I am confused as to why this always, even when I know it should be 0, returns 1.
function check_user_data($username, $password) {
global $db;
$query = "SELECT COUNT(*) FROM users WHERE username='$username' AND password='$password'";
$results = $db->query($query);
$results = $results->fetchColumn();
echo count($results);
because you are selecting a count in your query which returns a single number and then you are counting that single number with count($results)
Why does fetchColumn() always return 1?
It doesn't.
Check your data and code.
Related
I'm trying to count the number of rows in a table and thought that this was the correct way to do that:
$result = $db->query("SELECT COUNT(*) FROM `table`;");
$count = $result->num_rows;
But counts always returns (int)1. If I use the same query in phpMyAdmin I get the right result. It sits in a table so I tried testing $count[0] as well, but that returns NULL.
What is the right way to do this?
You have to fetch that one record, it will contain the result of Count()
$result = $db->query("SELECT COUNT(*) FROM `table`");
$row = $result->fetch_row();
echo '#: ', $row[0];
Always try to do an associative fetch, that way you can easy get what you want in multiple case result
Here's an example
$result = $mysqli->query("SELECT COUNT(*) AS cityCount FROM myCity")
$row = $result->fetch_assoc();
echo $row['cityCount']." rows in table myCity.";
I find this way more readable:
$result = $mysqli->query('select count(*) as `c` from `table`');
$count = $result->fetch_object()->c;
echo "there are {$count} rows in the table";
Not that I have anything against arrays...
$result->num_rows; only returns the number of row(s) affected by a query. When you are performing a count(*) on a table it only returns one row so you can not have an other result than 1.
I am using the following php to display the number of records returned in a db search.
$sql = "SELECT COUNT(id) FROM authorsbooks WHERE author LIKE '%$searchquery%'";
$query = mysqli_query($dbc, $sql);
$row = mysqli_fetch_row($query);
$rows = $row[0];
$textline1 = "Your Search Returned (<b>$rows</b>) Records";
<?php echo $textline1; ?>
This seems to work fine.
However, I cannot get the total number of records in the actual db to display.
Can anyone explain a way of getting the total number of records in the database. Btw, I have tried using $total = mysqli_num_rows($query) but it keeps returning 1 as an answer. Thanks for any help.
For that you've to fire another SQL query. Like this,
$sql = "SELECT COUNT(id) FROM authorsbooks";
$query = mysqli_query($dbc, $sql);
$row = mysqli_fetch_row($query);
$rows = $row[0];
echo $rows; // will return total rows in database.
SELECT COUNT(*) FROM authorsbooks
It's true that $total = mysqli_num_rows($query) should return one row. When you do a SELECT COUNT(*) then the query returns 1 row telling you how many matches there were in the table.
My function should return number of rows with email like '$email'. But whey return 0 all the time, although in database i have rows with email like I insert in variable '$email'. What could be the reason?
function checkMail($email){
$email = mysql_real_escape_string($email);
$sql = "SELECT COUNT(*) FROM users WHERE email='$email'";
return mysql_query($sql);
}
You aren't returning a result, you're returning a query resource:
function checkMail($email){
$email = mysql_real_escape_string($email);
$sql = "SELECT COUNT(*) as emailCount FROM users WHERE email='$email'";
$query = mysql_query($sql) or die(mysql_error()); // show error if one happens
return mysql_fetch_assoc($query);
}
This will return an associative array containing your results (if it succeeds), and you should be able to access your count by:
$res = checkMail('your#email.com');
$count = $res['emailCount'];
Side note:
mysql functions are deprecated, you should use mysqli or PDO syntax:
https://stackoverflow.com/a/13944958/2812842
function checkMail($email){
$email = mysql_real_escape_string($email);
$sql = "SELECT COUNT(*) FROM users WHERE email='$email'";
$resource=mysql_query($sql);
$row=mysql_fetch_array($resource);
return $row[0];
}
To fetch the count use:
mysql_query($sql)
$row = mysql_fetch_assoc($result);
return($row[0]);
The funny thing is that mysql_query return 0, which indicates query fail. Check the corresponding error message with:
echo mysql_error();
I have the code below and I just want to count from the table members how many people have a 1 in the column loggedin and echo that back. I'm sure I'm missing something small, I just can't see it.
<?php
include ('functions.php');
connect();
$result = mysql_query("SELECT * FROM members WHERE loggedin = '1'");
$num_rows = mysql_num_rows($result);
$total_mem = $num_rows + (1223);
return $total_mem;
echo $total_mem;
?>
The echo will never be called because it is after the return statement.
Remove the return statement and the value should be shown.
Why not let your database do the counting for you?
$result = mysql_query("SELECT count('id') as logged_in_count FROM members WHERE loggedin = '1'");
$row = mysql_fetch_assoc($result);
$num_rows = $row['logged_in_count'];
$total_mem = $num_rows + (1223);
echo $total_mem;
return $total_mem;
You're never going to hit that echo statement, because you have a return statement right above it.
Why not use SELECT COUNT(1) FROM members WHERE loggedin = 1, and then pull the value directly from that? You'll save time because it will only need to return 1 row instead of all the rows, when all you want is the count.
I'm trying to count the number of rows in a table and thought that this was the correct way to do that:
$result = $db->query("SELECT COUNT(*) FROM `table`;");
$count = $result->num_rows;
But counts always returns (int)1. If I use the same query in phpMyAdmin I get the right result. It sits in a table so I tried testing $count[0] as well, but that returns NULL.
What is the right way to do this?
You have to fetch that one record, it will contain the result of Count()
$result = $db->query("SELECT COUNT(*) FROM `table`");
$row = $result->fetch_row();
echo '#: ', $row[0];
Always try to do an associative fetch, that way you can easy get what you want in multiple case result
Here's an example
$result = $mysqli->query("SELECT COUNT(*) AS cityCount FROM myCity")
$row = $result->fetch_assoc();
echo $row['cityCount']." rows in table myCity.";
I find this way more readable:
$result = $mysqli->query('select count(*) as `c` from `table`');
$count = $result->fetch_object()->c;
echo "there are {$count} rows in the table";
Not that I have anything against arrays...
$result->num_rows; only returns the number of row(s) affected by a query. When you are performing a count(*) on a table it only returns one row so you can not have an other result than 1.