo("Header section");
}
Even better would be to use classes an autoloading, but that's probably more than you need to hear right now. With that kind of approach, your main page would look more like:
<?php
// This next line simply makes the class ActionController *available*,
// it does NOT cause new things to happen on its own
include_once("actioncontroller.php");
?>
<div class="1">
<?= ActionController::MakeSomeHTML(); ?>
</div>
<div class="2">
<?= ActionController::MakeSomeHTML(); ?>
</div>
<div class="3">
</div>
This code takes the output of actioncontroller.php and saves it into a variable, which can be echo'd multiple times.
<?php
ob_start();
include_once 'actioncontroller.php';
$output = ob_get_contents();
ob_end_clean();
?>
<div class="1">
<?php echo $output; ?>
</div>
<div class="2">
<?php echo $output; ?>
</div>

Reusable user interface in PHP?

For most of my projects I make an administration interface, which has the same design for every project. The design of the header, the footer, the topbar, the leftmenu, the css, etc. are always the same. It is a pity to create the views every time; so I was thinking: maybe there would be a nice way to put the admin interface in my MVC library, as it is reused by every project?
But for the moment, in every single view I got code like the following:
<?php $this->_include('/includes/doctype.php'); ?>
<head>
<?php $this->_include('/includes/head.php'); ?>
<title>Some title</title>
</head>
<body>
<?php $this->_include('/includes/topbar.php'); ?>
<div id="page">
<?php $this->_include('/includes/header.php'); ?>
<?php $this->_include('/includes/leftmenu.php'); ?>
<div id="content" role="main">
<h1>Some title</h1>
<p>Blah blah blah.</p>
</div><!-- /#content -->
<?php $this->_include('/includes/footer.php'); ?>
</div><!-- /#page -->
</body>
</html>
Would it be a good idea to extract the custom content from the structure of the interface, and put that structure in my library somehow to make it reusable?
After that how will it be possible to customize the title and the actual menus?
I do this all the time. I have a custom header and footer file that are called at the start and end of every page.
<?PHP
Require("includes/header.php");
...
Require("includes/footer.php");
?>
The header provides a database handle, a datetime string and handles logon, priveleges, logging of pageviews etc.
The footer provides a standard HTML page but includes some systematised variables. It also generates the menu dynamically from the driving database then closes the database connection.
This way when I write code, I don't get mixed up in the HTML and any bugs are easy to find.
I like variables akin to:
$display_scripts - adds extra data in the head section.
$display_onload_scripts - adds onload scripts to body section.
$display_style_sheets - option to include link to additional stylesheets
$display_above_menu - will appear above the menubar. NOT recommended.
$display_below_menu - will appear immediately below the menubar.
$display_one_column - page contents when only one column is to be used
$display_left_column - page contents when two columns used. Left pane.
$display_right_column - page contents when two columns used. Right pane.
$display_footer - appears in footer division.
My main code then just has to generate the appropriate variable. Fundamentally, what you need to do is examine the source of a good age you have produced then replace the stuff you want to change with variables.
Here is a schematised version of the file I use (pseudocode) to give you an idea of how I do it.
// Code here generates the menu from database
// Code here genereates popup alert messages from other users
//permanent links to external style sheets go here.
//You can also select skins here.
<?PHP
echo $display_style_sheets;
echo "<title>".$display_page_title."</title>";
?>
<script type="text/javascript" src="JAVASCRIPT GOES HERE.js"></script>
</head>
<body <?PHP echo $display_onload_scripts;?> >
<div id="page_area" >
<div id="banner">
</div>
<?php
echo $display_above_menu;
if(!$hide_menu){echo $display_menu;} //Insert the menu variable here.
echo $display_below_menu;
?>
<div id="content_area">
<div id="inner_content">
<?PHP
if($display_number_of_columns==1)
{
echo "<div id='onecolumn'>".$display_one_column."</div>"; //I only use this one
}
if($display_number_of_columns==2)
{
echo "<div id='leftcolumn'>".$display_left_column."</div>"; //these are left for legacy support from before I got better at CSS.
echo "<div id='rightcolumn'>".$display_right_column."</div>";
}
echo "<div id='footer'>".$display_footer."</div>"; //just in case - I hardly use it.
echo $display_pop_box; //for user alert messages to other users
?>
</div>
</div>
</div>
<div id="logbox"> Automatic Logout statement</div> //this is called by JS to activate timeouts.
</body>
</html>
<?PHP
$mysqlidb->close();
?>
Sorry it's such a lot of code. The layout allows easy adaptation and makes it simple to find the offending variable if things are not going as expected. There are more elegant solutions but this works well for me and is very fast.

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