Group SQL outputs with same value - php

Question

I'm trying to create a script that shows the openings of a store.
I want this openings to be listed below each others. If for example, Monday, Tuesday and Wednesday has the exact same opening time, I want it to be grouped like this:
Mon-Wed: 12:00-15:00
Thursday: 13:00-15:00
Friday: 10:00-18:00
Saturday: 12:00-18:00
Sunday: 14:00-18:00
It works fine when outputting weekday by weekday, but I cannot figure out, how to 'group' the weekdays, with the same opening time.
I have tried to use if($time == $time) but that didn't worked. I do not have any other ideas how to do it.
I don't want to get the weekday names from the table itself. That's why I've created the $weekdays array so that I can change the weekday name, directly in the code.
I also need to put the weekday names and the opening times in separate spans.
This is my SQL Table:
ID | mon | tue | wed | thu | fri | sat | sun
1 12:00-15:00 12:00-15:00 12:00-15:00 13:00-15:00 10:00-18:00 12:00-18:00 14:00-18:00
This is my current PHP code:
$get_openings = mysql_query("SELECT * FROM openings WHERE NC_Id='1'");
while($days = mysql_fetch_array($get_openings)) {
// Loads time only from database
$mon = $days['mon'];
$tue = $days['tue'];
$wed = $days['wed'];
$thu = $days['thu'];
$fri = $days['fri'];
$sat = $days['sat'];
$sun = $days['sun'];
$weekdays = array('monday','tuesday','wednesday','thuesday','friday','saturday','sunday');
$times = array($mon,$tue,$wed,$thu,$fri,$sat,$sun);
$i = 0;
foreach($times as $time) {
while ($i <= 6) {
if($time == "") {
echo $weekdays[$i++].": "."Closed<br>";
}
else {
echo $weekdays[$i++].": ".$time."<br>";
}
}
}
}
Can someone help me please?
Thanks - Jesper

Answer 1

1) define $weekdays outside the while-loop, since it doesn't change
2) define $mon, $tue ... and then collect them again in $times doesn't make sense. You can directly use the named array from the fetch statement.
$weekdays = array('mon','tue','wed','thu','fri','sat','sun');
$get_openings = mysql_query("SELECT * FROM openings WHERE NC_Id='1'");
while($days = mysql_fetch_array($get_openings)) {
$result = array();
foreach($weekdays as $day){
$time = $days[$day]==''?'closed':$days[$day];
if(count($result)>0 and $result[0][1]==$time){
$result[0][0] = substr($result[0][0],0,3) . '-' . $day;
} else {
array_unshift($result,array($day,$time));
}
}
$result = array_reverse($result);
/* add code to display $result here */
}
In each loop $result is an array of array containing the day names and the openning times. For Example: array(array('mon-wed','12:00-15:00'),array('thu',...),...)
*/

Answer 2

Try it like this:
$previous_time = null;
$previous_day = null;
$consequetive = 0;
while($days = mysql_fetch_assoc($get_openings)) { // loop through your rows
$days[''] = null;
foreach ($days as $day => $time) { // loop through your fields
if ($day != "id") { // skip the `id` field
if ($previous_time !== $time) {
echo $consequetive > 0 ? $previous_day : "";
echo $previous_day ? ": " : "";
echo $previous_time === "" ? "Closed" : $previous_time;
echo $previous_day && $day ? "<br>" : "";
echo $day;
$consequetive = 0;
}
else {
echo ++$consequetive == 1 ? " - " : "";
}
$previous_time = $time;
$previous_day = $day;
}
}
}