i having two check boxes when i am selecting both check boxes i want to show the value related to both from database ,but now i able to print only one id of check boxes i want to show both data can anyone help hoe to show both a value ,Below is my code:
html
<input type="submit" name="Update" src="/image/exporttt.png" style="margin:0px;cursor:pointer">
<tbody>
<?php
$clientid=$_GET['clientid'];
if($clientid!=""){
$sql = mysql_query("SELECT * FROM clientnetworkpricehistory");
while($rows=mysql_fetch_array($sql))
{
if($alt == 1)
{
echo '<tr class="alt">';
$alt = 0;
}
else
{
echo '<tr>';
$alt = 1;
}
echo '
<td id="CPH_GridView1_clientid" style="width:140px" class=" clientid '.$rows["net_id"].'">'.$rows["clientid"].'</td>
<td id="CPH_GridView1_country" style="width:160px" class=" country '.$rows['net_id'].'">'.$rows["country"].'</td>
<td id="CPH_GridView1_networkname" style="width:156px" class="networkname '.$rows["net_id"].'">'.$rows["networkname"].'</td>
<td id="CPH_GridView1_mccmnc" style="width:250px" class=" mcc'.$rows["net_id"].'">'.$rows["mcc"].'</td>
<td id="CPH_GridView1_mccmnc" style="width:250px" class=" mnc '.$rows["net_id"].'">'.$rows["mnc"].'</td>
<td id="CPH_GridView1_oldprice" style="width:320px" class=" oldprice '.$rows["net_id"].'">'.$rows["pricefrom"].'</td>
<td id="CPH_GridView1_newprice" style="width:129px" class=" newprice '.$rows["net_id"].'">'.$rows["priceto"].'</td>
<td id="CPH_GridView1_oldroute" style="width:143px" class="oldsupplierroute '.$rows["net_id"].'">'.$rows["routefrom"].'</td>
<td id="CPH_GridView1_newroute" style="width:143px" class=" newsupplierroute '.$rows["net_id"].'">'.$rows["routeto"].'</td>
<td id="CPH_GridView1_comments" style="width:143px" class=" comments '.$rows["net_id"].'">'.$rows["status"].'</td>
<td id="CPH_GridView1_from" style="width:143px" class=" fromdate '.$rows["net_id"].'">'.date('d.m.Y H:i', $rows["datetime"]).'</td>
<td style="width:65px" class=" '.$rows["net_id"].'"><input type="checkbox" name="chk1" value=" '.$rows["net_id"].'"/></td>
</tr>';
}
}
?>
</tbody>
jssearch.php
<?php
//connecting to db
$variable=$_POST['chk1'];
foreach ($variable as $variablename)
{
$sql_select="SELECT * from clientnetworkpricehistory where net_id=$variablename";
$queryRes = mysql_query($sql_select);
print"$sql_select";
}
echo "<table border='1'>
<tr>
<th>country</th>
<th>networkname </th>
<th>mcc</th>
<th>mnc</th>
<th>datetime </th>
</tr>";
while($row = mysql_fetch_array($queryRes))
{
echo "<tr>";
echo "<td>" . $row['country'] . "</td>";
echo "<td>" . $row['networkname'] . "</td>";
echo "<td>" . $row['mcc'] . "</td>";
echo "<td>" . $row['mnc'] . "</td>";
echo "<td>" . $row['datetime'] . "</td>";
echo "</tr>";
}
echo "</table>";
?>
my out put was(i am checked two checkboxes and i am trying to print two check boxes id it only showing one can any one help me how to do that)
56
Warning: Invalid argument supplied for foreach()
Use name="chk1[]" in your HTML so the checkboxes will be posted as an array.
Besides that:
The mysql_* functions are deprecated, consider using mysqli_* or PDO
You are vulnarable to SQL-injection on your where net_id=$variablename"
I agree with Peter but you also might wanna fix this little typo:
'.$rows['net_id'].'">'.$rows["country"].'
That's line 2 of that large echo you have with all the <td>s. The $rows['net_id'] should be double quotes.
But you knew that...:)
Related
This question already has answers here:
Creating dynamic tables in HTML using MySQL and PHP
(2 answers)
Closed 11 months ago.
I want to show the list of an array in a table, I want to insert each ID in the ID column, each name in the "name" column, etc...
But it's showing all the content in single column, How I can fix it?
It shows like that right now:
[![enter image description here][1]][1]
PHP:
<table class="blueTable">
<thead>
<tr>
<th>ID</th>
<th>USER</th>
<th>MAIL</th>
</tr>
</thead>
<tfoot>
<tr>
<td colspan="3">
<div class="links">« <a class="active" href="#">1</a> 2 3 4 »</div>
</td>
</tr>
</tfoot>
<tbody>
<?php
$query = $db->query("SELECT * FROM users ORDER by id");
echo "<tr>";
while ($row = $query->fetch_array()) {
echo "<td>" . $row['id'] . "</td>";
echo "<tr><td>" . $row['username'] . "</td></tr>";
echo "<tr><td>" . $row['email'] . "</td></tr>";
}
?>
</tbody>
</table>
[1]: https://i.stack.imgur.com/jPTR8.png
change while() loop code like below:
$query = $db->query("SELECT * FROM users ORDER by id");
while($row = $query->fetch_array()){
echo "<tr>"; //put <tr> opening code inside, not outside
echo "<td>".$row['id']."</td>";
echo "<td>".$row['username']."</td>"; //remove <tr></tr>
echo "<td>".$row['email']."</td>"; //remove <tr></tr>
echo "</tr>"; //</tr> need to be added at last
}
Try this
<?php
$query = $db->query("SELECT * FROM users ORDER by id");
while($row = $query->fetch_array()){
?>
<tr>
<td> <?php echo $row['id'] ?></td>
<td> <?php echo $row['username'] ?> </td>
<td> <?php echo $row['email'] ?> </td>
</tr>
<?php
}
?>
Here's the thing, I need to update a selected row from a table, so I'm putting a form for each row of it (Every single row has an update button) and when I click update, it doesn't submit, actually, doesn't do anything.
Here's my code, I'll be grateful with the solution.
<div class="table-responsive">
<table class="table table-condensed">
<thead class="">
<tr>
<th>ID</th>
<th>Project</th>
<th>Type</th>
<th>Kick-Off Date</th>
<th>Deadline Date</th>
<th>Current Ninja</th>
<th>Status</th>
<th></th>
</tr>
</thead>
<tbody>
<?php
$q = $_GET['q'];
$sql="SELECT pr.project_name, pr.project_type, pr.project_start_date, pr.project_end_date, us.nombre, st.id_status, pr.id_project FROM NT_Projects as pr LEFT JOIN Project_Status as st on st.id_status = pr.id_status LEFT JOIN NT_Clients as cl on cl.id_client = pr.id_client LEFT JOIN usuarios as us on us.username = pr.username WHERE cl.id_client = $q";
$result = mysql_query($sql) or die(mysql_error());
$upt = 1;
while($row = mysql_fetch_array($result)) {
echo '
<div id="update-project">
<form method="post" action="sistema/_actions/updateProject.php" id="res-update-proj-'.$upt.'">';
$kickoff = date('m/d/Y', strtotime($row[2]));
$deadline = date('m/d/Y', strtotime($row[3]));
echo '<tr>';
echo '<td width="95px">
<input class="form-control" name="id_Proj" type="text" value="'.$row[6].'" readonly>
</td>';
echo "<td>" . $row[0] . "</td>";
echo "<td>" . $row[1] . "</td>";
echo "<td>" . $kickoff . "</td>";
echo "<td>" . $deadline . "</td>";
echo "<td>" . $row[4] . "</td>";
echo '<td width="225px">';
echo '<select class="form-control" name="proj_Status">';
$qStatus = "SELECT * FROM Project_Status;";
$exStatus = mysql_query($qStatus);
while($rStatus = mysql_fetch_array($exStatus))
{
if($row[5] == $rStatus[0])
echo '<option value="'.$rStatus[0].'" selected>'.$rStatus[1].'</option>';
else
echo '<option value="'.$rStatus[0].'">'.$rStatus[1].'</option>';
}
echo '</select>
</td>
<td class="text-center">
<button type="submit" class="btn btn-sm btn-primary btn-UProj" value="res-update-proj-'.$upt.'">Update</button>
<div id="res-update-proj-'.$upt.'" style="width: 100%; margin:0px; padding:0px;"></div>
</td>
</tr>
</form>
</div>';
$upt = $upt + 1;
}
?>
</tbody>
</table>
</div>
That code is being called from another HTML with ajax
You cannot mix table tags with divs and forms according to the web standards. If you do, browser's HTML-parser will mix your tags in unpredictable way.
The only solution I know is to utilize CSS:
<div style="display: table">
<form style="display: table-row">
<div> style="display: table-cell"></div>
</form>
</div>
I'm using this code to get all data from database and display it in a table:
class Product
{
private $conn;
private $id;
private $name;
private $description;
private $price;
private $category_id;
private $category_name;
private $created;
public function __construct($db)
{
$this->conn = $db;
}
public function readAll()
{
$stmt = $this->conn->prepare('SELECT name, description, price, CategoryID, created FROM products');
$stmt->execute();
echo "<table class=\"highlight responsive-table\">
<thead>
<tr>
<th data-field=\"empty\"> </th>
<th data-field=\"name\">Name</th>
<th data-field=\"description\">Description</th>
<th data-field=\"price\">Price</th>
<th data-field=\"category\">Category</th>
<th data-field=\"action\">Action</th>
</tr>
</thead>";
while ($result = $stmt->fetch(PDO::FETCH_ASSOC)) {
$n = $result['name'];
$d = $result['description'];
$p = $result['price'];
$ca = $result['CategoryID'];
$c = $result['created'];
echo "<tbody>
<tr>
<td style=\"width:10%;\">
<input type=\"checkbox\" id=\"checkbox\" />
<label for=\"checkbox\"></label>
</td>
<td style=\"width:15%;\">" .$n. "</td>
<td style=\"width:30%;\">" . $d. "</td>
<td style=\"width:10%;\">" ."$".$p. "</td>
<td style=\"width:15%;\">" . $ca. "</td>
<td style=\"width:20%;\">
<a class=\"waves-effect waves-light btn\"><i class=\"material-icons\">mode_edit</i></a>
<a class=\"waves-effect waves-light btn\"><i class=\"material-icons\">delete</i></a>
</td>";
}
echo "</tbody> </table>";
}
}
It's working, but in the 1st column I want to have a checkbox so I can mark records I want to delete / edit, but for now, whichever checkbox I click, only the 1st one get checked. How can I automatically increment checkbox id?
I would recommend using the id field from the products table. If it doesn't have one, I would add it.
Then in your html change the checkbox line to:
<input type=\"checkbox\" id=\"checkbox".$id."\" name=\"delete_product\" value=\"".$id".\" />
<label for=\"checkbox".$id."\"></label>
I added name and value in case you are submitting the form, you can get that data in the POST if you end up using a form.
use a variable $i, initialize it with 1 before while loop and
inside your loop,increment it
replace your checkbox code like
<input type=\"checkbox\" id=\"checkbox_$i\" />
<label for=\"checkbox_$i\"></label>
$i++;
Try using a counting variable like this:
$i = 0;
while ($result = $stmt->fetch(PDO::FETCH_ASSOC)) {
$n = $result['name'];
$d = $result['description'];
$p = $result['price'];
$ca = $result['CategoryID'];
$c = $result['created'];
echo "<tbody>
<tr>
<td style=\"width:10%;\">
<input type=\"checkbox\" id=\"checkbox".$i."\" />
<label for=\"checkbox".$i."\"></label>
</td>
<td style=\"width:15%;\">" .$n. "</td>
<td style=\"width:30%;\">" . $d. "</td>
<td style=\"width:10%;\">" ."$".$p. "</td>
<td style=\"width:15%;\">" . $ca. "</td>
<td style=\"width:20%;\">
<a class=\"waves-effect waves-light btn\"><i class=\"material-icons\">mode_edit</i></a>
<a class=\"waves-effect waves-light btn\"><i class=\"material-icons\">delete</i></a>
</td>";
$i++;
}
Add id column to your sql query. Then modify your first column in table to
<input type=\"checkbox\" id=\"checkbox\" . $result['id'] . " name=\"id[" . $result['id'] . "]\"/>
<label for=\"checkbox" . $result['id'] . "\"></label>
In Controller you will have access to selected ids using for example $_POST['id']
My goal is to have the items in $row['status'] to change to red if value is OFF and green if value is ON. Any help would be greatly appreciated.
<?php
include("connection.php");
$r = mysqli_query($dbc, "SELECT * FROM enclosure ORDER BY computer ASC");
echo "<table id='table' align='center' border='1' cellspacing='3' cellpadding='3' width='75%'>
<tr>
<td align='left'><b>Enclosure Name</b></td>
<td align='left'><b>Screen Status</b></td>
<td align='left'><b>Time Screen in status</b>
</td><td align='left'><b>Temperature of Enclosure</b></td>
</td><td align='left'><b>Incoming Voltage</b></td>
</tr>";
while($row = mysqli_fetch_array($r)){
$row['voltage'] = $row['voltage'] /1000;
echo "<tr>
<td align='left'>".$row['computer']."</td>
<td align='left'>".$row['status']."</td>
<td align='left'>".gmdate("H:i:s",$row['length'])."</td>
<td align='left'>".$row['temp']."</td>
<td align='left'>".$row['voltage']."</td>
</tr>";
}
mysqli_close($dbc);
$page = $_SERVER['PHP_SELF'];
$sec = "5";
?>
DevlishOne's answer is correct, however you should also consider setting the class of the <td> rather than the color. If you're formatting desires become more sophisticated than red/green (e.g. transitions) or if this is or become a larger chunk of code you will appreciate having the styles shifted out to a css file. It's generally considered a good idea.
ADDITION:
You asked for a simple version using classes:
echo "<td align='left' class='STATUS" . $row['status'] . "'>" . $row['status'] . "</td>";
This uses classes named STATUSON and STATUSOFF so you could use a css stylesheet with
STATUSON {
color: green;
}
STATUSOFF {
color: red;
}
Obviously, you can add more formatting to each of those classes if that's helpful.
Change:
<td align='left'>".$row['status']."</td>
To:
echo "<td align='left' style='color:" . ($row['status'] == "OFF" ? "red" : "green") . "'>" . $row['status'] . "</td>";
I have a script written to grab a row from my database based on current session user, which outputs the row correctly, however I want to insert a small image to be displayed alongside of the echo'd row, and cannot figure out the proper syntax.
if ($row['lifetime']!="")
echo "<div style ='font:12px Arial;color:#2F6054'> Lifetime Member: </div> ".$row['lifetime'];
else
echo '';
?>
basically I want the image to appear right before or after the .$row appears, either or.
You can try:
<?php
if ($row['lifetime'] !== "") {
echo "<div style ='font:12px Arial;color:#2F6054'> Lifetime Member: </div>";
echo $row['lifetime'];
echo "<img src='' alt='' style='width:100px'/>";
}
?>
Just put the HTML for the image into the string you're echoing:
echo "<div style ='font:12px Arial;color:#2F6054'><img src="fill in URL here"> Lifetime Member: </div> ".$row['lifetime'];
You can try as below example
HTML
<table>
<thead>
<tr>
<th>No.</th>
<th>Customer Name</th>
<th>Photo</th>
<th ></th>
</tr>
</thead>
<tbody>
<?php
$tst=0;
$result = mysql_query("select * from acc_cust");
while($row = mysql_fetch_array($result))
{
echo "<tr class='odd gradeX'>";
echo "<td width=5%'>" . $row['ent_no']. "</td>";
echo "<td>" . $row['cust_name']. "</td>";
echo "<td><img src='[path]" . $row['cust_img'] . "' /></td>";
}
?>
</tbody>
</table>