PHP Prepared statement insert into database - php

Question

Does anyone see anything that is wrong with this. It isn't posting to database at all. There is a basic form asking for name and address on the page. But after submitting the form it just goes to a blank page.
Here is my code. There is stuff above this that reaches out to an API to validate the address data and declares the variables. The dedup part of the code is working in case that matters.
if(empty($errorMessage))
{
// Dedupe the entry into the form
$dupesql = "SELECT * FROM formData WHERE (name = '$full_name' AND address = '$primary_number' AND city = '$city_name' AND state = '$state_abbreviation' AND zip = '$zipcode_full' )";
$duperaw = $mysqli->query($dupesql);
if($duperaw->num_rows > 0) {
$dupe .= "$full_name already exists on $primary_number \n";
}
else {
$sql = "INSERT INTO formData(name, address, city, state, zip, date) VALUES (?, ?, ?, ?, ?, ?)";
$stmt = $mysqli->prepare($sql);
$stmt->bind_param("ssssss", $full_name, $primary_number, $city_name, $state_abbreviation, $zipcode_full, $date);
$stmt->execute();
header("location: index.php?success=1");
exit();
}
}
I have also tried using a query instead of a prepared statement but this just gives the success message and doesnt post to the DB
$sql = "INSERT INTO fromData (name, address, city, state, zip, date) VALUES (".
$full_name . ", " .
$primary_number . ", " .
$city_name . ", " .
$state_abbreviation . ", " .
$zipcode_full . ", " .
$date . ")";
$mysqli->query($sql);
Any help would be great!

Answer 1

Try this SQL
$sql = "INSERT INTO fromData (name, address, city, state, zip, date) VALUES ('$full_name', '$primary_number', '$city_name', '$state_abbreviation', '$zipcode_full', '$date')";
$mysqli->query($sql);
cHao was hinting towards it