php compare current date with dates stored in database - php

Question

I am trying coding a php script where i want to extract a date field from a database table,store this date compare it with todays. To see if the data. from database has passed or not compared to todays date.
the code i have written for this functionality looks like its not working
I think i am getting the date() format wrong.
I am not to sure about the logic if statments.
php
$sql="SELECT enddate FROM campaigns WHERE id=".$data['camp'];
$result = mysqli_query($db, $sql);
while($info = mysqli_fetch_assoc($result)){
if(date("Y-m-d") > $result){
exit;
echo "Success";
}
elseif(date("Y-m-d") < $result){
return true;
echo "Failure";
}
}

Answer 1

Use strtotime()
while($info = mysqli_fetch_assoc($result)){
if(strtotime(date("Y-m-d")) > strtotime($result)){
exit;
echo "Success";
}
elseif(strtotime(date("Y-m-d")) < strtotime($result)){
return true;
echo "Failure";
}
}

Answer 2

You have to do:
if(date("Y-m-d") > $info['enddate']) {

Answer 3

Youl could just let MySQL worry about it.
SELECT DATEDIFF(NOW(),enddate) FROM campaigns WHERE id=".$data['camp']
That will return the number of days between the two dates. See the manual for DATEDIFF.

Answer 4

You can use below query :
$sql="SELECT (CASE WHEN DATE(NOW()) > enddate THEN 'success' ELSE 'failed' END) AS mystatus FROM campaigns WHERE id=".$data['camp'];
Then you just need to call mystatus column from the query.

Answer 5

I spend lot of time to compare only dates and i found a solution like this
Always set format like date('Y-m-d')
$dateTo='2016-08-07';
if(date("Y-m-d", strtotime($dateTo)) > date('Y-m-d')){
echo 'yes';
}else{
echo 'no';
}