I have a text file that contains multiple occurrences of a substring - pin="*****" where * equals a number.
The pin number inside the enclose quotes can be N length.
What I would like to do is extract the line pin="*****" or even better just the number inside it and add it to an array for later processing.
An example of what the text file looks like is like so
[123456]
mystring="srthjkgnyjh"
pin="9898
anotherstring="jghksdfghjkdfg6788678345hjkfsd"
[654321]
mystring="hksfkhjsjl"
pin="4343434"
anotherstring="kdgig89794578945789jkhflsf7865"
etc..
Ideas are much appreciated
Thank you
You can use this:
preg_match_all('~(?<=\bpin=")[0-9]+(?=")~', $str, $matches);
$result = $matches[0];
(?<=..) and (?=..) are a lookbehind and a lookahead. You can find more informations about it here.
Related
I have a big string like this:
[/az_column_text][/vc_column_inner][vc_column_inner width="3/4"]
[az_latest_posts post_layout="listed-layout" post_columns_count="2clm" post_categories="assemblea-soci-2015"]
[/vc_column_inner][/vc_row_inner][/vc_column]
What I need to extract:
assemblea-soci-2015
Of course this value can change, and also the big string can change too. I need a regex or something else to extract this value (it will be always from post_categories="my-value-to-extract") from this big string.
I think to take post_categories=" as the beginning of a possible substring and the next char " as the end of my portion, but no idea how to do this.
Is there an elegant way to do this also for future values with, of course, different length?
You can use this regex in PHP:
post_categories="\K[^"]+
RegEx Demo
You can use this regex:
(?<=post_categories=")[^"]+(?=")
?<= (lookbehind) looks for post_categories=" before the desired match, and (?=) (lookahead) looks for " after the desired match.
[^"] gets the match (which is assumed not to contain any ")
Demo
Example PHP code:
$text='[/az_column_text][/vc_column_inner][vc_column_inner width="3/4"]
[az_latest_posts post_layout="listed-layout" post_columns_count="2clm" post_categories="assemblea-soci-2015"]
[/vc_column_inner][/vc_row_inner][/vc_column]';
preg_match ("/(?<=post_categories=\")[^\"]+(?=\")/", $text,$matches);
echo $matches[0];
Output:
assemblea-soci-2015
This should extract what you want.
preg_match ("/post_categories=\"(.*)\"\[\]/", $text_you_want_to_use)
I'm a regex-noobie, so sorry for this "simple" question:
I've got an URL like following:
http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx
what I'm going to archieve is getting the number-sequence (aka Job-ID) right before the ".aspx" with preg_replace.
I've already figured out that the regex for finding it could be
(?!.*-).*(?=\.)
Now preg_replace needs the opposite of that regular expression. How can I archieve that? Also worth mentioning:
The URL can have multiple numbers in it. I only need the sequence right before ".aspx". Also, there could be some php attributes behind the ".aspx" like "&mobile=true"
Thank you for your answers!
You can use:
$re = '/[^-.]+(?=\.aspx)/i';
preg_match($re, $input, $matches);
//=> 146370543
This will match text not a hyphen and not a dot and that is followed by .aspx using a lookahead (?=\.aspx).
RegEx Demo
You can just use preg_match (you don't need preg_replace, as you don't want to change the original string) and capture the number before the .aspx, which is always at the end, so the simplest way, I could think of is:
<?php
$string = "http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-146370543.aspx";
$regex = '/([0-9]+)\.aspx$/';
preg_match($regex, $string, $results);
print $results[1];
?>
A short explanation:
$result contains an array of results; as the whole string, that is searched for is the complete regex, the first element contains this match, so it would be 146370543.aspx in this example. The second element contains the group captured by using the parentheeses around [0-9]+.
You can get the opposite by using this regex:
(\D*)\d+(.*)
Working demo
MATCH 1
1. [0-100] `http://stellenanzeige.monster.de/COST-ENGINEER-AUTOMOTIVE-m-w-Job-Mainz-Rheinland-Pfalz-Deutschland-`
2. [109-114] `.aspx`
Even if you just want the number for that url you can use this regex:
(\d+)
really struggling with this...hopefully someone can put me on the right path to a solution.
My input string is structured like this:
66-2141-A-AC107-7
I'm interested in extracting the string 'AC107' using a single regular expression. I know how to do this with other PHP string functions, but I have to do this with a regular expression.
What I need is to extract all data between the third and fourth hyphens. The structure of each section is not fixed (i.e, 66 may be 8798709 and 2141 may be 38). The presence of the number of hyphens is guaranteed (i.e., there will always be a total of four (4) hyphens).
Any help/guidance is greatly appreciated!
This will do what you need:
(?:[^-]*-){3}([^-]+)
Debuggex Demo
Explanation:
(?:[^-]*-) Look for zero or more non-hyphen characters followed by a hyphen
{3} Look for three of the blocks just described
([^-]+) Capture all the consecutive non-hyphen characters from that point forward (will automatically cut off before the next hyphen)
You can use it in PHP like this:
$str = '66-2141-A-AC107-7';
preg_match('/^(?:[^-]*-){3}([^-]+)/', $str, $matches);
echo $matches[1]; // prints AC107
This should look for anything followed by a hyphen 3 times and then in group 2 (the second set of parenthesis) it will have your value, followed by another hyphen and anything else.
/^(.*-){3}(.*)-(.*)/
You can access it by using $2. In php, it would be like this:
$string = '66-2141-A-AC107-7';
preg_match('/^(.*-){3}(.*)-(.*)/', $string, $matches);
$special_id = $matches[2];
print $special_id;
I have some php string like below
abc-1987-mp3-songs
xyz-1999-india-mp3-songs
dec-2001-mp3-songs
ryu-2012-freemp3-songs
Now I want these string splited at last found numeric values like below
abc-1987
xyz-1999
dec-2001
ryu-2012
Please help me that which regex can be used to do this. thanks.
Ok, I had a look (do take some time to learn regex - but meanwhile):
$split = (preg_split('/(^.*?[0-9]+)\-?[^0-9]+/', 'foo-xyz-1999-india-mp3-songs', -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY));
echo $split[0];//<--- foo-xyz-1999, just like you wanted
Dumps an array with foo-xyz-1999 as first value, which is what you need. If you want to know what every part of the regex does read it here
The only difference is that, though the whole string becomes its own delimiter, there are two delimiters (the first part, always ending on a series of numbers and the rest of the string, that doesn't contain any more digits)
Use explode insted of regular expression
for example:-
$str="abc-1987-mp3-songs";
$f=explode("-",$str);
echo $final_result=$f[0]."-".$f[1];
or if you want to use reg exp.then
<?php
$str="abc-1987-mp3-songs";
echo $f=preg_replace('/[^0-9]/','', $str);
?>
Above code give you all the numeric digits of your string.
This would match last occurrence of numeric value from given string:
([\w\d-]*-[\d]+)
This is the link: Regex
Let's say I have the this text (not to be treated as PHP code):
$this->validation->set('username','username','trim');
$this->validation->set('password','password','trim');
$this->validation->set('password2','password2','trim');
$this->validation->set('name','name','trim');
$this->validation->set('surname','surname','trim');
I want to get the list of first words after set( which is in quotation marks in every line, so the output of previous input must be like this:
username
password
password2
name
surname
I think, it's possible with regular expressions. My question is how can I get the list of the words which is in first quotation marks with PHP?
Lets say the variable $text holds the data from your question.
Let's analyse the regular expression /set\('(.*?)'/:
/ is the delimiter.
set\(' and ' are the strings set(' and ', respectively.
.*? is the least amount of (arbitrary) characters between the two aforementioned strings.1
As a result, this regular expression matches:
$this->validation->set('username','username','trim');
To store all the strings you need in the array $matches[1], we can use the function preg_match_all.
It suffices to call preg_match_all("/set\('(.*?)'/", $text, $matches).
1 See also: Regex Tutorial - Repetition with Star and Plus - Laziness Instead of Greediness
Example code:
$text = <<<EOF
\$this->validation->set('username','username','trim');
\$this->validation->set('password','password','trim');
\$this->validation->set('password2','password2','trim');
\$this->validation->set('name','name','trim');
\$this->validation->set('surname','surname','trim');
EOF;
preg_match_all("/set\('(.*?)'/", $text, $matches);
print_r($matches[1]);
$arr = explode("'","this->validation->set('surname','surname','trim')");
print_r($arr);
not sure why you would want to do something like that, but the above should work