PHP get value from an array - php

Question

I have this PHP code:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $query_string);
curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0);
$jsondata = curl_exec($ch);
if (curl_error($ch))
die("Connection Error: ".curl_errno($ch).' - '.curl_error($ch));
curl_close($ch);
$arr = json_decode($jsondata);
echo "\nResponse: ".htmlentities($jsondata)."\n\nArray: ".print_r($arr,true);
Which outputs:
Response: {"result":"success","clientid":83} Array:
stdClass Object ( [result] => success [clientid] => 83 )
I want to grab the value 83 stored in the variable called $clientid.
But I can't figure out how to do it.

Answer 1

You are confusing a PHP object with a PHP array.
You should be doing this: echo $arr->clientid;
Example 1, access a value of an object like this:
<?php
$jsondata = '{"firstName":"John", "lastName":"Doe"}';
$arr = json_decode($jsondata);
echo gettype($arr);
echo $arr->firstName;
?>
This prints:
object
John
Example 2, access a value of an array like this:
<?php
$yarr = array(5,6,7);
echo $yarr[0];
?>
This prints:
5

Answer 2

Your main mistake is assuming json_decode returns an array.
$arr = json_decode($jsondata);
Will set up $arr as an object. If you wanted to access it as an array, you can do this:
$arr = json_decode($jsondata, TRUE);
The extra parameter on the end tells json_decode to return an array instead of an object. Then you could do:
echo $arr["clientid"];

Answer 3

try echo $arr["clientid"] to get data from array