i have the fowling code in my project:
$title = "In this title we have the word GUN"
$needed_words = array('War', 'Gun', 'Shooting');
foreach($needed_words as $needed_word) {
if (preg_match("/\b$needed_word\b/", $title)) {
$the_word = "ECHO THE WORD THATS FIND INSIDE TITLE";
}
}
I want to check if $title contains one of 15 predefined words,
for example lets say:
if $title contains words "War, Gun, Shooting" then i want to assign the word that is find to $the_word
Thanks in advance for your time!
try this
$makearray=array('war','gun','shooting');
$title='gun';
if(in_array($title,$makearray))
{
$if_included='the value you want to give';
echo $if_included;
}
Note:- This will work if your $title contains exactly the same string that is present as one of the value in the array.Otherwise not.
The best approach would be to use regular expressions, as it is most flexible, and allows you to have more controll over the words which you like to match. To be sure that the string contains words like gun (but also guns), shoot (but also shooting) you can do the following:
$words = array(
'war',
'gun',
'shoot'
);
$pattern = '/(' . implode(')|(', $words) . ')/i';
$if_included = (bool) preg_match($pattern, "Some text - here");
var_dump($if_included);
This matches more then it should. For example it will return true also if the string contains a warning (becouse it starts with war) you can improve this by introducing additinal constraints to certain patterns. For example:
$words = array(
'war(?![a-z])', // now it will match "war", but not "warning"
'gun',
'shoot'
);
Related
I have the following title formation on my website:
It's no use going back to yesterday, because at that time I was... Lewis Carroll
Always is: The phrase… (author).
I want to delete everything after the ellipsis (…), leaving only the sentence as the title. I thought of creating a function in php that would take the parts of the titles, throw them in an array and then I would work each part, identifying the only pattern I have in the title, which is the ellipsis… and then delete everything. But when I do that, in the X space of my array, it returns the following:
was...
In position 8 of the array comes the word and the ellipsis and I don't know how to find a pattern to delete the author of the title, my pattern was the ellipsis. Any idea?
<?php
$a = get_the_title(155571);
$search = '... ';
if(preg_match("/{$search}/i", $a)) {
echo 'true';
}
?>
I tried with the code above and found the ellipsis, but I needed to bring it into an array to delete the part I need. I tried something like this:
<?php
define('WP_USE_THEMES', false);
require('./wp-blog-header.php');
global $wpdb;
$title_array = explode(' ', get_the_title(155571));
$search = '... ';
if (array_key_exists("/{$search}/i",$title_array)) {
echo "true";
}
?>
I started doing it this way, but it doesn't work, any ideas?
Thanks,
If you use regex you need to escape the string as preg_quote() would do, because a dot belongs to the pattern.
But in your simple case, I would not use a regex and just search for the three dots from the end of the string.
Note: When the elipsis come from the browser, there's no way to detect in PHP.
$title = 'The phrase... (author).';
echo getPlainTitle($title);
function getPlainTitle(string $title) {
$rpos = strrpos($title, '...');
return ($rpos === false) ? $title : substr($title, 0, $rpos);
}
will output
The phrase
First of all, since you're working with regular expressions, you need to remember that . has a special meaning there: it means "any character". So /... / just means "any three characters followed by a space", which isn't what you want. To match a literal . you need to escape it as \.
Secondly, rather than searching or splitting, you could achieve what you want by replacing part of the string. For instance, you could find everything after the ellipsis, and replace it with an empty string. To do that you want a pattern of "dot dot dot followed by anything", where "anything" is spelled .*, so \.\.\..*
$title = preg_replace('/\.\.\..*/', '', $title);
Here is my code:
function TranslatedTitle($Title) {
ConnectWithMySQLDatabase();
$v = mysql_query("SELECT * FROM `ProductTranslations`");
while($vrowis = mysql_fetch_array($v)){
$English[] = $vrowis['English'];
$Bulgarian[] = $vrowis['Bulgarian'];
}
$TranslatedTitle = str_replace($English, $Bulgarian, $Title);
return $TranslatedTitle;
}
I am using this code to fetch data from MySQL table and then search for certain phrase in English and then replace it with the phrase setted to replace the English one with the Bulgarian one.
Example:
I have very big blue eyes.
Will be translated to:
I have very големи сини eyes . It takes the phrase big blue and replace it with големи сини at the position where it can be found.
In other words how can i make the replaced part to be moved in the beginning of the string giving final result by my example as големи сини I have very eyes.
The sentence in the example have no meaning but i have created it as an example.
I would try looping through the $English array and when finding the matching word move it to the beginning, then translating... something like:
foreach($English as $word){
$pos = strpos($Title, $word);
if ($pos !== false) {
//english word found
$Title = $word . str_replace($English, '', $Title);
break;
}
}
Then
$TranslatedTitle = str_replace($English, $Bulgarian, $Title);
First off, you will want to use PDO to interact with your database. mysql_ extensions are now deprecated, bad practice and vulnerable to sql injections. You can manipulate your strings using strpos see php.net/manual/en/function.strpos.php. You will want to first go like this: find the text to replace, translate, remove the word from where ever it is by using $strip = str_replace("",$word) and finally append your result to a new variable ike this $variable = $translate.$strip . Hope that helps
This function searches for words (from the $words array) inside a text and highlights them.
function highlightWords(Array $words, $text){ // Loop through array of words
foreach($words as $word){ // Highlight word inside original text
$text = str_replace($word, '<span class="highlighted">' . $word . '</span>', $text);
}
return $text; // Return modified text
}
Here is the problem:
Lets say the $words = array("car", "drive");
Is there a way for the function to highlight not only the word car, but also words which contain the letters "car" like: cars, carmania, etc.
Thank you!
What you want is a regular expression, preg_replace or peg_replace_callback more in particular (callback in your case would be recommended)
<?php
$searchString = "The car is driving in the carpark, he's not holding to the right lane.\n";
// define your word list
$toHighlight = array("car","lane");
Because you need a regular expression to search your words and you might want or need variation or changes over time, it's bad practice to hard code it into your search words. Hence it's best to walk over the array with array_map and transform the searchword into the proper regular expression (here just enclosing it with / and adding the "accept everything until punctuation" expression)
$searchFor = array_map('addRegEx',$toHighlight);
// add the regEx to each word, this way you can adapt it without having to correct it everywhere
function addRegEx($word){
return "/" . $word . '[^ ,\,,.,?,\.]*/';
}
Next you wish to replace the word you found with your highlighted version, which means you need a dynamic change: use preg_replace_callback instead of regular preg_replace so that it calls a function for every match it find and uses it to generate the proper result. Here we enclose the found word in its span tags
function highlight($word){
return "<span class='highlight'>$word[0]</span>";
}
$result = preg_replace_callback($searchFor,'highlight',$searchString);
print $result;
yields
The <span class='highlight'>car</span> is driving in the <span class='highlight'>carpark</span>, he's not holding to the right <span class='highlight'>lane</span>.
So just paste these code fragments after the other to get the working code, obviously. ;)
edit: the complete code below was altered a bit = placed in routines for easy use by original requester. + case insensitivity
complete code:
<?php
$searchString = "The car is driving in the carpark, he's not holding to the right lane.\n";
$toHighlight = array("car","lane");
$result = customHighlights($searchString,$toHighlight);
print $result;
// add the regEx to each word, this way you can adapt it without having to correct it everywhere
function addRegEx($word){
return "/" . $word . '[^ ,\,,.,?,\.]*/i';
}
function highlight($word){
return "<span class='highlight'>$word[0]</span>";
}
function customHighlights($searchString,$toHighlight){
// define your word list
$searchFor = array_map('addRegEx',$toHighlight);
$result = preg_replace_callback($searchFor,'highlight',$searchString);
return $result;
}
I haven't tested it, but I think this should do it:-
$text = preg_replace('/\W((^\W)?$word(^\W)?)\W/', '<span class="highlighted">' . $1 . '</span>', $text);
This looks for the string inside a complete bounded word and then puts the span around the whole lot using preg_replace and regular expressions.
function replace($format, $string, array $words)
{
foreach ($words as $word) {
$string = \preg_replace(
sprintf('#\b(?<string>[^\s]*%s[^\s]*)\b#i', \preg_quote($word, '#')),
\sprintf($format, '$1'), $string);
}
return $string;
}
// courtesy of http://slipsum.com/#.T8PmfdVuBcE
$string = "Now that we know who you are, I know who I am. I'm not a mistake! It
all makes sense! In a comic, you know how you can tell who the arch-villain's
going to be? He's the exact opposite of the hero. And most times they're friends,
like you and me! I should've known way back when... You know why, David? Because
of the kids. They called me Mr Glass.";
echo \replace('<span class="red">%s</span>', $string, [
'mistake',
'villain',
'when',
'Mr Glass',
]);
Sine it's using an sprintf format for the surrounding string, you can change your replacement accordingly.
Excuse the 5.4 syntax
This is a problem that I have figured out how to solve, but I want to solve it in a simpler way... I'm trying to improve as a programmer.
Have done my research and have failed to find an elegant solution to the following problem:
I have a hypothetical array of keywords to search for:
$keyword_array = array('he','heather');
and a hypothetical string:
$text = "What did he say to heather?";
And, finally, a hypothetical function:
function bold_keywords($text, $keyword_array)
{
$pattern = array();
$replace = array();
foreach($keyword_array as $keyword)
{
$pattern[] = "/($keyword)/is";
$replace[] = "<b>$1</b>";
}
$text = preg_replace($pattern, $replace, $text);
return $text;
}
The function (not too surprisingly) is returning something like this:
"What did <b>he</b> say to <b>he</b>ather?"
Because it is not recognizing "heather" when there is a bold tag in the middle of it.
What I want the final solution to do is, as simply as possible, return one of the two following strings:
"What did <b>he</b> say to <b>heather</b>?"
"What did <b>he</b> say to <b><b>he</b>ather</b>?"
Some final conditions:
--I would like the final solution to deal with a very large number of possible keywords
--I would like it to deal with the following two situations (lines represent overlapping strings):
One string engulfs the other, like the following two examples:
-- he, heather
-- sanding, and
Or one string does not engulf the other:
-- entrain, training
Possible way to solve:
-A regex that ignores tags in keywords
-Long way (that I am trying to avoid):
*Search string for all occurrences of each keyword, store an array of positions (start and end) of keywords to be bolded
*Process this array recursively to combine overlapping keywords, so there is no redundancy
*Add the bold tags (starting from the end of the string, to avoid the positions of information shifting from the additional characters)
Many thanks in advance!
Example
$keyword_array = array('he','heather');
$text = "What did he say to heather?";
$pattern = array();
$replace = array();
sort($keyword_array, SORT_NUMERIC);
foreach($keyword_array as $keyword)
{
$pattern[] = "/ ($keyword)/is";
$replace[] = " <b>$1</b>";
}
$text = preg_replace($pattern, $replace, $text);
echo $text; // What did <b>he</b> say to <b>heather</b>?
need to change your regex pattern to recognize that each "term" you are searching for is followed by whitespace or punctuation, so that it does not apply the pattern match to items followed by an alpha-numeric.
Simplistic and lazy-ish Approach off The Top of My head:
Sort your initial Array by Item length, descending! No more "Not recognized because there's already a Tag in The Middle" issues!
Edit: The nested tags issue is then easily fixed by extending your regex in a Way that >foo and foo< isn't being matched anymore.
I am relatively new to php, and hope someone can help me with a replace regex, or maybe a match replace I am not exactly sure.
I want to automatically bold the (second occurance of a match) and then make the 4th appearance of a match italic and then the 7th appearance of a match underlined.
This is basically for SEO purposes in content.
I have done some replacements with: and were thinking this should do the trick?
preg_replace( pattern, replacement, subject [, limit ])
I already know the word I want to use in
'pattern' is also a word that is already defined like [word].
`replacement` 'This is a variable I am getting from a mysql db.
'subject' - The subject is text from a db.
Lets say I have this content: This explains more or less what I want to do.
This is an example of the text that I want to replace. In this text I want to make the second occurance of the word example < bold. Then I want to skip the next time example occurs in the text, and make the 4th time the word example appears in italic. Then I want to skip the 5th time the word example appears in the text, as well as the 6th time and lastly wants to make the 7th time example appears in the text underline it. In this example I have used a hyperlink as the underline example as I do not see an underline function in the text editor. The word example may appear more times in the text, but my only requerement is to underline once, make bold once and make italic once. I may later descide to do some quotes on the word "example" as well but it is not yet priority.
It is also important for the code not to through an error if there is not atleast 7 occurances of the word.
How would I do this, any ideas would be appreciated.
You could use preg_split to split the text at the matches, apply the modifications, and then put everything back together:
$parts = preg_split('/(example)/', $str, 7, PREG_SPLIT_DELIM_CAPTURE);
if (isset($parts[3])) $parts[3] = '<b>'.$parts[3].'</b>';
if (isset($parts[7])) $parts[7] = '<i>'.$parts[7].'</i>';
if (isset($parts[13])) $parts[13] = '<u>'.$parts[13].'</u>';
$str = implode('', $parts);
The index formula for the i-th match is index = i · 2 - 1.
The regular expression itself cannot count, and the preg_ functions provide little help. You need a workaround. If you were to actually search for just a word, you might want to use string functions. Otherwise try:
// just counting
if (7 >= preg_match_all($pattern, $subject, $matches)) {
$cb_num = 0;
$subject = preg_replace_callback($pattern, "cb_ibu", $subject);
}
function cb_ibu($match) {
global $cb_num;
$match = $match[0];
switch (++$cb_num) {
case 2: return "<b>$match</b>";
case 4: return "<i>$match</i>";
case 7: return "<u>$match</u>";
default: return $match;
}
}
The trick is to have a callback which does the accounting. And there it's quite easy to add any rules.
That's an interesting question. My implementation would be:
function replace_exact($word, $tag, $string, $limit) {
$tag1 = '<'.$tag.'>';
$tag2 = '</'.$tag.'>';
$string = str_replace($word, $tag1.$word.$tag2, $string, 1);
if ($limit==1) return $string;
return str_replace($tag1.$word.$tag2,$word,$string,$limit-1);
}
Use it like this:
echo replace_exact('Example', 'b', $source_text, 2);
echo replace_exact('Example', 'i', $source_text, 4);
I don't know about how fast this will work, but it will be faster than preg_replace.