create dynamic reports using core php and mysql - php

Question

Currently we are doing a project to manage projects and our client need a dynamic reports which he can get Time Sheet Project wise.
Let me explain the situation.
3 database tables.
Project table, user table and task table.
This is the sample reports format with a sample data, but structure is the same.
Multiple users can work on a single project and user can work on multiple projects at the same time.
This is what i have tried to up to now.
<?php
/////get projects which are not finished/////
$sql_project = "SELECT * FROM project where P_Status!='finished'";
$result_project = mysql_query($sql_project) or die("Error in query: $sql_project.".mysql_error());
////////get users from the users table
$sql_getUsers="select * from tbl_user where status='Active' order by U_Name";
$result_getUsers=mysql_query($sql_getUsers);
?>
<tr>
<td>Project</td>
<td>Client</td>
<td>Estimated Cost</td>
<td >Total spent to date </td>
<?php
while($row_getUsers=mysql_fetch_array($result_getUsers))
{
?>
<td ><?php echo $row_getUsers['U_Name']; ?></td>
<?php
}
?>
</tr>
<?php
while($row_project=mysql_fetch_array($result_project))
{
$individualProject=trim($row_project['P_Title']);
$sql_tasks = "Select SUM(Time)as totalTime from tbl_txn where project like '%$individualProject%' and Date<='$endDate'";
$result_sql = mysql_query($sql_tasks) or die("Error in query: $sql_file_no.".mysql_error());
?>
<?php
while($row_sql_tasks=mysql_fetch_array($result_sql))
{
?>
<tr>
<td><?php echo $row_project['P_Title']; ?></td>
<td ><?php echo $row_project['P_Client']; ?></td>
<td ><?php echo $row_project['estimatedCost']; ?></td>
<td ><?php echo round($row_sql_tasks['totalTime']); ?></td>
<td><?php echo round($row_getIndiUserTime['Time']); ?></td>
<?php
}
}
?>
I have managed to display the users, but i have no idea how to display users have work on each project?.
on project A, how much time User 1 has spent and user 2 like wise.
hope i have clearly mentioned about the problem.
can anyone help me on this please?
Thanks in advance

Answer 1

The idea to do this is to join a table in mysql.
Here is a resource you can learn how to use mysql join table and show the data accordingly. Hope this will help you.