I'm having trouble displaying the sql below in the hph view file.
$query = mysqli_query($con, "SELECT TF.tf_ID AS QuestID, TF.Question AS Question FROM QuizQuestions quest, addTF TF WHERE quest.QuestID = TF.tf_ID AND quest.QuizID ='".$quizID."' AND quest.Type = 'tf'");
$rows = array();
while ($row = mysqli_fetch_assoc($query)) {
$rows[] = $row;
}
echo json_encode($rows);
This is the part of the php view that is supposed to display the sql. I know it is wrong but I don't know how to fix it. Any help is welcome.
<?php foreach($json as $tf) :?> <?php echo $tf['Question']; ?> <div class="row-fluid"><div class="span8">
<div class="btn view" id="view" style="width: 98%">
<p class="text-left" style="margin: 0;float: left;">
<input type ="hidden" value="tf" name="type">
<input type="checkbox" id="questID" value="<?php echo $tf['tf_ID'];?>" name="questID" class="questID" > <?php echo 'Question: '.$tf['Question']; ?> </input><br/>
<input type="hidden"> <?php echo 'Answer: '.$tf['Answer'] ; ?> </input><br/>
</div> </div> </div> <?php endforeach; ?>
I've used similar codes and they work. They problem is I do not know how to work with sql "AS". My apology in advance if this question was once asked and for the format.
There is no method called mysqli_fetch_assoc(). There is mysql_fetch_assoc() but not mysqli_fetch_assoc().
You can do this to get the rows:
$query = "SELECT TF.tf_ID AS QuestID, TF.Question AS Question FROM QuizQuestions quest, addTF TF WHERE quest.QuestID = TF.tf_ID AND quest.QuizID ='".$quizID."' AND quest.Type = 'tf'";
$result = mysqli_query($con, $query);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
If you are calling the query through an Ajax method and returning the data to JavaScript you should JSON encode. However, if you are just printing the rows with PHP there is no reason to JSON encode them.
To iterate the rows in PHP you can do:
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo '<div>' . $row['foo']; . '</div><div>' . $row['bar']; . '</div>';
}
I'm not clear what you are trying to do.
The top code create some JSON which will be sent to the browser. Presumably in response to a AJAX or jQuery request. Once the JSON is on the browser it can be added to the current page using Java-Script.
The second code fragment is PHP which always executes on the server, but your data is on the client???
I would have expected something more like...
$rows = mysqli_fetch_assoc($query)
echo "<div>\n";
foreach($rows as $row) {
// generate one row getting values as {$row['fieldname']}
}
echo "</div>";
Also - if you don't generate 100% valid and error free html you not only have to test on all current browsers, you cannot complain if a new browser displays it wrongly next release.
Related
I need to display a list of results form a survey on a PHP page then export them to a CSV file. The list also acts as a summary that can be clicked thorugh to the full result.
I have all that sorted but now I need to have the CSV export by a check bx selection so that we dont need to download the entire databse each time just the ones we need.
My code so far below.
<div class="resultsList">
<h1>PEEM Results List</h1>
<a class="exportCSV" href="https://domain.com/downloadcsv.php">Export to CSV</a>
<!-- Export CSV button -->
<h3 class="resultsbydate">All results by date</h3>
<div class="resultsListHeader">
<div class="clientidTab">Agency</div>
<div class="clientidTab">Family ID</div>
<div class="clientidName">Name</div>
<div class="clientidTab">Date</div>
<div class="clientidTab"></div>
</div>
<div class="entriesListMain">
<?php
$connection = mysql_connect("localhost", "username", "password"); // Establishing Connection with Server
$db = mysql_select_db("database_name", $connection); // Selecting Database
//MySQL Query to read data
$query = mysql_query("select * from results ORDER BY peemdate DESC", $connection);
while ($row = mysql_fetch_array($query)) {
echo "<div><input type=\"checkbox\" name=\"xport\" value=\"export\"><span>{$row['client_id']}</span> <span>{$row['family_id']}</span> <span>{$row['firstname']} {$row['lastname']}</span> <span>".date("d F Y", strtotime($row['peemdate']))."</span>";
echo "<span><a class=\"parents-button\" href=\"peem-parent-repsonses.php?id={$row['survey_id']}\"><strong>Parent’s Review</strong></a></span>";
echo "<span><strong>View Results</strong></span>";
echo "</div>";
}
?>
</div>
</div>
<?php
if (isset($_GET['id'])) {
$id = $_GET['id'];
$query1 = mysql_query("select * from results where survey_id=$id", $connection);
while ($row1 = mysql_fetch_array($query1)) {
?>
<?php
}
}
?>
<?php
mysql_close($connection); // Closing Connection with Server
?>
And the downloadcsv.php
<?php
$conn = mysql_connect("localhost","username","password");
mysql_select_db("databasename",$conn);
$filename = "peem_results.csv";
$fp = fopen('php://output', 'w');
$query = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA='realwell_peemfinal' AND TABLE_NAME='results'";
$result = mysql_query($query);
while ($row = mysql_fetch_row($result)) {
$header[] = $row[0];
}
header('Content-type: application/csv');
header('Content-Disposition: attachment; filename='.$filename);
fputcsv($fp, $header);
$query = "SELECT * FROM results";
$result = mysql_query($query);
while($row = mysql_fetch_row($result)) {
fputcsv($fp, $row);
}
exit;
?>
Any help with this would be great, cheers
Updated with a screenshot of what I am trying to achieve
The initial result set needs to be wrapped in a form which POST to the next page.
The Checkbox must send an array of ids to the export script.
<input type='checkbox' name='xport[]' value='ID_OF_THE_ROW_HERE'>
The [ ] after xport means that $_POST['xport'] will be an array of values.
The export page can collapse that array of ids into a comma separated string and to be used the query:
SELECT * FROM results WHERE id IN (4,7,11,30)
<form method="POST" action="downloadcsv.php">
<h1>PEEM Results List</h1>
<a class="exportCSV" href="https://domain.com/downloadcsv.php">Export to CSV</a>
<!-- Export CSV button -->
<h3 class="resultsbydate">All results by date</h3>
<div class="resultsListHeader">
<div class="clientidTab">Agency</div>
<div class="clientidTab">Family ID</div>
<div class="clientidName">Name</div>
<div class="clientidTab">Date</div>
<div class="clientidTab"></div>
</div>
<div class="entriesListMain">
<?php
$connection = mysql_connect("localhost", "username", "password"); // Establishing Connection with Server
$db = mysql_select_db("database_name", $connection); // Selecting Database
//MySQL Query to read data
$query = mysql_query("select * from results ORDER BY peemdate DESC", $connection);
while ($row = mysql_fetch_array($query)) {
echo "<div><input type='checkbox' name='xport[]' value='{$row['client_id']}'><span>{$row['client_id']}</span> <span>{$row['family_id']}</span> <span>{$row['firstname']} {$row['lastname']}</span> <span>".date("d F Y", strtotime($row['peemdate']))."</span>";
echo "<span><a class=\"parents-button\" href=\"peem-parent-repsonses.php?id={$row['survey_id']}\"><strong>Parent’s Review</strong></a></span>";
echo "<span><strong>View Results</strong></span>";
echo "</div>";
}
?>
</div>
</form>
Change $row['client_id'] to the correct value
Then in the export script:
<?php
/*
Expecting $_POST['xport'] array of row ids
*/
if( !isset($_POST['xport']) OR !is_array($_POST['xport']) ) {
exit('No rows selected for export');
}
$conn = mysql_connect("localhost","username","password");
mysql_select_db("databasename",$conn);
$filename = "peem_results.csv";
$fp = fopen('php://output', 'w');
$query = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_SCHEMA='realwell_peemfinal' AND TABLE_NAME='results'";
$result = mysql_query($query);
while ($row = mysql_fetch_row($result)) {
$header[] = $row[0];
}
header('Content-type: application/csv');
header('Content-Disposition: attachment; filename='.$filename);
fputcsv($fp, $header);
//Cast all ids to integer
$ids = $_POST['xport'];
array_walk($ids, function(&$value, $key) {
$value = (int)$value;
});
$ids = implode(', ', $ids);
$query = "SELECT * FROM results WHERE id IN ($ids)";
$result = mysql_query($query);
while($row = mysql_fetch_row($result)) {
fputcsv($fp, $row);
}
exit;
?>
So if I'm getting this correctly, you just need to be able to check checkboxes to select the databses ($rows) you want to insert into the csv file....
Every checkbox that you checked will be in the $_POST variable, so:
1st you make an array with all the names of checkbox options (databases), for example
$all_db = ['database1', 'database2', 'database3'];
2nd you loop through each of the values in $all_db and check if they exist in the $_POST array, if they do, then you can export the row
foreach( $all_db as $db_check ) {
if ( array_key_exists( $db_check, $_POST ) {
// EXPORT TO CSV
}
}
Don't forget ! This means the "name" attribute of the checkbox should be the name of the database.
If you don't want to have a static list of databases (i.e. there is a possibillity of them having different names in the future / there will be moreor maybe less etc then let me know i can edit my answer if needed :) )
( If you use the $_GET variable, then you can do the same thing just change $_POST to $_GET)
Know though that $_GET comes over as a bit amateuristic for the enduser if he gets a thousand variables in his URL,
$_POST is often a better alternative since it is hidden and cleaner for the enduser...
EDIT: UPDATING ANSWER (SEE COMMENT)
So basically you need people to be able to choose what rows they export from you dB...
First of all this means we need a unique ID for each row,
This can either be a column used solely for that (i.e. ID column with auto increment and unique attribute)
Or this can be a column you already have, just make sure it's a unique column so we don't get dupliate values (you'll see why below)
Then we give the value of this unique ID column to the checkbox's "name" attribute, and using jquery / php we append / prepend a static string...
For example, using your family ID:
"rownumber_" + $family_ID
This gets us (again using your example) :
$_POST[] = ['rownumber_123456' => 1, 'rownumber_0000000' => 1, .....]
So then in your PHP file you just do the following to add the correct lines to your CSV:
while($row = mysql_fetch_row($result)) {
if ( array_key_exists($row['your_row_id'], $_POST) {
fputcsv($fp, $row);
}
}
-- Again using your example with family_ID : --
while($row = mysql_fetch_row($result)) {
if ( array_key_exists($row['family_ID'], $_POST) {
fputcsv($fp, $row);
}
}
EDIT: Updating answer for comment no.2
So little sidenote if you are going to loop through html using php
(i.e. loop trhough db rows and print them out in an orderly fashion)
Then you propably want to use the ":" variants of the loops,
While() :
for() :
foreach() :
if () :
.....
These variants allow yu to close the php tag after the ":" and whataver html / css / php / jquery you put in the condition / loop will be executed like normal...
For example you can do :
<ul>
<?php foreach ($row as $columnkey => $columnvalue): ?>
<img src="whateveryouwant"?>
<li class="<?php echo $columnkey;?>">This is my value: <?php echo $columnvalue; ?></li>
<?php endforeach; ?>
</ul>
When you do it this way it's much cleaner and you won't have any problems using double quatation signs and all that stuff :)
So using that method here is how your displayed list would look like in code:
<div class="entriesListMain">
<?php
$connection = mysql_connect("localhost", "username", "password"); // Establishing Connection with Server
$db = mysql_select_db("database_name", $connection); // Selecting Database
//MySQL Query to read data
$query = mysql_query("select * from results ORDER BY peemdate DESC", $connection);
while ($row = mysql_fetch_array($query)) :
?>
<div>
<input type="checkbox" name="<?php echo $row['family_id']; ?>" value="export">
<span><?php echo $row['client_id']; ?></span>
<span><?php echo $row['family_id']; ?></span>
<span><?php echo $row['firstname'] . " " . $row['lastname']; ?></span>
<span><?php echo date("d F Y",strtotime($row['peemdate']); ?></span>;
<span>
<a class="parents-button" href="peem-parent-repsonses.php?id=<?php echo $row['survey_id']; ?>">
<strong>Parent’s Review</strong>
</a>
</span>
<span>
<a href="peem-repsonses.php?id=<?php echo $row['survey_id']; ?>">
<strong>View Results</strong>
</a>
</span>
</div>
<?php endwhile; ?>
</div>
Like this the checkbox will get the name of the family ID, and so in your csv.php you can use this code :
while($row = mysql_fetch_row($result)) {
if ( array_key_exists($row['family_ID'], $_POST) {
fputcsv($fp, $row);
}
}
Since now it will check for each row wether the family ID of the SQL row is posted as a wanted row in the $_POST variable (checkbooxes) and if not it won't export the row into the csv file ! :)
So there you go ^^
EDIT 3: Troubleshooting
So there are a couple of things that you do in this function,
the form,
Do the checkboxes in your html form have the family_ID in their name attribute ?
(i.e. <input type="checkbox" name="<?php echo $row['family_id']; ?>".... check if the name attribute is really filled )
you post stuff from a form, (your checkboxes and stuff)so let's see what actually gets posted,
die(print_r($_POST)); - This means you want php to die after this line (stop working at all), then print out a variable as is (sort of xml format you'll see)
So then you will get a whole bunch of information, if you want to see this information in a nicely formated way, just right click inspect element on it :)
Then see how your checkboxes are coming out of the $_POST variable,
(they should have the family_ID as a key and a value of 1)
If that's all ok, then check your row['family_ID'] variable see if the family_ID is filled correctly, do the same with your whole $row variable, in fact check every variable you use in csv.php and then check why the key does not exist in the array you are searching for :)
Also dont forget to check that you filled the array_key_exists( has a key FIRST and an array[] LAST )
I can't help you directly with this , since this will propably be a faulty variable or a mistake in your form so try to find this yourself, if still nothing , post these variables values:
$_POST
$row
and the full HTML of your form
I have a PHP function that returns a single row from a localhost MySQL table like so:
<?php
//include database connection process
require_once("includes/conn.inc.php");
//prepare statement
$stmt = $conn->prepare("Select * FROM races WHERE raceID = ?");
$id = 1;
$stmt->bind_param("i", $id);
$stmt->execute();
$result = $stmt->get_result();
$row = $result->fetch_assoc();
?>
What I would like to do with this array is output the data from the individual fields in their own HTML <div> or <p> with a heading indicating what they mean in a separate div. I currently user the print_row method that outputs everything in one. All the data I want is there, but I'd like it separated out into name/value paragraphs or divs.
//what I currently have
<?php
print_r($row);
?>
Is there a way to do this?
Thanks in advance,
Mark
I didn't understand the question very well but I think I understand what you need.
Use while to iterate trough each row.
while($row = $resultDesc->fetch_assoc())
{
echo '<p><strong>Description:</strong></p> ';
echo '<p>'. $row['description'] . '</p>';
}
That's not the exact solution but atleast shows you the path.
You can use foreach
<?php foreach ($row as $key => $val): ?>
<p><strong><?php echo $key; ?>:</strong></p>
<p>
<?php
//output relevant attribute
//of query run on page load
echo $val;
?>
</p>
<?php endforeach; ?>
I am making a periodic table and am new to php. I have looked far and wide for information on how to accomplish this task, but I can't find anything. What I want to do is query my database and get values for things like atomic weight, name, element symbol, etc, and have them populate in my periodic table that I have constructed with html and css. However, I just don't know to run the "while" loop and have the data populate in the appropriate spaces. I understand how to create a table with the results, but I don't understand how to have results populate into an html structure that has already been created. Here is a part of my code. Again, I am very new to php, so any help would be greatly appreciated. I'm fairly certain this has a lot to do with where I'm placing my opening/closing php tags. Essentially, how do I get the loop to recognize the variables within the html? Do I close php tags and reopen?
Thank you tremendously.
<?php
//query database (connection successful)//
$result=mysql_query("SELECT * FROM elementdata", $link);
//fetch results into array to loop through//
while($row = mysql_fetch_array($result)) {
//begin table structure where I would like to insert data//
<div id="hydrogen" class="element group1 period1">
<span class="number"> echo $row['atomicNumber']; </span><br>
<span class="symbol">H</span><br>
<span class="name"> echo $row['name']; </span><br>
<span class="molmass">1.007 94</span></div>
<div id="Helium" class="element group18 period1">
<span class="number">echo $row['atomicNumber'];</span><br>
<span class="symbol">He</span><br>
<span class="name"> echo $row['name']; </span><br>
<span class="molmass">4.002 602</span></div>
//...table continues...//
?>
You could go with two approaches, using PHP to echo the HTML or having PHP in the HTML.
PHP printing HTML
<?php
//query database (connection successful)//
$result=mysql_query("SELECT * FROM elementdata", $link);
//fetch results into array to loop through//
while($row = mysql_fetch_array($result)) {
//begin table structure where I would like to insert data//
echo '<div id="hydrogen" class="element group1 period1">';
echo ' <span class="number">' . $row['atomicNumber'] . '</span><br>';
echo ' <span class="symbol">H</span><br>';
echo ' <span class="name">' . $row['name'] . '</span><br>';
echo ' <span class="molmass">1.007 94</span></div>';
}
HTML with PHP
<?php
//query database (connection successful)//
$result=mysql_query("SELECT * FROM elementdata", $link);
//fetch results into array to loop through//
while($row = mysql_fetch_array($result)) {
?>
//begin table structure where I would like to insert data//
<div id="hydrogen" class="element group1 period1">';
<span class="number"><?php echo $row['atomicNumber']; ?></span><br>';
<span class="symbol">H</span><br>';
<span class="name"><?php echo $row['name']; ?></span><br>';
<span class="molmass">1.007 94</span></div>';
<?php
}
Well i am not sure about whether you are storing the molmass,symbol,group and period in the MySQL table, but you most probably are. Since i dont know what you named them, please replace molmass,atomicSymbol,atomic_group and atomic_period with your coloumn name.
You can use this code,
<?php
//query database (connection successful)//
$result=mysql_query("SELECT * FROM elementdata", $link);
//fetch results into array to loop through//
while($row = mysql_fetch_array($result)) {
// echo the first line, i.e the div
echo "<div id='{$row['name']}' class='element {$row['atomic_group']} {$row['atomic_period']}'>";
// Echo the atomic number, symbol, name and molmass
echo "<span class='number'>{$row['atomicNumber']}</span><br>";
echo "<span class='symbol'>{$row['atomicSymbol']}</span><br>";
echo "<span class='name'>{$row['name']}</span><br>";
echo "<span class='molmass'>{$row['molmass']}</span><br>";
echo "</div>";
}
?>
Explaination: The {} is required for us to insert the $row[''] syntax in a string, else it gives us trouble.
Rest we just loop over everything in the table, fetch what you named them and what group and period they belong to, create a div. Then we print each of their properties.
You need to step in and out of PHP
After :
//fetch results into array to loop through//
while($row = mysql_fetch_array($result)) {
If you want to output HTML, you must close PHP
?>
Now when you want to output some PHP variable inside a HTML tag :
<span class="number"><?php echo $row['atomicNumber']; ?></span><br>
Similar to the opening and closing tags in HTML, you enclose your PHP code within PHP tags.
Well, let's try one possible way:
<html>
<head>
</head>
<body>
<?php
open your db stuff
$query = " SELECT name,
symbol,
atomicnumber,
molmass,
otherstuff
FROM periodictabletable
WHERE index > 0 ";
$result = mysqli_query($cxn, $query) or die ("could not query database");
echo "<table>";
while ($row = mysqli_fetch_array($result))
{
echo "<tr><td>".$row['name']."</td><td>".$row['symbol']."</td><td>".$row['atomicnumber']."</td><td>".$row['molmass']."</td></tr>";
}
echo "</table>";
?>
</body>
</html>
Once you get this up and running, you can embed all kinds of formatting tags into the html, just make sure you only use single quotes for stuff like - class='numbercolor' .
But there are many ways to do this. You could make the table in html, then populate it with an ajax call - depends on what you want to do.
Have fun!
I have a simple page which contains some products in the database. What I want is to create some sort of an updater, if the user add a product then that specific div in the page will display the latest product added automatically.
I tried to view this link but it doesnt help at all we have different problem.
Anyway heres the function i have in php.
function recentlyAddeditems() {
echo '<h3>Recently Added Products</h3> <hr/>';
echo '<div id="main_section_widget">';
$sql = mysql_query("SELECT * FROM products ORDER BY id DESC LIMIT 20") or die(mysql_error());
if ($sql) {
while ($row = mysql_fetch_array($sql)) {
$name = $row['name'];
$id = $row['id'];
$category = $row['category'];
echo "$name | $category<br/>
<hr/>
";
}
echo '</div>';
echo '
<p><br/>More items...</p>
';
}
}
and the in html page
<div id="main_section_widget_cover" class="dates">
<?php recentlyAddedItems(); ?>
</div>
Is there a simpler way how to do this? I tried to read about ajax in jquery but still having confused without a concrete example.
Please help wizards of stack!!!
IF you want an example of a ajax in jquery here is a really simple example
<div id="main_section_widget_cover" class="dates"><div>
<script>
$('#main_section_widget_cover').load('recentitems.php');
</script>
in recentitems.php
<?php recentlyAddedItems(); ?>
Thats it, thats all you need to do to do a basic ajax call
I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me.
First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug.
Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser.
$query = "SELECT * FROM employees";
$result = mysql_query($query);
$num = mysql_num_rows($result);
echo '<table>';
for ($i = 0; $i < $num; $i++){
$row = mysql_fetch_array($result);
$id = $row['id'];
$l_name = $row['l_name'];
$f_name = $row['f_name'];
$ssn = $row['ssn'];
$class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row";
echo "<tr>";
echo "<td class=" . $class . ">$wrap_id</td>";
echo "<td class=" . $class . ">$wrap_l_name</td>";
echo "<td class=" . $class . ">$wrap_f_name</td>";
echo "<td class=" . $class . ">$wrap_ssn</td>";
echo "</tr>";
}
echo '</table>';
mysql_close($link);
}
EDIT
To answer a few questions:
#controlfreak123, I am not sure what you mean by "include ('filename_with_php_in_it')". As far as the page not being called to be parsed, I think it is being called and contact is being made. I pointed out in my original question that I believe this is true because FireBug shows the code for the table, and that code is in separate PHP file, thus communication between the HTML file and the PHP file must be taking place. Here is how I am calling the PHP file from the HTML file you if you care to know:
<script language="javascript" type="text/javascript" src="/Management/Employee_Management.php?action=Edit_Employee"></script>
#Matt S, I am not getting much in the way of output, in fact I didn't know I was getting anything at all until I looked at FireBug and saw that the PHP code (or some of it) was indeed being passed to the HTML file. The specific question is how do I get the data I want from my MySQL database and populate it into an HTML table via PHP. I can also confirm that employees does have data in it, two entries I put in for testing. I can try to put the code into its own file without the JavaScript as you suggested, but that would defeat my purpose since I want my HTML and PHP files to be separate, but I may try it just to see if the PHP code is good and to make sure the JavaScript isn't breaking it.
#Aaron, I am not sure what you are asking (sorry). The code is meant to populate create and populate a table on an HTML page.
Here is a full example of what you're looking for:
pull some data from mysql using php
put that data into an html table
apply alternating colored rows to the table
For the styling I cheat a little and use jquery which I find a bit easier then what you're trying to do.
Also, remember $row[field] is case sensitive. So $row[id] != $row[ID].
Hope this helps:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js" type="text/javascript"></script>
<style type="text/css">
tr.header
{
font-weight:bold;
}
tr.alt
{
background-color: #777777;
}
</style>
<script type="text/javascript">
$(document).ready(function(){
$('.striped tr:even').addClass('alt');
});
</script>
<title></title>
</head>
<body>
<?php
$server = mysql_connect("localhost","root", "");
$db = mysql_select_db("MyDatabase",$server);
$query = mysql_query("select * from employees");
?>
<table class="striped">
<tr class="header">
<td>Id</td>
<td>Name</td>
<td>Title</td>
</tr>
<?php
while ($row = mysql_fetch_array($query)) {
echo "<tr>";
echo "<td>".$row[ID]."</td>";
echo "<td>".$row[Name]."</td>";
echo "<td>".$row[Title]."</td>";
echo "</tr>";
}
?>
</table>
</body>
</html>
Here's the table code only using PHP to alternate the styles like you're trying to do in your example:
<table class="striped">
<tr class="header">
<td>Id</td>
<td>Title</td>
<td>Date</td>
</tr>
<?php
$i = 0;
while ($row = mysql_fetch_array($query)) {
$class = ($i == 0) ? "" : "alt";
echo "<tr class=\"".$class."\">";
echo "<td>".$row[ID]."</td>";
echo "<td>".$row[Name]."</td>";
echo "<td>".$row[Title]."</td>";
echo "</tr>";
$i = ($i==0) ? 1:0;
}
?>
</table>
The reason your code is not executing is that you cannot include PHP with the Script tag. You must use PHP's include function, and the original page must be parsed as PHP.
<?php
include('./my_other_file.php');
?>
The starting of the coding is a little bit wrong. It should be:-
<?php
$query = "SELECT * FROM employees";
$result = mysql_query($query);
$num = mysql_num_rows($result);
echo '<table>';
if($num) {
while( $row = mysql_fetch_array($result) ) {
// all logic for each of the rows comes here
}
}
else {
// no rows fetched, so display proper message in a row
}
echo "</table>";
?>
The first time "mysql_fetch_array" function is used on a Resource Handler, after that it does not work properly. This answer may seem a bit vague, but I have seen it many times, so I always use a "while" or "do-while" loop for fetching multiple rows from DB.
Try using the above code, & see if any information crops up.