I'm working on a bb-code replacement function when a user wants to post a smiley.
The problem is, that if someone uses a bb-code smiley that doesn't exists, it results in an empty post because the browser will not display the (non-existing) emoticon.
Here's my code so far:
// DO [:smiley:]
$convert_smiley = preg_match_all('/\[:(.*?):\]/i', $string, $matches);
if( $convert_smiley )
{
$string = preg_replace('/\[:(.*?):\]/i', "<i class='icon-smiley-$1'></i>", $string, $convert_smiley);
}
return $string;
The bb-code for a smiley usually looks like [:smile:] or like [:sad:] or like [:happy:] and so on.
The code above is working well, until someone post a bb-code that doesn't exists, so what I am asking for is a fix for non existing smileys.
Is there a possibility, in example to create an array, like array('smile', 'sad', 'happy') and only bb-code that matches one or more in this array will be converted?
So, after the fix, posting [:test:] or just [::] should not be converted and should be posted as original text while [:happy:] will be converted.
Any ideas? Thanks!
I put your possible smiley’s in non-grouping parentheses with or symbol in a regexp:
<?php
$string = 'looks like [:smile:] or like [:sad:] or like [:happy:] [:bad-smiley:]';
$string = preg_replace('/\[:((?:smile)|(?:sad)|(?:happy)):\]/i', "<i class='icon-smiley-$1'></i>", $string);
print $string;
Output:
looks like <i class='icon-smiley-smile'></i> or like <i class='icon-smiley-sad'></i> or like <i class='icon-smiley-happy'></i> [:bad-smiley:]
[:bad-smiley:] is ignored.
A simple workaround:
$string ="[:clap:]";
$convert_smiley = preg_match_all('/\[:(.*?):\]/i', $string, $matches);
$emoticons = array("smile","clap","sad"); //array of supported smileys
if(in_array($matches[1][0],$emoticons)){
//smily exists
$string = preg_replace('/\[:(.*?):\]/i', "<i class='icon-smiley-$1'></i>", $string, $convert_smiley);
}
else{
//smily doesn't exist
}
Well, the first issue is you are setting $convert_smiley to the true/false value of the preg_match_all() instead of parsing the results. Here is how I reworked your code:
// Test strings.
$string = ' [:happy:] [:frown:] [:smile:] [:foobar:]';
// Set a list of valid smileys.
$valid_smileys = array('smile', 'sad', 'happy');
// Do a `preg_match_all` against the smiley’s
preg_match_all('/\[:(.*?):\]/i', $string, $matches);
// Check if there are matches.
if (count($matches) > 0) {
// Loop through the results
foreach ($matches[1] as $smiley_value) {
// Validate them against the valid smiley list.
$pattern = $replacement = '';
if (in_array($smiley_value, $valid_smileys)) {
$pattern = sprintf('/\[:%s:\]/i', $smiley_value);
$replacement = sprintf("<i class='icon-smiley-%s'></i>", $smiley_value);
$string = preg_replace($pattern, $replacement, $string);
}
}
}
echo 'Test Output:';
echo htmlentities($string);
Just note that I chose to use sprintf() for the formatting of content & set $pattern and $replacement as variables. I also chose to use htmlentities() so the HTML DOM elements can easily be read for debugging.
Related
I have a doubt, it may be something simple but I have no knowledge to solve it.
I get a string in php
$ string = "[link = someUrl] Text [link]"
And I would like to turn this string into:
"<a href='someUrl'> Text <a/>"
How do I change the URL? and How Can I do the opposite?
Remember that the string belongs to a text with more strings of these gifts.
Short preg_replace solution:
$s = "[link=someUrl] Text [/link]";
$result = preg_replace('#\[[^=]+=([^]]+)\]([^[]+).*#', '<a href=\'$1\'>$2</a>', $s);
print_r($result);
The output (as web page source code):
<a href='someUrl'> Text </a>
You can use the following code
function transformText($string) {
preg_match("/\[link\=([^\]]*)\](.*?)\[\/link]/", $string, $matches);
$someUrl = $matches[1];
$text = $matches[2];
$newString = "<a href='$someUrl'>$text</a>";
return $newString;
}
$string = "[link=someUrl] Text [/link]"; // Test string
echo (transformText($string));
Live demo for the regex used : https://regex101.com/r/tzVfmH/4
Note : The above code works only if there's a single [link], [/link] pair.
If multiple occurrences are to be handled then its better to use regex search and replace, using php's preg_replace as suggested in RomanPerekhrest's answer.
I want to replace all image contained in a string, which is like:
<img src="data:image/png;base64,IMAGE DATA
with a reference to a cid.
Since the images can't get the same cid's, i need to replace them with an increment. But i don't know how to. Only thing i've found so far is following code, which replaces the string with the same:
$string = 'normal text [everythingheregone] after text ';
$pattern = '\[.*?]';
$replacement = '[test]'
echo preg_replace($pattern, $replacement, $string);
//normal text [test] after text
Do you have any ideas?
Shame on me, i should've searched a little bit more:
Here is what i've found out on replacing with increment:
$count = 0;
preg_replace_callback('/test/', 'rep_count', $content);
function rep_count($matches) {
global $count;
return 'test' . $count++;
}
Thanks to #s.d.a.p.e I've come a step close but I'm not quite there yet.
What I'm trying to do is replace all instances of a string in a block of text. I want to replace something like this:
user is ?user_id=34&first_name=Ralph so is ?user_id=1 also
With this:
user is /user/34/ so is /user/1/ also
Here is the preg_replace code I'm using:
$pattern = '#\?user_id=([0-9]+)#';
$replace = '/user/$1/';
echo preg_replace($pattern,$replace,$string);
With that pattern I end up with this:
user is /user/34/&first_name=Ralph so is /user/1/ also
Thanks again.
try this:
$string = "user is ?user_id=34&first_name=Ralph so is ?user_id=1 also";
$result = preg_replace('/\?(user)_id=(\d+)(.*?)(?! )/i', '/$1/$2/$3', $string );
echo $result ;
Output:
user is /user/34/&first_name=Ralph so is /user/1/ also
DEMO
I'd use this:
$string = 'user is ?user_id=34&first_name=Ralph so is ?user_id=1 also';
$pattern = '#\?user_id=([0-9]+)\S*#';
$replace = '/user/$1/';
echo preg_replace($pattern, $replace, $string);
Where \S stands for any character that is not a space.
Output:
user is /user/34/ so is /user/1/ also
print preg_replace(
'#\?user_id=([0-9]+)\&(first_name=(?:.*))#',
'/user/$1?$2',
'?user_id=34&first_name=Ralph'
);
result :
/user/34?first_name=Ralph if get it right..
I have to extract the email from the following string:
$string = 'other_text_here to=<my.email#domain.fr> other_text_here <my.email#domain.fr> other_text_here';
The server send me logs and there i have this kind of format, how can i get the email into a variable without "to=<" and ">"?
Update: I've updated the question, seems like that email can be found many times in the string and the regular expresion won't work well with it.
You can try with a more restrictive Regex.
$string = 'other_text_here to=<my.email#domain.fr> other_text_here';
preg_match('/to=<([A-Z0-9._%+-]+#[A-Z0-9.-]+\.[A-Z]{2,4})>/i', $string, $matches);
echo $matches[1];
Simple regular expression should be able to do it:
$string = 'other_text_here to=<my.email#domain.fr> other_text_here';
preg_match( "/\<(.*)\>/", $string, $r );
$email = $r[1];
When you echo $email, you get "my.email#domain.fr"
Try this:
<?php
$str = "The day is <tag> beautiful </tag> isn't it? ";
preg_match("'<tag>(.*?)</tag>'si", $str, $match);
$output = array_pop($match);
echo $output;
?>
output:
beautiful
Regular expression would be easy if you are certain the < and > aren't used anywhere else in the string:
if (preg_match_all('/<(.*?)>/', $string, $emails)) {
array_shift($emails); // Take the first match (the whole string) off the array
}
// $emails is now an array of emails if any exist in the string
The parentheses tell it to capture for the $matches array. The .* picks up any characters and the ? tells it to not be greedy, so the > isn't picked up with it.
I want to get all Performance ID's from this page .
<?php
$content = file_get_contents("http://www124.popmundo.com/Common/Performances.asp?action=ComingPerformances&ArtistID=1962457");
$regex = "Performances\.asp\?action=Arrangements&PerformanceID=([0-9]+)";
//$regex = "/Performances\.asp\?action=Arrangements&PerformanceID=([0-9]+)/";
//$regex = "/Performances\.asp\?action=Arrangements&PerformanceID=([0-9]+)/s";
//all pattern variations tested, not working
if(preg_match_all($regex, $content, $m))
print_r($m);
else
echo "FALSE";
// this is returning FALSE
Use & instead of & in your regex.
Try this:
$regex = "/Performances\.asp\?action=Arrangements&PerformanceID=([0-9]+)/";
It looks like an escape problem. Not knowing php, I would guess one of these
might fix it:
$regex = 'Performances\.asp\?action=Arrangements&PerformanceID=([0-9]+)';
or
$regex = "Performances\\.asp\\?action=Arrangements&PerformanceID=([0-9]+)";
or
$regex = '/Performances\.asp\?action=Arrangements&PerformanceID=([0-9]+)/';